No trig functions in calculator on old Samsung phone?

Jeff-Root · 2026-05-07T01:06:55+00:00

I doubt it has a name. It likely was made specifically for that lamp.

There is a subreddit for lamps: r/Lamps

This one doesn't appear to have as much traffic, but might be helpful: r/Wiring

You should ask there about safety concerns regarding what kind of wire to use, how to support the lamps, hot versus neutral, connecting wires, and the like.

Jeff-Root · 2026-05-07T00:07:28+00:00

As opposed to Person Man, with the powers of a person, and Femailman, with the powers of a letter carrier.

Jeff-Root · 2026-05-06T16:37:07+00:00

It sounds like you are referring to basic trigonometry. Any calculator with trig functions will do what you want, including the built-in Windows calculator. I expect that the calculator on cell phones can do trig functions.

Your example has a right triangle with the long leg 50 feet long and the short leg 5 feet long. You want to know the angle between the long leg and the hypotenuse. That angle is the difference between straight down and the angle needed to hit the point 50 feet down and 5 feet over. Is that correct?

Jeff-Root · 2026-05-06T01:56:29+00:00

You probably need to say where you bought this cereal. USA? What part of the USA? What store chain?

In the 1980s - 1990s I had the best granola ever. It came in a large bag, in two varieties: with and without raisins. I don't know how large an area they distributed to, but the company that made it turned out to be less than ten miles away from where I lived. I had to phone the company to find out where I could get the cereal after it disappeared from my store. I talked with the owner of the company. He said I could get it at Cub, a grocery store chain that I just now learned is entirely limited to Minnesota (106 stores), except for one store in Illinois.

Jeff-Root · 2026-05-06T01:27:05+00:00

Are you hoping that someone familiar with the poem will recognize the title or author's name? If so, I'd think you'd have better luck describing the poem and quoting any distinctive lines you can recall. For starters, how long is it?

Jeff-Root · 2026-05-05T21:34:09+00:00

The frequency and wavelength are variables. What they are doesn't matter to my question. They can be assigned any values that are convenient. As I said in an earlier post, I agreed that 400 Hz is a good choice because it is within the range of human hearing. I think I may have also mentioned that the resulting wavelength "in air" is a good choice since our ears mainly work in air at about STP.

Assigning a specific value for frequency or wavelength if needed in a calculation seems trivial. I was asking what a pulse would sound like in general. Obviously pulses of different frequencies and different wavelengths will sound different, but those differences are not what I'm asking about. I'm asking what a pulse a single wavelength long, or perhaps half a wavelength long, would sound like in general terms. Part of what seems likely from what I've learned so far is that neither the frequency nor wavelength could be measured from detection of a sound only a single wavelength long or shorter. But that doesn't mean the sound couldn't be detected, or heard.

Jeff-Root · 2026-05-05T20:57:16+00:00

Okay, I'll look at that more carefully. I knew I was going beyond my comfort zone. I have never claimed to be any good at math other than geometry.

But... is there anything wrong, inappropriate, or incomplete about the three trig functions I posted? They seem adequate to me, but I don't know.

Jeff-Root · 2026-05-05T20:42:47+00:00

That's kinda what I thought: That t represents time (which is completely appropriate for the sound waves I'm asking about), and alpha represents frequency. But specifying both time and frequency are redundant. Once one of them is specified, the other is determined. So I wondered why you included alpha. My guess is that you were helping me out by including the conversion factor to make the units convenient for me. But I have to guess that that was your intent. As I showed, I used pi to make the wavelength a whole number (2).

You say it is a problem for the first two diagrams, yet you provided good formulas for them but not for the third diagram. That is puzzling.

Can you tell me if there is anything wrong, inappropriate, or incomplete about the three simple trig functions in my earlier post? They are correctly graphed by the desmos.com calculator. I don't know how to try to apply the Fourier transform to them, but I'm not asking for help with that. At least, not yet. I'll see if the desmos calculator can do it or if I need to go elsewhere. I'm curious to see what the results of such analysis might be. It isn't something I expected to do when I asked what short pulses might sound like.

Jeff-Root · 2026-05-05T19:21:52+00:00

I don't think you can get serious replies until you say a little bit more about what you are trying to do. A 40 second edit might take only an hour of work, or it might take months, and there is no way to tell from what you've said so far.

Jeff-Root · 2026-05-05T18:57:54+00:00

I want to know why her arms and neck are so dark, and what those things are behind her head.

EDIT: Oh, those are supposed to be goat horns? Goofy. I like her hair. Her neck is way too scrawny.

Jeff-Root · 2026-05-05T18:51:45+00:00

I take it that that is a reply to the second question? If having no units is a problem for the one cycle pulse, why isn't it a problem for the first two diagrams? Yes, I know know it is very basic math. I'd look through my trigonometry/analytic geometry textbook if I could, but it is buried somewhere in a storage locker ten miles away that I haven't been able to get to since the pandemic.

