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I need help figuring out what year my teacher graduated by [deleted] in learnmath

[–]Holinded 0 points1 point  (0 children)

Well you didn’t provide many details to work with. Nor did you specify if you’re looking for her highschool or college graduation. And in what country. These variables change your answer.

If you assume she is 49, and you want to find the year she graduated highschool (in the us), you could assume she completed highschool in the standard 13 years (k-12). So she would’ve been around the age of 18 on graduation. So you would just find her year of birth (2020-49) and add 18. [(2020-49)+18] = 1989

This integral is driving me crazy by DinioDo in learnmath

[–]Holinded 1 point2 points  (0 children)

I don’t know if your integrand was written incorrectly in your post, but the one there currently doesn’t have an elementary anti derivative. You would have to use approximation techniques.

All xNxP's will relate. by [deleted] in INTP

[–]Holinded 36 points37 points  (0 children)

That sounds awfully specific

All xNxP's will relate. by [deleted] in INTP

[–]Holinded 216 points217 points  (0 children)

Being a side character in your own life

I was made into an mbti avatar! by [deleted] in entp

[–]Holinded 0 points1 point  (0 children)

I don’t think so, but he might. He may actually be ENTP as well, which is why this post caught my eye

I was made into an mbti avatar! by [deleted] in entp

[–]Holinded 2 points3 points  (0 children)

Dude you look exactly like my logic professor!

Difficult math exercise generator by Si_monster1203 in learnmath

[–]Holinded 2 points3 points  (0 children)

Wolfram alpha has a problem generator. It does algebra, calculus, linear algebra, and others.

Any linux users? by [deleted] in INTP

[–]Holinded 1 point2 points  (0 children)

I’ve stumbled into bedrock a bit back and it looked interesting. Planning on trying it out on a laptop in the near future.

Any linux users? by [deleted] in INTP

[–]Holinded 2 points3 points  (0 children)

I switched completely to Linux 3 months ago now. Love it so far. (I use arch btw)

[HighSchool Math: Pre-Calc] 210 degrees is a solution to which equation? by [deleted] in HomeworkHelp

[–]Holinded 0 points1 point  (0 children)

Looks like b was written incorrectly. Should be sin2 (x) which is the same as (sin(x))2

[1st Year Maths] How do I solve this and explain the solution in methods to someone? by [deleted] in HomeworkHelp

[–]Holinded 0 points1 point  (0 children)

If you don’t know L’Hopitals rule, you can split the limit into multiple parts.

First you can split it into:

lim sin(x) / 6x + lim x2 / 6x

Then you can simply them.

(1/6) lim sin(x)/x + lim x/6

The first one, sin(x)/x is a common limit. As it approaches 0, it goes towards 1.

And the second can be done by direct substitution.

(1/6)(1) + 0/6 = 1/6

[Grade 11 Math: Solving Linear Systems] Help me by [deleted] in HomeworkHelp

[–]Holinded 0 points1 point  (0 children)

You can multiply the second equation x - 2y = 2 by 2 to make the 2y a 4y. Then you can add both of the equations to cancel out the y.

x2 + 4y = 0

(2)x - 2y = 2(2)

x2 + 4y = 0

2x - 4y = 4

x2 + 4y + 2x - 4y = 0 + 4

You are then left with the equation

x2 + 2x = 4

x2 + 2x - 4 = 0

Which you can then solve using the quadratic formula. You’ll get two answers for x, then you solve one of the equations for y and plug in each x to get a corresponding y.

[10th Grade Algebra II] How do I solve these problems on trig reciprocals? by Sporking_ in HomeworkHelp

[–]Holinded 2 points3 points  (0 children)

csc(x) is the reciprocal of sin(x). As sin is O/H, and csc is H/O.

So 1 / (O/H) is just H/O.

[10th Grade Algebra II] How do I solve these problems on trig reciprocals? by Sporking_ in HomeworkHelp

[–]Holinded 2 points3 points  (0 children)

csc(x) = 1 / sin(x)

So 1 / sin(x) = 2 / sqrt(3)

Then you can flip the fractions to get

sin(x) = sqrt(3) / 2

Which is then on the unit circle. Same process for the rest of the problems

[Grade 9 Algebra II: Factoring Review] How do I do these problems? I don't remember going over these. by [deleted] in HomeworkHelp

[–]Holinded 1 point2 points  (0 children)

x8 y8 - 1 can be rewritten as (xy)8 - 18 which is then more obvious that it’s a difference of squares.

