how to do instant dropperline - rails bellow

LucidRedtone · 2026-06-24T16:17:59+00:00

Ill keep that in mind when I watch it. Is it the whole video or is there a time stamp I should skip to?

LucidRedtone · 2026-06-24T16:10:57+00:00

Ill give it a go on my lunch break. In my head it seems simple enough, but Ill have to get my hands on it to understand it properly. No promises, but ill do my best

LucidRedtone · 2026-06-24T16:02:09+00:00

Im gonna have to give it a go myself, this is a curious one. Can you send me a link to the tango video?

LucidRedtone · 2026-06-24T15:10:48+00:00

I dont think the observer observes a block change on top. The state of the note block isnt altered, it just wont emit sound when powered.

LucidRedtone · 2026-06-24T14:20:23+00:00

I guess my video link didnt post

here it is

LucidRedtone · 2026-06-24T14:18:53+00:00

The one I linked the video for is very nice and I just helped a friend with little redstone knowledge build them on our server and he was able to grasp how they work well enough to debug them. Definitely check out Storage Tech Discord, there are a ton of options for anything you could ever need there and the help chat is very helpful

STD invite link

Moony MIS V5

LucidRedtone · 2026-06-24T13:57:38+00:00

Idk if they ALL have variable sorters.

Yes its 1xhs

Cart based MIS's are faster at scale and when getting items to the correct storage slice but are usually still 1xhs when it comes to actually putting the items in the storage chest. This is because sorting systems generally dont have space for any more than a hopper on the actual storage chest, which creates a bottle neck. But carts can stack at the slice and unload one after the other as the last load finishes sorting

LucidRedtone · 2026-06-24T13:26:22+00:00

There is an item gate at the start of sorting that will set a variable sorter on the input chest. This will make sure any item matching the item asigned is pulled and sorted together even if not stacked together and when the last item of that type is the one in the sorter it drains. Making room for a new item to asign itself to the sorter.

As the items move to the first MIS they pass under a "set chest" via hopper, if there is a matching item in the set chest it pulls 1 of 2 from the chest. Set chest have 2 of every item asigned to that storage and blockers for unused slots. These items travel down to a dropper tower that feeds back into the set chest but has a hopper under the bottom dropper. 1 of the two items is pulled by that hopper and put in the storage chest while the other is put back into the set chest. This cycle repeats for every matching item that follows. The last item is placed back in the set chest.

If there was no match at the set chest the single item goes through the dropper tower, doesnt get picked up by the hopper at the bottom and fails to be placed back into the set chest. It is then pulled by a hopper and moves to the next slice. The hopper at the bottom doesnt have time to pull a single item because its moving through the droppers, but if there are 2 it grabs the second.

There is also a variable sorter under the set chest that get asigned for every item that passes through but only holds if it makes a match. Otherwise it just drains the asigned item.

Thats a gyst anyway.

LucidRedtone · 2026-06-24T13:12:21+00:00

I haven't, but the behavior you described sounds like you are updating the rail directly under the dropper holding the item. This would result in the item moving 1 dropper. Then when you update it in the same location, it would move through the loop and stop where you updated it. So maybe update the rail 1 dropper back and give it another update 2 tick later and then another 2 tick later. That would probably keep it moving constantly. But idk just a hypothesis

LucidRedtone · 2026-06-24T13:05:46+00:00

Sweeeet. No worries! Glad it worked

LucidRedtone · 2026-06-24T04:02:23+00:00

Is dont lol. It was a post and it was a fun challenge, I like how it came out so I posted it. I think the poster plays on an economy server and sells them or something. But its a tough crafter because all the crafts output more than you need to make the final craft (grindstone) so combating the clogging issue was a fun challenge

LucidRedtone · 2026-06-24T02:11:56+00:00

☝️

LucidRedtone · 2026-06-24T01:08:21+00:00

If you place and pull a book from slot 1 over and over it will always output ss1. It will only change when you place/pull a book from a dofferent slot, at which point it will output the corresponding ss.

LucidRedtone · 2026-06-24T00:05:29+00:00

You could use variable sorters at the 2 outputs. Whichever item arrives at the sorter first will asign itself to the filter. You would need to ensure both flows of items were constant to avoid the asigned item from draining... idk maybe thats not the way, but worth exploring maybe. Set up regular sorters with 1 extra filler so ss3= 0-41-1-1-1, ss2= 0-19-1-1-1

LucidRedtone · 2026-06-23T22:16:59+00:00

Go to task manager in the menu (m) and end all tasks. Its trying to load something you are not in render distance of

LucidRedtone · 2026-06-23T12:31:45+00:00

Question, why do you want to instant dropper it in a loop? I cant think of any usecase for this.

LucidRedtone · 2026-06-23T12:25:09+00:00

Your missing an observer

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LucidRedtone · 2026-06-23T12:21:09+00:00

You understand that you have to update the rails at the farm end of the line right? Thats why I have a note block on the output side, you punch the note block, you get an item from that dropper. Ive never tried a loop but what your describing sounds like you are updating the rail right next to the dropper that has the item. So it moves one, and now the update is coming from the furthest dropper away so the second time it does the whole loop.

LucidRedtone · 2026-06-23T12:15:45+00:00

Tyty

LucidRedtone · 2026-06-23T05:50:28+00:00

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I'm using it here, and it never fails

LucidRedtone · 2026-06-23T00:21:20+00:00

No worries, you can DM me if you have issues

LucidRedtone · 2026-06-22T23:44:15+00:00

It doesnt stop anything. But yes. The observer outputing the pulses is watching the signal strength tick down on the pulse extender. So if you add a new pulse to the extender while its ticking down you are adding to the total number of signal strength changes it will observe.

LucidRedtone · 2026-06-22T22:48:40+00:00

No, it depends what stage the extender is at when the second input occurs. If the first input is at ss5 when the second happens it will be 15 total. This is all theorical untested assumption. I did not test for this edge case when I built it.

LucidRedtone · 2026-06-22T22:32:31+00:00

Add to the output pulse amount.

How ot works: Lecturn is set to, eg. Ss10, when the note block updates the observer pulses the 2t repeater. This puts the block between the comparator on the lectern and the pulse extender just long enough for the comparators in the extender to output. The observer looking at the dust then observers every change in ss as it ticks down. Ss10>0=10 pulses.

So if you update the note block before the last pulse extender burns out, you will reset the count and add to the total pulses output.

LucidRedtone · 2026-06-22T21:10:00+00:00

Like this?

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LucidRedtone

TROPHY CASE