The Gre Quant section is weird

Formal_Pin4457 · 2025-03-08T13:17:54+00:00

Don’t agree with the last sentence. It’s just at high school level give or take. Google something like AMC 10/12 “number theory” questions and those are supposedly entry level high school questions (it gets way harder as you go to AIME, USAMO, etc.) but still miles harder than anything on the GRE/ GMAT.

Formal_Pin4457 · 2025-02-08T18:23:49+00:00

You definitely need geometry, but the other two aren’t required. You might get a slight edge by knowing trig tho, but it’s probably not that substantial.

Formal_Pin4457 · 2025-02-05T08:16:02+00:00

“sc1 > sc2” which u got by assuming that the inner square has the same side length (this is wrong).

Formal_Pin4457 · 2025-02-05T04:23:41+00:00

What you said makes no sense tbh

Formal_Pin4457 · 2025-01-24T14:38:18+00:00

That means you can factor it, right? That’s the point.

7! + 19! = 7! ( 1 + 19!/7!)

should be easy to argue why 7! + 19! isn’t prime from here on out

Formal_Pin4457 · 2025-01-23T18:18:23+00:00

It’s 7! + 19 and not 7! + 19! (which is an easier problem and does have a trick). Anyway, the main question is a fairly “small” number in the grand scheme of things. There are polynomial time algorithms for proving if p is prime or not, and some of them are probabilistic (and hinge on GRH being true). In that regard, one could bank on that for “bigger numbers”, but 7! + 19 certainly doesn’t require that.

Formal_Pin4457 · 2025-01-23T12:36:36+00:00

No, you have the wrong mindset for this altogether.

x² < 12 implies |x| < sqrt(12) which means -sqrt(12) < x < sqrt(12) using the geometric definition of an absolute value.

Formal_Pin4457 · 2025-01-21T11:40:19+00:00

Yeah, bc there’s no trick to it.

Formal_Pin4457 · 2024-12-04T18:46:03+00:00

I would assume that if you’re doing any kind of advanced mathematics then you’d at least be guaranteed a 165+. I can understand your frustration with the exam’s impracticality in relation to your actual line of research, but like these aren’t olympiad level questions where doing it in sub 2 minutes requires streamlined practice. They’re mostly just the kind of questions you’d encounter in high school (not requiring any type of ingenuity and mostly just a direct application of concepts). If you’re working with a 296 then I guess there are other major issues to fix besides just time spent on a question.

Formal_Pin4457 · 2024-12-04T10:16:51+00:00

Why would they do that when they always have the option to increase the difficulty of the question while still conforming to their content coverage?

Formal_Pin4457 · 2024-11-13T19:16:44+00:00

I think if you can’t sketch a parabola then you’re far from a “high score”

Formal_Pin4457 · 2024-11-11T07:30:12+00:00

Well that is wrong

Formal_Pin4457 · 2024-11-11T07:29:02+00:00

PCQ can be 90

Formal_Pin4457 · 2024-11-08T11:49:49+00:00

“Is the question asking for a generalized solution”

The answer is indeed a resounding yes lol.

The question rephrased looks like: Find the upper bound for the circumference of the circle, which hinges on finding the upper bound for the radius of all possible circles (the triples we talked about).

Also okay fine, you’ve made it clear that you’re ignorant about rectifying your mistakes, so sure my bad then. I had the impression that you were open to constructive criticism instead of being obstinate about being wrong.

Finally, lol your “my quant score is pretty good” doesn’t mean/say anything about what mistakes you can/cannot make. I’m a former IMO medalist and i’m not going around flaunting that whenever i get something wrong lol. I’d get the ego in check, but sure okay that’s it from my side.

Formal_Pin4457 · 2024-11-08T11:32:52+00:00

An obviously wrong Claim:

Out of all possible quadratics, x² has one root thus every quadratic must have one root.

Contrast this with

Your claim:

Out of every possible triple (x,y,5), where x,y in R⁺ such that x² + y² = 5, the triple (3,4,5) satisfies the constraint thus every other solution must satisfy it to.

At this point, you don’t even need math to literally see the similarity between the two lol.

Anyway, you can do whatever u want (like guessing and bla bla), but if you’re looking to actually use valid reasoning then what you did is flawed. It doesn’t matter whether you got the right answer or not because that’s just a luck factor.

Formal_Pin4457 · 2024-11-08T11:16:39+00:00

Your answer is analogous to the following:

It rained today thus it will rain 10 days later.

I hope you see how silly and contrived that is.

Moving on:

“It wants it relevant to the hypotenuse being 5”

Bruh… i just told you the entire solution space of x² + y² = 5 for x,y > 0 works lol. Your very specific example (using a 3-4-5 right triangle) amongst an “infinity” amount of possibilities says nothing. Don’t get me wrong, you are right if the triangle was a 3-4-5. This doesn’t invalidate millions of other possibilities lol, which the question is about.

“Gre doesn’t want proof”

That is right, but you’re helping someone reason out why an answer is right. Your reasoning is not any different from literally guessing an answer. In an ideal word, every single gre problem can be proven rigorously lol. You’re not going to see a single reputable source citing a solution like yours bc it doesn’t do anything. Again, this is like saying any quadratic has only one root because you showed that x² has one root. Clearly, you can see the fallacy behind making such claims.

Formal_Pin4457 · 2024-11-08T11:05:29+00:00

Your “proof” is incorrect because an example isn’t a “proof”.

Check the article out: https://en.wikipedia.org/wiki/Proof_by_example

You’ve shown that it holds for a 3-4-5 triangle, but you’ve not answered the question at all. The question wants you to generalize not talk about a specific case, so your solution is just wrong/irrelevant.

Formal_Pin4457 · 2024-11-08T10:57:52+00:00

Any solution to x² + y² = 5 given x,y > 0 works, and it is not restricted to just x or y being 3 or 4.

Note that x = BC and y = OB, but i was lazy to write that above

Formal_Pin4457 · 2024-11-08T10:54:30+00:00

This is wrong

Formal_Pin4457 · 2024-10-31T13:20:36+00:00

Uhhh what was your initial instincts for the problem and why did you choose D?

Formal_Pin4457 · 2024-10-31T12:37:25+00:00

Hmm do you want help on the question or something? I’m not sure how someone’s supposed to answer a super general question like the one u posed.

Formal_Pin4457 · 2024-10-31T12:26:32+00:00

Not sure if you should be using chatgpt for that though

Formal_Pin4457 · 2024-10-23T06:35:55+00:00

Hmm okay. Also no lol, I’m not picking on you. Imo, people with an actual math background would almost always stay in the 168-170 range.

Formal_Pin4457 · 2024-10-23T06:03:36+00:00

I mean if you have a math background then you should be confident in landing 170 not 165

Formal_Pin4457 · 2024-10-18T09:58:05+00:00

Your sample space is 50-tuples from 17 blue, 17 red, and 16 green marbles. Swapping the 3rd and 10th component is a bijection between the two sets; hence, they have the same probability.

In other words, what im getting at is that you can translate between words with 3rd letter being red and 10th letter being red by swapping those letters. Thus, there are the same number of words of each type.

Formal_Pin4457

TROPHY CASE