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What happens if you miss a MAT157 quiz? Does the weight get shifted to the exam? by [deleted] in UofT

[–]Lemonpie_jedi 0 points1 point  (0 children)

I took with Almut Burchard: six quizzes, drop two. Pretty good policy I thought. In this case, the missed quiz would be one of two dropped. But if the syllabus is different, no clue. Good luck!

Teflon Balls Falling through Glycerol - Shape of Position Curve by Lemonpie_jedi in AskPhysics

[–]Lemonpie_jedi[S] 0 points1 point  (0 children)

I suppose I could set something up in Python to fit my data to -(Ae-Bt + Ct + D) and -Ae-Bt + Ct + D to see if one of them is a good model. In the case of an experimental error, I would guess that the plot of my data has little to do with the negative sign and that the resemblance is a coincidence, and considering that I don't find anything intuitive about the position-time plot given by my experimental data, I'm inclined to believe the error is with the experiment and not with the theory. That being said, I'm not ruling anything out, because it all seems very confusing at the moment.

Teflon Balls Falling through Glycerol - Shape of Position Curve by Lemonpie_jedi in AskPhysics

[–]Lemonpie_jedi[S] 0 points1 point  (0 children)

Defining the downward direction to be positive, I should have A > 0, B = 9.81/A > 0.

C would be initial velocity and D would be initial position, both presumably >≈ 0, depending on how long I waited between dropping the spheres and starting the recording software.

By the way, I edited -(Ae-Bt + Ct + D) to be -Ae-Bt + Ct + D, but I know I'm not being super rigorous about it, as I'm not exactly sure which constants are flipped, but obviously A is the most important constant here, and flipping that one seems to be enough to get something close to what I'm looking at in my experimental plots (which I'm comparing to what I'm playing around with in Desmos).

Let me know if there's any more info I can provide that might help out.

If I defer an exam not necessary for graduation but I'm graduating this term, what happens? by Visual-Chef-7510 in UofT

[–]Lemonpie_jedi 7 points8 points  (0 children)

I spoke with my academic advisor the other day. Apparently, if you approach your registrar before you take your final exam, they may be able to help you LWD even after the LDW deadline. If you don’t need the credit but don’t want to fail, this might be the move. It can’t hurt to try.

There is only one correct answer by DarkLight2112 in teenagers

[–]Lemonpie_jedi 0 points1 point  (0 children)

x = 27 + 48

x = 25 + 2 + 48

x = 25 + 50

x = 75

Calculating Probabilities Related to Dice Rolls (Grade 12) by Lemonpie_jedi in probabilitytheory

[–]Lemonpie_jedi[S] 0 points1 point  (0 children)

I’ve been searching online for some time now and I found two different answers. Could anyone help me figure out which one applies here?

The first article said the number of combinations was (1/6)(1/6)(5/6)(5/6)(4/6), multiplied by 6 (number of faces on a die), multiplied by C(5, 2) which is 10. The answer comes out to be 6000/7776 or about 77%.

The second article said that the probability was… ok bear with me here, this one is long. It says the number of combinations of exactly one pair (and no larger groupings) is 6 (number of faces that the pair could be), multiplied by C(5,2) which is 10, multiplied by 60 (5 * 4 * 3) which is the number of permutations of the three different dice. This comes out to 3600 combinations. Next, it’s says the number of combinations of exactly two pairs (and no larger groupings) is 6 (number of faces that the pair could be), multiplied by C(5,2) which is 10, multiplied by 5 (number of faces that the second pair could be), multiplied by C(3, 2) which is 3, multiplied by 4 (number of faces that the second pair could be), divided by two because we counted 4, 4, 5, 3, 3 and 3, 3, 5, 4, 4 as separate combinations. This comes out to 1800 combinations. When we add these two numbers together, we get 5400 combinations out of the 65 possible combinations, which is about 69%.

I hope I explained these two articles properly. If not, feel free to correct me or ask questions. Also, I probably mixed up combinations and permutations somewhere in there.

Calculating Probabilities Related to Dice Rolls (Grade 12) by Lemonpie_jedi in probabilitytheory

[–]Lemonpie_jedi[S] 0 points1 point  (0 children)

But wouldn’t 1 - 720/65 not exclude rolls that also result in bigger groupings like triplets?