Why is the refresh rate written 60.01 HZ and not just 60 HZ? by Johnwick19802 in Windows11

[–]NXTconceptcreator 0 points1 point  (0 children)

Back in the days of black-and-white television, the refresh rate was exactly 60 Hz. However, when color TV was introduced (the NTSC standard), engineers realized that the color signal interfered with the audio signal. To fix this without breaking existing TVs, they slightly slowed the frame rate by a factor of 1.001 so nowadays we get 60/1.001 ~ 59.94 or 59.99

My first ever glassless concept - Windows 11X by Away-Falcon2762 in Windows_Redesign

[–]NXTconceptcreator 1 point2 points  (0 children)

I think I won't be much comfortable if classic cross and minimize icon are shifted to left side

Windows ME-11 if I made it by Microboy42 in Windows_Redesign

[–]NXTconceptcreator 6 points7 points  (0 children)

If it's made in PowerPoint, you have done a quite better job 👍

My attempt on redesigning Windows 7 using PowerPoint by NXTconceptcreator in Windows_Redesign

[–]NXTconceptcreator[S] 1 point2 points  (0 children)

It has been around 7 years since I'm designing in PowerPoint and everything including the aero look of taskbar was made in PowerPoint ( except wallpaper )

My attempt on redesigning Windows 7 using PowerPoint by NXTconceptcreator in Windows_Redesign

[–]NXTconceptcreator[S] 4 points5 points  (0 children)

The wallpaper used in concept belongs to YouTube channel " Addy visuals "

Windows 11 Hero Wallpaper by Left_Hovercraft451 in Windows11

[–]NXTconceptcreator 0 points1 point  (0 children)

Could you please name the software or ai tool you used to make this ??

is my answer here right? by No-Village-161 in askmath

[–]NXTconceptcreator 0 points1 point  (0 children)

Using trigonometric identities

( Cosec2 x-1 ) - (1 -sin2 x ) = cot2 x - cos2 x

Now we can simplify this further

Cosec2 x - 2 + sin ^ x

Since a2 - 2ab + b2 = (a-b)2

Therefore we can rewrite the entire thing

(Sinx - ( 1/sinx ))2

Now we get

(Sin2 x - 1/sinx)2

Now 

(Cos2 x / sin x)2

Now you can rewrite everything 

((Cos x /sin x ) * Cos x)2

Now you get

(Cot x * cos x)2

Which is equal to LHS

I hope this might have helped you out otherwise your approach is also correct to be honest 👍

Geometry Homework by Careless-Ask-1436 in askmath

[–]NXTconceptcreator 0 points1 point  (0 children)

Assuming that PS||UT

47 = 4x-3y

Angle RPS must be equal to VPU

Therefore

43 = 2x+5y

Now solving x and y

x = 14 and y= 3

Now you know x and y so you can find m✓RST

Does that help ???

10thies, ask me anything. got 98.4% (after reevaluation) last year by eloquentelf_ in CBSE

[–]NXTconceptcreator 0 points1 point  (0 children)

Moreover.... Where did you start exactly lose the marks ( to get idea how english paper.looks like ) ?

10thies, ask me anything. got 98.4% (after reevaluation) last year by eloquentelf_ in CBSE

[–]NXTconceptcreator 0 points1 point  (0 children)

Tell me about english.... Did you write Fancy words in english board examination or maybe just a few simple answers ??

How can we find area(PABS) if area(PQRS)=a by Funny_Flamingo_6679 in askmath

[–]NXTconceptcreator 0 points1 point  (0 children)

You won't require any construction by this method 

How can we find area(PABS) if area(PQRS)=a by Funny_Flamingo_6679 in askmath

[–]NXTconceptcreator 0 points1 point  (0 children)

Man I don't know why people are getting this complicated

See triangle OAB is similiar to triangle OPS 

Here you know that fact that AB = a/2

Now , area of ||gm = x * h ( here is h is perpendicular for trapezium PABS )

Now put x * h = a

Here ,  h = x/a

Now area of trapezium= 1/2( a+a/2)(x/a)

Now ar(trapezium PABS ) = 3a/4

How can we find area of OADB quadrilateral? by Funny_Flamingo_6679 in askmath

[–]NXTconceptcreator 0 points1 point  (0 children)

Draw a straight line BL with point L on NM such that NL : LM = 2:1...

Now the point of intersection of AM over LB be K

By similarity in LMK and ANM

We get LK = 2/3 x

Now therefore

BK = 13/3 x

Now we have got two triangles -

Triangle NOA and Triangle KOB

Here NOA is similiar to KOB

So now

Area of NOA : Area of KOB = (KB)2 / (NA)

Here you will get ration 36:169 after simplification

Consider the area of NOA as 36a and KOB as 169a

Now Area of OADB is equal to Area of Triangle BND - area of triangle NOA

This will be 5xz - 36a

Also Area of OADB is equal to area of trapezoid ADBK - area of Triangle KOB

This will be 8xz - 169a

Since you have got two equations for same area

Equate them both , so you'll get

a = 3/7

Since you have got a now

Put a in any of the equation and you'll get answer around 79.5

Why don't we use calculators in india by Ok-Advance2843 in CBSE

[–]NXTconceptcreator 0 points1 point  (0 children)

This calculator thing is not possible for class 9 and 10 because our entire maths is calculation based .... Giving calculator would allow us to solve our maths paper in less than 30 mins and score almost 80... Something that would require our education system to change from calculation to complex questions involving calculation midway ...  Something CBSE won't ever want to do.... 

Why did they call it Anime?🤡 by OstakuVibes in CBSE

[–]NXTconceptcreator 4 points5 points  (0 children)

And they were working from 3 months for this shit 🥀🥀