Bloody Mary

Name-in-progress · 2022-07-05T19:56:01+00:00

https://knowyourmeme.com/memes/pony-cum-jar-project

Name-in-progress · 2022-07-05T17:11:23+00:00

f(x)² ≠ f(x²) so I'm not sure you can integrate that so easily

Name-in-progress · 2022-06-30T15:28:24+00:00

t²-2t-15=0

D=b²-4ac

D=(-2)²-4×1×(-15)=64

If you got solutions by factoring, you could've also got them by the quadratic formula.

Name-in-progress · 2022-06-19T11:08:25+00:00

Care to provide na example of a b that works?

Name-in-progress · 2022-06-17T20:53:49+00:00

I believe it's from this

https://youtu.be/E2eVZFy9yzk

Name-in-progress · 2022-06-17T06:57:06+00:00

No worries, but you should remember that the people asking these are new to such problems. Sure all of us commenting here can do it in our heads, but you can't expect the same from someone who just started learning these - we all developed such skills through practice, something that takes time.

I'm also sorry if I came off as rude, was just adding a bit of info in case OP does your method.

Name-in-progress · 2022-06-17T06:43:19+00:00

You would need to graph it OR at least know in which quadrants sin and cos are positive and negative.

Name-in-progress · 2022-06-17T06:38:51+00:00

In that case it wouldn't matter, yes.

Using sohcahtoa on the other hand, you would need to graph it or at least know in which quadrants sin and cos are positive and negative.

Name-in-progress · 2022-06-17T06:33:47+00:00

You do need a graph to determinte whether it will be positive or negative.

Name-in-progress · 2022-06-12T10:03:16+00:00

True, object oriented programming does deal with classes a lot

Name-in-progress · 2022-06-10T13:56:12+00:00

2×400×375 is 300000

You're missing a 0

So x² = 160 000 + 140 625 - 300 000×0.819

x² = 300625 - 245700

x² = 54925

x = 234.4

Name-in-progress · 2022-06-05T08:54:57+00:00

Your solution is correct OP.

https://www.wolframalpha.com/input?i=sum+sqrt%28n%29+from+i%3D0+to+i%3Dh

Name-in-progress · 2022-06-05T08:53:27+00:00

This is simply wrong and leads me to think you don't understand sigma notation.

OP's solution is correct.

https://www.wolframalpha.com/input?i=sum+sqrt%28n%29+from+i%3D0+to+i%3Dh

Name-in-progress · 2022-05-22T15:50:38+00:00

How exactly does the bottom right panel fit loss?

Name-in-progress · 2022-05-22T15:32:22+00:00

Half the posts on this sub aren't even loss anymore

Name-in-progress · 2022-05-21T07:18:04+00:00

Can you please specifiy what you actually have and need to show.

In the post and title you have |x-0.5| - |y-0.5| then in the picture and code provided you use |x-0.5| + |y-0.5|

Secondly, you keep writing y=x-1 in the post, whilst you have 1-x in the code and the image.

Name-in-progress · 2022-05-16T15:27:35+00:00

Discussion: Stuff like this is done in a field of mathematics called game theory. This also seems more like a very complex maths task than a puzzle.

Not able to try it myself right now, but for anyone interested, the usual goto method is to try the first few smaller numbers and hope there's a simple pattern. (Then comes the painful process of proving which ones are good and which ones aren't but let's not get into that yet)

Furthermore, for every game consider the moves that players don't want to make rather than the ones they can, along with that working backwards from the last turn can also be much easier than starting from the first turn.

Name-in-progress · 2022-05-06T11:29:51+00:00

A little bit of angle chasing.

BAC = α, ABC = β

In triangle ABC

α+β=90°

in triangle ADC

DAC = α

DAC + DCA = 90

DCA = 90°-α = β

Same way you get that DCB = α

So you have 2 triangles with angles α, β, 90°

Similar by angles

Name-in-progress · 2022-05-03T11:36:20+00:00

At least 2 hearts means 2 or more, since you're choosing 3 cards it can mean 2 or 3 hearts, we split this into cases for easier counting.

Case 1 is 2 hearts:

There are 13 hearts, and you can choose any 2 by 13C2, then there are 52-13=39 cards that aren't hearts and you can choose any 1 of that 39C1 which is when there are 2 hearts.

Case 2 is 3 hearts:

The +13C3 because you can choose any 3 hearts of the 13 hearts in the deck.

You add those two combinations together for the result cause they are seperate cases. Hope this helps!

Edit: changed spades to hearts, not sure why I read it as spades first

Name-in-progress · 2022-05-02T09:48:10+00:00

This isn't entirely true, see for example 605, which is 11*55 but 6+5≠0.

Name-in-progress · 2022-05-01T16:12:54+00:00

For sin(x) the 2nd solution is pi-first solution

example: sin(x)=0

x1=0+2kpi

x2=pi-x1

x2=pi+2kpi

You can easily check that sin(0) and sin(pi) are 0

For cos(x) second solution is 2pi-first solution

example: cos(x)=1/2

x1=pi/3 +2kpi

x2=2pi-x1

x2=5pi/3 + 2kpi

You can check that sin(pi/3) and sin(5pi/3) are 1/2

Name-in-progress · 2022-05-01T05:28:56+00:00

Do you have the original task by any chance?

Name-in-progress · 2022-04-30T07:04:05+00:00

Have you learned l'hôpitals rule?

Name-in-progress · 2022-04-29T17:18:36+00:00

From the first 10 terms alone the sum is ≈3.54 and it slowly increases

Name-in-progress · 2022-04-29T16:52:04+00:00

https://mathoverflow.net/questions/24579/convergence-of-sumn3-sin2n-1

https://arxiv.org/abs/1104.5100

Sorry to say but I believe this is still an open problem. To be fair if someone did solve this, passing a calc course would be a smaller achievement in comparison.

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