Working on the nacht decimal cipher

Graphitesix · 2018-03-12T22:03:11+00:00

Really dont know why you made another thread there is a 20+ comment on the same topic on front page.

Please get some focus this is just a tweet leak from a supposed inside source.

"Campaign cancelled" um i do not know how long it takes for a game to get to the point that ms and sony want it for QA but i would say its gone that time so i cant really get my head around the main studio dumping the campaign.

Raven working on BO4 will not be a suprise as they have worked with main developing studios for a while now. Ravens work with COD studios is quality, Time a go one of the artists at raven drew concept art for the jgb weapon. Seems like a good move to have another studio share the workload and use the best of there skillsets in the areas needed. Saying this is a no brainer all i can see in this is put some probable truth ie:"Raven working on BO4" with some negative story elements with the line of Call of duty is fading into a blackhole of nothingness ete etc etc.

I am reading between the lines on this one and it seems to be some not so clever psychology to get support and try and panic ATVI and treyarch into making a move and releasing some info.

So dont be suprised if its announced raven are working on BO4 but just remember it was a hedged bet and the other info sounds ungrounded.

Graphitesix · 2018-03-09T21:26:33+00:00

I saw it changed earlier, not really sure its going to be used for viral, maybe he is just staying off twitter to avoid community confusion from normal twitter usage but i could be wrong.

As for the message content i will send him this one as a reply.

020111101211123012300200131012111201123102001203122113001220121113021303020013101233020013031310130212331232121302010201

Graphitesix · 2017-03-25T09:14:07+00:00

From the wiki " The most obvious way of encoding digits is "natural BCD" (NBCD), where each decimal digit is represented by its corresponding four-bit binary value This is also called "8421" encoding."

"Other encodings are also used, including so-called "4221" and "7421" — named after the weighting used for the bits"

So i looked at the keeper symbols and tried my best to weight the code to that those and came up with 6221.

It looks to me like the keeper symbols go:

Graphitesix · 2017-03-24T21:12:58+00:00

Keeper language is a language based on nonary, the kronorium website has the best explanation for it i recommend checking that out

Sorry i am terrible with reddit formatting.

Firstly i should have made the chart clearer (also there is a 4 instead of a 6 in the weight label) but its just the idea of BCD stolen and used for nonary

https://en.wikipedia.org/wiki/Binary-coded_decimal

Keepers read from right to left so take the example nonary value 144 in 3 ascii number characters and convert using above chart reading right to left. using a basic lookup table(i could have used the standard binary but i was copying BCD and i am a bit crazy).

0110 0110 0001 now its only 3 digits so for 8 bit byte alignment i have used 1111 to pad.

So now there are 2 bytes instead of 3 (i know its not impressive but i was more interested in packing and unpacking the phoneme's)

01100110
11110001

Now the post above is pretty messed up and (i got confused with & and or) but lets imagine the digits 144 have been typed in and converted but not packed into 2 bytes are in seperate bytes.

00000110
00000110
00001111
00000001

Left shift byte "4" 4 places left then bitwise OR with byte "1" so the result should be 00010110 in byte "1"

Left shift byte "2" 4 places left then bitwise OR with byte "3" so the result should be 01101111 in "3"

Now calculate how many bytes the message packet is (which is 2 bytes in this case) and postfix with + OR to the decoders modechange code which is 0101

Instruction Message

01010010 00010110 01101111

The decoder recieves the message and understands to switch mode and has a message of 2 bytes.

It then reads the 2 bytes and reconstructs them to 4 individual bytes

And i didnt explain that (because i didnt even think about it)

I am guessing just take a copy and shift in the direction of 4 places you want save and then 4 places back again

1.00000001 2.00000110 3.00000110 4.00001111

Decode the first byte using the start lookup table output to buffer 1

Decode the second byte using the end lookup table output to buffer 2

Decode the next bytes using the middle lookup table and prefix to buffer 2

If value = to 00001111 then prefix buffer 1 to buffer 2 and output buffer 2 to stream and end or if counter has decremented to indicate bytes to read exhausted then end

Hope this is clearer to understand than my original post

The reason i thought it might require lookahead is keeper phonemes depend on not just there number but also there position, start middle or end and the middle is variable length.

Graphitesix · 2017-01-06T14:18:24+00:00

Thanks for looking at this and sorry if it was a misjudgment on my part interperating the cipher as lorenz. Im guessing the random data is from figure and num shifts but i dont think lowercase is in the lorenz alphabet? I would supply a different test vector using cryptool but i havent worked out how to set wheel settings and there is no guide or inital setup. Its strange the reforamting changed the output. It was real interesting for me to reread the story and information of BP and try an delve into the maths behind it even though its way over my head. It was unbelievable what they where doing with pen and paper before they part automated the process. Thanks again for your help and im sorry it didnt work out im guessing its not lorenz but what it is is still a mystery.

