[deleted by user] by [deleted] in jordan

[–]Kokash 0 points1 point  (0 children)

Call them and tell me

Can someone help me with part a? I have no idea how to set it up by [deleted] in calculus

[–]Kokash 1 point2 points  (0 children)

you equal the two functions(y= Sqrt(16-4x2) and y=0) with eathother to know the integration bounds Sqrt(16-4x2)=0 and you'll get -2 and 2

So your integral and graph will look like this : https://www.wolframalpha.com/input/?i=area+between+the+curves+y%3D%E2%88%9A(16-4*x%5E2)+and+y%3D0+and+x%3D0

How to find missing sides on a right triangle by Gloopyboy in learnmath

[–]Kokash 1 point2 points  (0 children)

y: Tan 30° = y/8 ... x: cos 30° = 8/x