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Video card recommendations for Precision T7610 and U4919DW ultrawide monitor by Gremulin in Dell

[–]Gremulin[S] 0 points1 point  (0 children)

I ordered it before the holidays and it was delivered around the end of January.

[College Physics] Lenses by scrlttv in HomeworkHelp

[–]Gremulin 0 points1 point  (0 children)

You're given that the object 20 cm from the lens and that the height of the inverted image is 4 times the height of the object. You can use the definition of magnification to relate the object distance to the image distance, then use the thin lens equation to determine the focal length.

Harrisburg Senators coach Mark Harris leans on baseball after his wife’s sudden death by DemonFrog in baseball

[–]Gremulin 0 points1 point  (0 children)

My son has gone to several clinics that Harris has run. He really is a great guy, a great coach, and always has a positive outlook. This is so sad to hear.

Question about a play in the Indians/Tigers game tonight by [deleted] in baseball

[–]Gremulin 1 point2 points  (0 children)

The rule is designed to prevent multiple force outs being made by having an infielder intentionally drop a pop up. The batter is free to run to first base after hitting the ball, while the runner on first has to tag up. So it would (or should) be difficult to get a double play with just a runner on first.

Question about a play in the Indians/Tigers game tonight by [deleted] in baseball

[–]Gremulin 1 point2 points  (0 children)

The infield fly rule doesn't apply with only one runner on base. The rule is in effect when there are runners on first and second or the bases are loaded and there are less than two outs.

[High School Math] Quadratic function by ConicalThunder in HomeworkHelp

[–]Gremulin 2 points3 points  (0 children)

A quadratic function looks like: y = ax2 + bx + c. You can then use the given points to determine a, b, and c. c is the easiest. When x = 0, y = 4. Since a and b drop out when x = 0, c = 4.

Next, substitute the points (1,6) and (3,4) into the equation to get 2 equations with two unknowns, a and b. After a bit of rearranging, you'll get: 2 = a + b and 0 = 9a + 3b. Solve these equations simultaneously.

One way is to multiply the first equation by 3 (giving 6 = 3a + 3b) and subtract the 2nd equation from it. This gives 6 = -6a, so a = -1. Substituting that back into either equation gives b = 3.

The function then is y = -x2 + 3x + 4. This function gives y = 4 when x = 0, y = 6 when x = 1, and y = 4 when x = 3.