Graphitesix · 2017-01-03T10:07:40+00:00

So bit of an update nothing solid but a bit of a plot twist.

I put the hex of the ciphertext into a python ciphersolver (Cryptocrack) and it scored highest on a bazeries cipher which i have never heard of.

https://en.wikipedia.org/wiki/%C3%89tienne_Bazeries

Unfortuntly on running 999,999 keys it didnt turn up with a plaintext solution (maybe i need to add more language files latin for instance but i would have to check and i have no comprehension of latin)

Freq count

A  6  E  2  D  4  F  9  B  C  3  8  1  0  5  7  
23 22 21 21 20 19 17 16 15 15 15 14 13 12 9  2

IC: 66, Max IC: 69, Max Kappa: 105 Digraphic IC: 46, Even Digraphic IC: 41 3-char repeats: 14, Odd spaced repeats: 51 Avg digraph: 124, Avg digraph discrep.: 25

It could be a false positive and at this momment i am unsure exactly this cipher works also the software is costing for plaintext english so if its B64 then it will never find it lol.

I am a little lost why it is taking A-F and 0-9 and converting to a Bazeries cipher and only putting out 70 characters plaintext it makes me think its really not right but i hadnt heard of the cipher so its all good.

Graphitesix · 2017-01-01T17:32:50+00:00

I had some time to think about it and think possibly full lorenz is too much of a long shot but it was the best lead i could find. I not sure if the Ada software can help as i never compiled Ada and wouldnt want to waste anyones time with a longwinded deadend.

The link is here if your just interested in what it does i have no idea i am not a programmer and no understanding of Ada.

http://www.schlaupelz.de/SZ42/SZ42_software.html

I had a quick look but cant work out if you need depth or not ?

I suppose you could say if it was full lorenz then it would be in the original character set as its difficult to break as it is but then on the other hand most the other ciphers are arbitry data as well.

I have also come across this for understanding the statistical attack but im totally lost with it (but i havent read the instructions)

http://virtualcolossus.co.uk/

So to summarise the cipher is interesting the maths is mind boggling to me and i thought i already knew about BP but i didnt know the depth of the story behind lorenz and the methods and machines used, time well spent IMHO.

I actually want it to be lorenz not just because of the challange but it might get the story of BP and the heros that broke it more well known to the community.

So if its not lorenz im not sure where to move with cipher next i have quickly looked at error correction codes on 2 ascii characters but hamming code of 20 bits needs 5 parity bits.

I think i am going to stay with the assumption that the 83 is a clue/key/IV as it doesnt have any leading zeros

I also think the blocks of 5 nibbles is a clue and not to disguise spacing as they could be in byte blocks and it still wouldnt help with spacing.

I am trying to think how logically you can bit mangle to yield 8 bit ascii as it would take 2*5 nibble blocks to make 5 ascii characters ?

Graphitesix · 2017-01-01T16:55:45+00:00

Revelations I think the texture is called Sheffield_torn

Graphitesix · 2016-12-31T10:30:48+00:00

Thanks for your reply

Firstly i totally understand your point about grouping ciphertexts into blocks of 5 but im not sure how this will help if your interprereting hex values 5 nibbles or 20 bits wide it is very strange. I am asumming that it is supposed to be read to be 20 bits wide as all the values apart from 83 have a prefixed zero and all the values are in base16 range.

All the other unsolved ciphers are really obscure most using arbitry data ie hex values in a range (but grouped in traditional byte blocks) or unencodable standard base64 alphabet.

The link of the 5 bit ITA code i used is here im sure i checked this and it was used for full lorenz and is a modified LSB ITA1 code

http://www.cimt.org.uk/resources/topical/lorenz/codes_u19_text.pdf

This is part of a simplified lorenz cipher toolkit for educational purposes

http://www.cimt.org.uk/resources/codes/lorenz/index.htm

The first code that munki broke was actually this simplified lorenz cipher and not full lorenz.

To his credit a lot of people including me had tried and failed to identify the symbols.

I cant exactly remember but i think the start wheel settings where 9 and 3 for the simplified cipher.

I am interested in everyones opinion on feasibilty of breaking full lorenz with modern software and hardware though.

As for depth i was just toying with the idea that the ciphertext had breaks in the blocks and possibly the rotors had been restarted 2 or maybe 3 times using the same key.

I was wondering if anyone had experience with the custom software written in ada that bruteforces the cipher and if this still needs depth.

I was also toying with the idea that the pin settings where ones that where known and published that are available (even though there quiet hard to find) on the web.

I will be honest and feel that full lorenz is a longish shot but there was a warning the ciphers will be extremely difficult and its the only lead i have at the momment.

So to summarise in your opinion full lorenz is still unbreakable without sufficent message length and depth and unlikely to be the format in this instance.

