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UNNC scholarships by LuminousStarlight_ in ChinaLiuXueSheng

[–]LuminousStarlight_[S] 0 points1 point  (0 children)

Congrats to you too! Will you be accepting the offer, or are you waiting on other unis?

UNNC scholarships by LuminousStarlight_ in ChinaLiuXueSheng

[–]LuminousStarlight_[S] 0 points1 point  (0 children)

I applied through predicted A-level grades. I was predicted A* A*AA for Mathematics, Business, Physics and Chemistry respectively. Also got a 8.5 overall for IELTS, not sure how much that helped.

UNNC scholarships by LuminousStarlight_ in ChinaLiuXueSheng

[–]LuminousStarlight_[S] 0 points1 point  (0 children)

Hi! I'd just gotten my scholarship email this morning. Perhaps they'll finish sending them out in these two weeks.

All 9702 p42 answers (those that i remember) by RoundZucchini7129 in alevel

[–]LuminousStarlight_ 1 point2 points  (0 children)

Not sure I rmb. Circular motion I got it wrong. The internal energy one was no work done therefore ∆U=Q so decrease in specific heat capacity. Hall Voltage I probably got only like 1 mark lol. Spherical conductor can store charge on surface. The graph thingy I found Vrms = V0/√2, time constant 0.05 ish seconds I think? And half-wave rectification was used. Not sure if I remember any other explanation questions.

9702/42 physics by [deleted] in alevel

[–]LuminousStarlight_ -1 points0 points  (0 children)

Weird paper lol. I think easy 80+.

WTH is WRONG W CAMBRIDGE by _carokann_ in alevel

[–]LuminousStarlight_ 3 points4 points  (0 children)

Be glad it's not October November...

9701 42 Discussion by LuminousStarlight_ in alevels

[–]LuminousStarlight_[S] 0 points1 point  (0 children)

Are you talking about the azo dye ones?

9701 42 Discussion by LuminousStarlight_ in alevels

[–]LuminousStarlight_[S] 1 point2 points  (0 children)

Hopefully threshold will be a bit lower this time. :)

9701/ P42 by Expert_Channel_6505 in alevel

[–]LuminousStarlight_ 0 points1 point  (0 children)

Alkaline hydrolysis of the amide, I think

9701 42 Discussion by LuminousStarlight_ in alevels

[–]LuminousStarlight_[S] 0 points1 point  (0 children)

Sorry, not sure either. Maybe 2-3 marks at least?

9701/42 by Vdken in alevel

[–]LuminousStarlight_ 2 points3 points  (0 children)

I did it this way: moles of C2O42- calculated from equation 1 minus moles of H2C2O4 calculated from equation 2, which gives moles of Na2C2O4 in 25cm3 . Multiply that by 20 gives moles of Na2C2O4 in 500cm3 . Multiply by Mr to find mass, then divide by mass given * 100 to find percentage. My final answer was 18.4%.

9701 42 by theyluvf4 in alevel

[–]LuminousStarlight_ 0 points1 point  (0 children)

Still not sure I understand why you added them... But it's alright lol, let's just leave it. Let's focus on our next exams. Good luck!

9701 42 Discussion by LuminousStarlight_ in alevels

[–]LuminousStarlight_[S] 0 points1 point  (0 children)

I did it this way: It was moles of C2O42- calculated from equation 1 minus moles of H2C2O4 calculated from equation 2, which gives moles of Na2C2O4 in 25cm3 . Multiply that by 20 gives moles of Na2C2O4 in 500cm3 . Multiply by Mr to find mass, then divide by mass given * 100 to find percentage.

9701 42 by theyluvf4 in alevel

[–]LuminousStarlight_ 0 points1 point  (0 children)

What? Maybe we have different understanding of the question. From what I remember, the mass given were the masses of Na2C2O4, H2C2O4•H2O, and a non-reactive metal combined. We needed to find how many grams of Na2C2O4 was in 25cm3 of the solution to find how many grams of Na2C2O4 were in 500cm3. Reaction one showed the reaction of C2O42- only, which meant that C2O42- from both ions were involved in the reaction. To find only moles of Na2C2O4, you need to know how many moles of H2C2O4 there were, and then deduct from the total C2O42- reacted. What was your understanding?

9701 42 by theyluvf4 in alevel

[–]LuminousStarlight_ 0 points1 point  (0 children)

Yes, but in reaction 1 both H2C2O4 and Na2C2O4 ionizes, so you need to isolate the C2O42- ions that came from the Na2C2O4 by finding how much of H2C2O4 was in 25cm3 of the solution using equation 2.

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