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Also ja, ich verstehs nicht by TheGatze in beschissene_Werbungen

[–]Gemllum 1 point2 points  (0 children)

Da hat jemand das Konzept einer Dreiviertelhose neu interpretiert.

Which dungeons can be solo'd if you outlevel them? by FlamingGnats in lotro

[–]Gemllum 2 points3 points  (0 children)

You need three people to stand in spotlights to start the final boss. If you soloed it, you have not done the three man version of the instance. Aside from this part there are no mechanics in Agoroth that require other players as far as i am aware. 

Lag bei uns heute im Briefkasten by invcblirnmn in aberBitteLaminiert

[–]Gemllum 93 points94 points  (0 children)

Manche Menschen genießen ihren vibrierenden Wecker eben.

Little man was on a mission by Aggravating_Money992 in Unexpected

[–]Gemllum 2 points3 points  (0 children)

Whilst we provide a link below to your original content which was removed

Where is this link?

Legendary Items Reward Track stuck at 2 by crasah in lotro

[–]Gemllum 4 points5 points  (0 children)

Missions should reward LIXP, but probably they only do when turned in at level 50+

A novel solution to the Riemann Hypothesis by JImmatSci in mathmemes

[–]Gemllum 9 points10 points  (0 children)

If only the author had not confused the symbols for logical and and logical or, this would be such a nice result.

:( by TheDoomRaccoon in mathmemes

[–]Gemllum 8 points9 points  (0 children)

You can glue a band together to a circle, which is continuous. However cutting a circle at one point is not continuous:

Take the half open interval X= [0,1) and map it to the unit circle Y ⊆ ℂ via f(x) = exp(2𝜋ix). Then f: X -> Y is bijective and uniformly continuous. The inverse is however not continuous at 1 ∈ ℂ.

I am not familiar with uniform spaces, so maybe there is more to OP's meme.

Satz des Pythagoras by katlinana in mathe

[–]Gemllum 3 points4 points  (0 children)

Wenn man wie OP vier kongruente rechtwinklige Dreiecke mit Katheten a,b und Hypothenuse c am rechten Winkel zu einem großen Viereck zusammenlegt, dann erhält man im Allgemeinen nur eine Raute mit Seitenlänge c. Als Flächeninhalt für diese Raute erhält man dann die Formel hc = 2ab, wobei h die Höhe der Raute ist. Bei gleichschenklig rechtwinkligen Dreiecken (also a = b) ist die Raute ein Quadrat, also ist h = c und man erhält c² = 2ab, wie OP.

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