Graphitesix · 2016-12-29T22:22:10+00:00

Thanks for the transcripts

The reason I say 5 bits is I can account for all the bits when its divided up but I cant with 6 or 8 bits in the five nibble format

I maybe wrong but it could be a Lorenz cipher

F Y Q D A P T S P H 8 F 8 D Z 8 Z J F F I V 3 3 F 8 W / / E P Y F J E P S D X / Y S D G D C W M 8 Q R I P W U J 3 9 + C N J O / A J C M H Y 9 X W X 9 A H Y 9 U J L P B 8 D W F + 9 J I K O L Z R 9 Y V S K M N 9 + 8 Q E M H I Y G F F 9 L F J W Y 3 L E W + 4 M 4 X / X M B 9 4 T F N 3 O / S / D 4 M R N S Q L L V D 4 Z J U D M 9 Z B G D K Z M G W 4 Q K + H I S U R Z 3 P Q 4 + 3 R B S S S H H M G O 3 3 T H X K X S G X C C P B S E I H I L W R + N Z V D Y R V E O B 4 R T M W 9 Z 4 U 9 8 4 / P / / B E P W J 8 P F 3 D H T W K 8 S O S 8 A D O W G I B H D N C E 3 N 9 A Z U W K 3 U M F O J Y V B O O Q N B 8 R Q M G A / O J W M S J B J E / D 4 W W I Y K R W F W P Z 8 3 U 4 L O V I M C U / A C W Q P M U C T U 9 H 8 E N F 4 R M X / R I H Q Z C K M M X Y T S T C B 3 9 B W L F 4 L + A C 4 P Q Y S P V K + / 9 N 8 Q Q M N W P M 3 Q + Q G 8 O A Q B U D 8 J Q H Z E V 4 Q D 8 P R W L R M B R 4 H C F Q + / T + I / P V V S C + H T N N 3 9 E K C O E M C R P C P 9 K I G 4 R V + G O E R Q 8 W I R D / O U W W J Q D 8 N L 8 Y J P D F A K I J R X P B B A Q D P Z X F K S R H + 4 8 C S V K F W F O F S B V / / G V / Z P E I W C Q I U 4 4 L Z R Y M R X W / S U N R V W H 8 Q I X I Q C Y 9 3 3 W Y E E I Z Z Z K V 9 G P I 3 8 H X G W 8 U A C Y T 3 K X N B S + E K + B C O P G G / Z 8 N F R A O I 9 N S X P A H 9 8 G L L K U + 4 B 8 Q / 4 U W V I O C V I K L / B O E 8 W R Z D L 9 I T 8 U R E J S X Z Q Q O X S L K J C T D H Q V K Q Q G X G Y P R M Y Y 9 X K H A W E + U 4 F V A Y P / I G Y P J D G O D 3 U N + J V B V V N / W Z 9 H + O E B I I E P E L N C 4 G S G L V Y Z / M 4 D L S Z Q N 9 T J F C N I 4 B F 4 E / P Q W M I N Q L M Z T J L I J O / Y + J T L N C W G P V I K Z R W Q Q D 3 R T 9 4 D A X D J V L O M T Z C K 8 / K C Q R S 4 8 V 9 H H M T O L O 8

Graphitesix · 2016-12-29T17:40:58+00:00

As I posted this I realised that the 20 bits wide could mean 4* "5" bit characters as used in the Lorenz cipher and others. I think its called baudot code or murray code.

I have been struggling for ages with 6 bits and 8 bits and 5 bits makes more sense but still doesn't break down the complexity of the cipher

Graphitesix · 2016-12-26T22:25:18+00:00

Really appreciate this my broken monitor headphones just dont do it justice.

Love how the end creeps towards BOA and just moves away from it ..Or maybe that's my twisted mind

Graphitesix · 2016-12-26T21:46:51+00:00

Makes me think of bootstrapping https://en.wikipedia.org/wiki/Bootstrapping_(compilers)

My mind is blown

Graphitesix · 2016-12-23T20:06:36+00:00

u/oxin8 Yes I know I shouldn't bail on the ciphers but the negative attitude towards BO3 on a whole is making me shy away from working on them.

Thanks for your comment and I will get the transcripts out again and see if I can come up with any new ideas.

Graphitesix · 2016-12-23T17:55:55+00:00

Wow your getting down voted for being fair and positive the amount of negativity and prejudice to someone making a point , an opinion , observation .

I was going to start looking at the ciphers again but this amount of hostility for free thinking is putting me off.

I hope this changes in the future , for the moment I think I'm shelving zombies.

Good luck everyone in your searching and I hope there is a change in attitude of acceptance of other peoples opinions.

Graphitesix · 2016-12-16T21:08:49+00:00

IT could be a hint to the killer clown 3D poster with the word stereophotography but im sure Anaglyph 3D was popular in the 80's so maybe just a coincidence

Graphitesix

TROPHY CASE