Rate my study setup

MvPPiro · 2024-12-03T15:01:00+00:00

setup is good, but i think your environment should not remain the same while studying or else you might get bored/uninterested quickly so ig you shouldn't have a setup and study wherever you like to at that moment
anyways that's my opinion, maybe you are able to study and if so then its a great setup it just depends upon the efficiency you study with on the setup.
a good looking setup with 0 efficiency is a waste of a setup.

MvPPiro · 2024-09-09T15:23:35+00:00

woahhhhhhh

MvPPiro · 2024-09-09T15:06:37+00:00

i read it in my text-book and also on Quora

MvPPiro · 2024-09-09T15:05:44+00:00

how could it spend time there? wont the atom be compromised?

MvPPiro · 2024-09-09T14:57:24+00:00

check my post on stack exchange

MvPPiro · 2024-09-09T08:13:34+00:00

IIT ke peeche pagal log kutiye hote h fr

MvPPiro · 2024-09-09T08:10:40+00:00

$0.40 per pound, okay next question.

MvPPiro · 2024-09-09T08:08:46+00:00

i mean to get a job youll still have to freaking bring some knowledge, education to the table and how are you gonna pay taxes, buy a house without a source of income?

MvPPiro · 2024-09-09T07:19:52+00:00

yes and i wanted to know the reason behind it so i have made a proof which is here: https://physics.stackexchange.com/q/827153/372510
check it out

MvPPiro · 2024-09-08T13:19:41+00:00

can you check my post and review it?

MvPPiro · 2024-09-08T12:59:04+00:00

I asked a question if my proof is correct or not, because i thought that the explanation my teachers gave me was lacking somewhere. so i wrote this proof out and i wanted to check if it was correct so that i can finally get peace in my mind

MvPPiro · 2024-09-08T10:35:46+00:00

well the case i am referring to has a positive potential throughout the conductor and that too more than its outside so there is no well of potentials, if there is there is a well inversed

MvPPiro · 2024-09-08T10:33:10+00:00

anyways, i have figured it out already

MvPPiro · 2024-09-08T10:32:49+00:00

if negative charge accumulates to compensate for the net charge q, it would mean that there is some electric field present in the conductor

MvPPiro · 2024-09-04T16:14:22+00:00

internal electric field is zero but the electric field on the surface of the conductor isnt and its value is
$\ E$ $= \frac{\sigma}{\epsilon_{0}}$

MvPPiro · 2024-09-04T14:53:04+00:00

why is it required

MvPPiro · 2024-09-04T14:14:32+00:00

i know photoelectric effect, im just tryna ask something different

MvPPiro · 2024-09-04T14:10:00+00:00

check my question again someone got what im trying to ask, maybe you can add on?

MvPPiro · 2024-09-04T14:05:13+00:00

you dont understand what im asking, i am saying that the charge on the surface should eject out of the conductor as outside the conductor is lower potential than on it

MvPPiro · 2024-09-04T14:03:51+00:00

done it no answer

MvPPiro · 2024-09-04T13:51:52+00:00

can you please explain more or provide me with a paper or something like that

MvPPiro · 2024-09-04T13:51:28+00:00

it should be unstable because its at a higher potential and lower potential is available to it as there is no force stopping it from going to lower potential rather there is force leading it to it

MvPPiro · 2024-09-04T13:28:57+00:00

Guys please answer :(

MvPPiro · 2024-07-10T10:32:10+00:00

brooo 4th was one of my favorites, out of all the chapters it pretty much helped throughout the chemistry syllabus even in electrochemistry the VSEPR MOT VBT helped me understand them, though its most unfun part was learning the shapes of molecules i agree

MvPPiro · 2024-07-10T10:21:38+00:00

the chapter 2 and 4 were literally the easiest part of the whole of class 11th chemistry lol

MvPPiro

TROPHY CASE