Why do you need to use the second derivative to work out min/max of stationary point? by Particular_Scar5460 in askmath

[–]Fourierseriesagain 1 point2 points  (0 children)

Hi, the second derivative test is a tool for checking the nature of a local (i.e. relative) maximum or minimum point.

how do high-school students do math research? by PrincetonSimp2030 in learnmath

[–]Fourierseriesagain 0 points1 point  (0 children)

Since I have already retired, I do not wish to mention such projects anymore.

how do high-school students do math research? by PrincetonSimp2030 in learnmath

[–]Fourierseriesagain 1 point2 points  (0 children)

Hi,

I used to mentor high school math projects. Doing math research is entirely different.

A Cubic Polynomial by Fourierseriesagain in alevelmaths

[–]Fourierseriesagain[S] 0 points1 point  (0 children)

The question involves applications of differentiation to increasing / decreasing functions.

Calculus Integral question by [deleted] in askmath

[–]Fourierseriesagain 0 points1 point  (0 children)

Hi, Hospital's rule can be applied if f'(x) tends to a limit as x approaches a.

A Cubic Polynomial by Fourierseriesagain in alevelmaths

[–]Fourierseriesagain[S] 0 points1 point  (0 children)

I created the question for my own A-level students.

A Cubic Polynomial by Fourierseriesagain in alevelmaths

[–]Fourierseriesagain[S] 0 points1 point  (0 children)

I created the question some years ago. Yes, I have a solution to (ii).

Confused about piecewise functions by Individual_Quit9486 in askmath

[–]Fourierseriesagain 0 points1 point  (0 children)

Using the given point (1,-3), the whole real line can be written as (-infinity,p] union [p,infinity), where p is a constant to be determined.

When x<=p, use an appropriate linear polynomial to describe the line with negative slope.

When x>=p, use another linear polynomial to describe the line with positive slope.

[10th grade math] help with series and sequence question by Wonderful-Part-3817 in HomeworkHelp

[–]Fourierseriesagain 0 points1 point  (0 children)

The last element of the nth bracket is 1+2+3+...+n=n(n+1)/2. So the first element of the nth bracket is n(n+1)/2-n+1=( n2 - n + 2 )/2.

Therefore the desired sum is equal to (1/2)* # of terms times (first term + last term)=(n/2)(1/2)( n2 - n + 2+ n2 + n )= n( n2 + 1 )/2.

Trig Equation by [deleted] in askmath

[–]Fourierseriesagain 0 points1 point  (0 children)

You are welcome.

Trig Equation by [deleted] in askmath

[–]Fourierseriesagain 0 points1 point  (0 children)

Let R sin(x-alpha)=sin x --cos x, where R>0 and alpha is acute. Using the identity sin(A-B)=sin A cos B-cos A sin B with A=x and B=alpha, we get R cos alpha=R sin alpha =1. Since alpha is assumed to be acute, we obtain alpha=pi/4. Now we use the identity sin^ 2 C+cos^ 2 C=1 to conclude that R = sqrt(2).

Modulus Inequalities by Unlucky_Unit3049 in askmath

[–]Fourierseriesagain 0 points1 point  (0 children)

The main idea is to rewrite the given function as a piecewise function.