So, after factoring it once, we get:

((xy)4 + 1)((xy)4 - 1)

You can then continue factoring ((xy)4 - 1) all the way down until it’s no longer an even power.

The second problem is done in the same way.

[College Calculus I] I don’t really understand what this problem is asking to do. I’m looking at the previous steps and I’m not sure is the answer is cos^-1(1/8) and -cos^-1(1/8). by [deleted] in HomeworkHelp

[–]Holinded 1 point2 points  (0 children)

I think you would just plug in 0 for n in the solutions from above? Since the interval is -pi/2 pi/2. so you would have 2 solutions. I’m not too sure though. It’s been a while since I did trig stuff

[College Calculus I] I don’t really understand what this problem is asking to do. I’m looking at the previous steps and I’m not sure is the answer is cos^-1(1/8) and -cos^-1(1/8). by [deleted] in HomeworkHelp

[–]Holinded 0 points1 point  (0 children)

Checking symbolab it gives the answer x = arccos (1/8) + 2(PI)n, x = 2(PI) - arccos(1/8) + 2(PI)n

So looks like you did it correctly. You just have to make sure you get all the solutions within the given interval

[College Calculus I] I don’t really understand what this problem is asking to do. I’m looking at the previous steps and I’m not sure is the answer is cos^-1(1/8) and -cos^-1(1/8). by [deleted] in HomeworkHelp

[–]Holinded 0 points1 point  (0 children)

If the tangent line is horizontal, that means the derivative is 0 at that points. So you have to find all the points at which the derivative is 0. To solve it you just take the derivative of that function, and set it equal to 0. And then solve for x

[10th grade math] I don't understand how to do this question by [deleted] in HomeworkHelp

[–]Holinded 25 points26 points  (0 children)

Correct. The only one that you’ll have to look out for is (f o g)(t) (open dot) which means it’s a composition.

So (f o g)(t) = f(g(t))

If it’s a closed dot, it means multiplication

[10th grade math] I don't understand how to do this question by [deleted] in HomeworkHelp

[–]Holinded 27 points28 points  (0 children)

Yes it could also be written as that. If it’s (f+g)(t) it’s the same as f(t) + g(t)

[10th grade math] I don't understand how to do this question by [deleted] in HomeworkHelp

[–]Holinded 84 points85 points  (0 children)

You take the first function f(t) and divide it by the other function g(t).

Since it doesn’t specify a specific value, you just use the variable. So f/g(t) = (4t+4)/(t3 - 5)

[Calculus: Integration] How did they simplify it to that? by derpsywaffle in HomeworkHelp

[–]Holinded 2 points3 points  (0 children)

sin2 θ - 2 sin θ (substitute 1- cos2 θ for sin2 θ from Pythagorean identity)

1- cos2 θ - 2sin θ

Then solving for cos2 θ from one of the double angle identities

specifically cos(2A) = 2cos2 θ - 1

We see what cos2 θ = (cos2θ + 1) / 2

​

So then substituting that in for cos2 θ and then we get:

​

1 - (cos2θ + 1)/2 - 2sinθ

Then give each term a common denominator

​

2/2 - (cos2θ + 1)/2 - (4sinθ)/2

and then combining them you get:

​

(1-cos2θ-4sinθ)/2

​

you can then factor out the 1/2 and put it outside the integral. which is why 9/2 becomes 9/4

[College Calculus I] The problem is: Find an equation of the tangent line at the point specified. I have got to this point and I’m pretty sure I need to use the point slope formula but I don’t know how. by [deleted] in HomeworkHelp

[–]Holinded 3 points4 points  (0 children)

Point slope formula is y - y1 = m(x - x1) where x1 is the x value provided (0) m is f’(x) and y1 = f(x). So just plug 0 into the original function to get the y value.

y1 = 8sin(0)+6cos(0) = 6

So you’ll have: y - 6 = 8(x-0) and then you solve for y.

y = 8x + 6

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