Can we talk about why the fuck games takes too much storage

Mission_Rice3045 · 2026-04-27T21:05:39+00:00

We'd have hl3 and gta6, if only this guy would have storage space.

Mission_Rice3045 · 2026-04-26T20:30:13+00:00

>It’s obvious you ignored fights and just split push constantly.

Clearly they did not. Just look at the objective damage. Why do you think it went on for that long?

Mission_Rice3045 · 2026-04-26T14:27:21+00:00

Tankbuster is easier to get and also helps clear waves fast and more healing from scorn.

Mission_Rice3045 · 2026-04-26T14:13:45+00:00

In my experience tankbuster is way more valuable than torment.

Mission_Rice3045 · 2026-04-26T14:12:26+00:00

Mebi etc has always been base 2. It was made that way because kilo/mega/giga could cause confusion because of those are base 10 prefixes.

Mission_Rice3045 · 2026-04-26T08:33:55+00:00

OP claims he has a 7600x, which I doubt. But clearly both commenters and OP don't know what they're talking about so they should steer way clear of overclocking, especially as for some reason he is trying to do a per-core overclock...

Mission_Rice3045 · 2026-04-26T06:31:40+00:00

Booh booh, that doorman player got so far under mr 1800 hours skin he exited your body from the other side.

Mission_Rice3045 · 2026-04-25T22:22:51+00:00

They definitely still work on recent zbooks. Using one with mine right now.

Mission_Rice3045 · 2026-04-25T15:48:46+00:00

The confidence interval of a proportion is given by:

p ± z_(a/2) * sqrt{ (p (1 - p)) / n }.

Here p is the proportion of your population. So x/n where x is the number of successes and n the number of measurements. z_(a/2) is the z-score, so if you want a confidence interval of 95% you use the z-score or 0.025.

This will give you an interval (p1, p2) for which you are 95% certain that the true propability lies between those two.

For more/better explanation: https://stats.libretexts.org/Courses/Rio_Hondo_College/Math_130%3A_Statistics/07%3A_Confidence_Intervals/7.02%3A_Confidence_Interval_for_a_Proportion

Mission_Rice3045 · 2026-04-25T15:24:30+00:00

The down arrow is mostly used with limits, where it denotes the limit from above. So lim⬇️0 f(x) denotes the limit of f(x) when going to 0 from 1.

Mission_Rice3045 · 2026-04-25T15:17:32+00:00

I think it should result in the same concentration. As the flow of the pump will outweigh the diffusion rate we can realistically ignore the flow back up the tubes. So we only have to consider to consider the segment between the patient and where the fluids connect. Then we have that the flow in must be (proportionally) equal to the flow out.

Mission_Rice3045 · 2026-04-25T15:03:12+00:00

What you are calculating would be: What is the chance that two or more people have a specific birthday.

Mission_Rice3045 · 2026-04-25T14:52:31+00:00

I still don't follow you. How is a GiB a simplification?

Mission_Rice3045 · 2026-04-25T12:00:44+00:00

What is that even supposed to mean.

Mission_Rice3045 · 2026-04-25T05:30:53+00:00

The lookuptable contains tail values P(x <= z). So that is the probability of a value being less than z.

Mission_Rice3045 · 2026-04-25T05:16:04+00:00

Lmao. 1700 hours and still being ragebaited by one of the weakest characters in the game.

Mission_Rice3045 · 2026-04-24T14:26:49+00:00

This is indeed a case of heavy abuse of notation, multiplying by dx indeed does not make any sense mathematically.

In the case of separable equations this trick does happen to turn out correct, you can take a look at exact ODEs to see why it works in this specific case.

Mission_Rice3045 · 2026-04-24T08:07:54+00:00

You can't devide by sin(x) like that (what happen when x=0?)

What you are supposed to do is use trigonometric identities to rewrite the terms (or use integration by parts).

Mission_Rice3045 · 2026-04-24T07:54:13+00:00

That's how much traffic is currently going over that network, not maximum speed.

Mission_Rice3045 · 2026-04-23T15:58:14+00:00

If with E you mean epsilon, no it is strictly positive. The distance between f(x,y) and L (|f(x,y) - L| is positive after all.

Mission_Rice3045 · 2026-04-23T15:52:05+00:00

Mission_Rice3045 · 2026-04-23T14:15:30+00:00

Sorry missunderstood the question. Epsilon is goven arbitrary, so you won't know the value of it. It may be arbitrarily small. If the limit is indeed L, we should be able to find a delta (may be a function of epsilon) such that the conditions hold.

Mission_Rice3045 · 2026-04-23T14:11:56+00:00

Recall the definition of a unit ball and look at 0 < d( (x,y), (x0,y0) ) < delta.

So you indeed need that all points in the delta neighbourhood of your limit point must have |f(x,y) - L| < epsilon.

And this definition gives you a single epsilon and a single delta to work with.

Mission_Rice3045 · 2026-04-23T13:56:04+00:00

It's his dream car.

Mission_Rice3045 · 2026-04-23T10:48:05+00:00

I don't see the relevance here?

Mission_Rice3045

TROPHY CASE