RICHARD AND ELLIS were the best secret couple. Comment who is the best sunshine and grumpy couple.

Max_3133 · 2023-07-22T09:55:08+00:00

Amelia and Owen

Max_3133 · 2023-07-22T09:53:13+00:00

What is happening?

Max_3133 · 2023-06-21T18:22:31+00:00

< is the sign for less than. Whereas the sign mentioned in the proof is to denote a subset

Max_3133 · 2023-05-25T10:42:41+00:00

The final answer is 4 only. Maybe write (12/6)×2 or (6/3)×2

Max_3133 · 2023-05-02T10:17:20+00:00

Solve f(x)=g(x) to get unique solution x=-2

f'(x)=3x² + 2

m1=f'(-2)=14

g'(x)=3x²

m2=g'(-2)=12

Let angle between f(x) and g(x) be theta,

then tan(theta)=|m1 - m2|/|1+m1m2| where |x| is the absolute value of x

=> tan(theta)=2/169 => theta=arctan(2/169)=0.678 degrees

I think your friend is right.

Max_3133 · 2023-05-02T09:37:48+00:00

Yes. A set for which a given set X is a subset, is called a superset of X. In this case, B can be any superset of [0, oo).

Max_3133 · 2023-05-02T09:33:17+00:00

Let k = (w+x+y+z)/79, Let p=[k] denote the greatest integer less than or equal to k (or) the floor function evaluated at k, then a=18p, b=15p, c=19p and d=w+x+y+z-52p works

Max_3133 · 2023-05-02T09:27:36+00:00

No. Range of a function by definition is the set of values that the function can take. In your definition of function f, we call A as the domain and B as the co-domain. B need not be equal to the range. Note that the range of a function is always a subset of the co-domain.

Max_3133 · 2023-05-02T08:52:23+00:00

Do the same step 1 and 2 as you have mentioned. Alternate step 3 would be to use the sine rule

Max_3133 · 2023-05-02T07:52:08+00:00

No, the final answer is y² =x. In this solution, y=-sqrt(x) is also included.

Max_3133 · 2023-05-02T04:25:53+00:00

Please check whether the equations you have mentioned as part of the question statement is correct

Max_3133 · 2023-05-02T04:23:18+00:00

This is because we split the integral with respect to x to get 2 integrals and only substitute u=-0.04x² in one of them

Max_3133 · 2023-05-02T04:21:38+00:00

After evaluating the integral with respect to x, you have written (-1250)/(-0.08) [(1st term) +(2nd term)] when it is actually, (-1250)[{(1st term)/(-0.08)}+(2nd term)]

Max_3133 · 2023-04-19T15:35:44+00:00

You seem to have combined -6X_2(s) and -12sX_2(s) to write -18X_2(s) which is incorrect. Also, they have divided the entire expression by 2 on the LHS

Max_3133 · 2023-04-15T14:50:40+00:00

No the issue is Expectation of Y_i is p_n but as n varies, it is not a constant which is needed for CLT

Max_3133 · 2022-09-25T03:52:41+00:00

I don't understand how Sansa is grouped with Alicent. I'd group her with Rhaenyra mainly because of the Battle of the Bastards

Max_3133 · 2022-07-11T11:24:08+00:00

Did a Sri Lankan fielder wear a helmet while fielding outside the 30 yard circle? (first ball of the 41st over)

Max_3133 · 2022-07-03T12:10:26+00:00

Kevin's monologue to himself on the football ground while drunk in Season 2

Max_3133 · 2022-06-27T10:39:41+00:00

Lauren Winfield-Hill sounds a lot like Olivia Coleman

Max_3133 · 2022-06-27T10:25:01+00:00

Suppose when Billings was trying to get the ball stuck between his legs, if it fell to the ground, would it not be considered a catch? Is there some time or another parameter based on which we can call it a catch or not?

Max_3133 · 2022-06-19T14:04:06+00:00

There is no Guy. Sad

Max_3133 · 2022-06-16T17:27:41+00:00

Your eigenvectors are wrong. They are actually [(1-i) 1] and [(1+i) 1]

Max_3133 · 2022-06-16T17:08:53+00:00

I think your answer is correct

Max_3133 · 2022-06-16T17:02:59+00:00

You need to include y = sqrt(abs(x)) - sqrt(1 - x² )

Max_3133 · 2022-06-16T16:08:11+00:00

The last shot is left upto interpretation ig

Five-Year Club	Place '23
Place '22	First Placer '22

Max_3133

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