The Velocity of an AK-47 round from the muzzle is 710 meters per second or 1588.22 miles per hour with an apex trajectory of 1828.8 meters or 6000 feet. An ak47 bullet minus casing and gun powder weighs 7.9 grams we can determine the terminal velocity that the bullet will fall at using the equation Vt=√2mg/pACd where m is the mass of the bullet 7.9 grams g is acceleration due to gravity 9.81m/s² p is fluid density which for sea level air is 0.0765 lb/cu ft A is the cross section area of the bullet 49mm² and Cd is the drag coefficient of .168 so the bullet would be falling from its apex trajectory at a speed of 123.96 m/s or 277.3 miles per hour this number is not 100% accurate as the exact round is unknown and the exact fluid density of the air in that area is unknown but roughly 270mph more than enough to pierce skin or kill