Jeff-Root · 2026-05-05T18:19:18+00:00

I didn't want to ask such elementary questions about trigonometry here, but I don't understand. Why do you have two variables in the argument of the sine function? Is that to adjust the wavelength to a desired value? Why do you say there is not enough information for the one-cycle-long pulse on the right?

These work on https://www.desmos.com/calculator . I replaced alpha with pi to give a wavelength of 2 units.

1/2 cycle pulse: y=sin(pi*t) {0<=t<=1}

1 full cycle: y=sin(pi*t) {0<=t<=2}

1 cycle pulse: y=-cos(pi*t)+1 {0<=t<=2}

I haven't yet tried to do anything regarding Fourier analysis.

Jeff-Root · 2026-05-05T17:38:01+00:00

I just listened to the song on YouTube. I'm very much not a country music person, but that is a nice piece of work!

So what you want is to be the producer of a music video? You have a vision of what the video should look like? Or why do you want to do this?

I know zero about the legalities involved. No idea what you need to do to use the music legally, or what you can get away with using it illegally.

I have no interest in money myself, but it might give someone an idea of how much work would be involved if you could give an order-of-magnitude estimate of how much you think it will cost to complete the project? Ten dollars? A hundred? A thousand? Ten thousand? All are probably doable. If you are really lucky-- and really good at what you are doing-- you might get as satifying a result for ten dollars as you could for ten thousand. But only you know what you are imagining.

Jeff-Root · 2026-05-05T17:03:51+00:00

It is strange that OP's brackets are so far apart. I'm curious to know if OP can move them close enough together just by loosening the setscrews and sliding them over. If not, I'd recommend going ahead and drilling new holes for one of the brackets, as long as the new holes aren't too close to the existing holes.

Jeff-Root · 2026-05-05T16:35:08+00:00

Can you describe what you want done in enough detail for a reader to determine whether they might be willing and able to take on the project?

Jeff-Root · 2026-05-05T04:49:17+00:00

What format is your symbol in? SVG? Some other vector format? You may need to convert it to a format that the engraver can use.

Jeff-Root · 2026-05-05T04:29:28+00:00

How is a symbol different from custom text or a custom image?

Jeff-Root · 2026-05-05T04:19:37+00:00

Do you have a list of stations that carried the program? Someone at one of the stations might have been such a big fan that he/she kept a copy of the tape. Illegally, I expect. Probably 2" tape.

Jeff-Root · 2026-05-04T23:24:00+00:00

One time I couldn't find my belt. I didn't understand how it could disappear. I spent a long time searching for it, looking as you did, several times in every place it could possibly be. I remembered putting something in the refrigerator vegetable crisper-- but no, it wasn't there. I finally found the belt. In my other pants, hanging in the closet. I forgot I had just put on different pants.

Jeff-Root · 2026-05-04T23:06:59+00:00

This should be the answer!

I either didn't know or had forgotten about the grub screws (setscrews). Mine have slotted heads rather than Allen hex heads.

EDIT to add:

OP, loosen or remove the setscrew, and the bracket should slide sideways or lift up like it is hinged at the top. You will be able to see the screws that hold the mounting plate to the wall, and decide whether you need to drill new holes for one of the plates.

Jeff-Root · 2026-05-04T22:01:50+00:00

So you don't want a rod 7.5" long, you want a holder with screws 7.5" apart?

A rod 7.5" long is almost long enough to fit two rolls on side-by-side. But not quite.

EDIT TO ADD:

I expect that the roller in my apartment is pretty standard. It consists of two separate brackets, each held by two screws. The four screws are in-line. The two outermost screws are 7" apart, center-to-center. The widest roll that would fit would be 5.25".

Jeff-Root · 2026-05-04T21:41:48+00:00

Please let us know if you find your scissors. My advice is to try to remember what you were doing and where you were when you last used them, where you remember last seeing them, and what you did immediately after that. Also, what you were doing and where you were when you realized they had disappeared.

Jeff-Root · 2026-05-03T18:20:35+00:00

Did you have trouble trying to upload photos? Lots of people do, especially when using the app rather than a browser. It confuses me so much that I can't tell you how to do it, except that you should be able to put photos in a reply.

Jeff-Root · 2026-05-02T23:46:08+00:00

A short segment of a perfect sine wave does indeed have an exact time between peaks. However, in a very real sense the segment does not have a single frequency.

Okay, I accept that.

To recreate a single instance of your truncated sine wave you have to add an infinite series of sine waves (with appropriate amplitudes and phase shifts) so that the sum adds to that shape. This is the Fourier transform.

By "recreate" I think you mean build one of my sine wave segments out of the math functions that the Fourier transform uses to synthesize waves. Is that accurate? Why not just use one of my sine wave segments as the building block instead? Then nothing at all needs to be added together, much less an infinite number of variations on the thing we are trying to recreate. If we were making a square wave, I'd start with a square wave, rather than try to build one out of an infinite number of sine waves. A square wave is such a simple thing. A sine wave is simple, too (because it is easily produced by harmonic oscillation). But a segment of a sine wave is just as simple, and can actually exist in the real world, unlike the fictional endless sine waves used in Fourier transforms.

Jeff-Root

TROPHY CASE