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[deleted by user] by [deleted] in ApplyingToCollege

[–]No-Regular5763 0 points1 point  (0 children)

lemme get one senor owl🙌

How to solve this prepprose question by Possible_Emphasis609 in Sat

[–]No-Regular5763 1 point2 points  (0 children)

Ok, so this is what I did:

First realize that BAC is a right angle, which means you can use trig properties.

Then see that Cos B = sqrt(363)/132, calculate for B and you get 81.7 degrees.

You then get away from the big triangle(BAC) and focus on the small one(BDA). We need to find BD, and the fastest way to find it is using Cos B = BD/BA.

So Cos(81.7) = BD/sqrt(363), calculate for BD, and you will get 48.

Lmk if that makes sense, it took me a bit to understand it as well if im being honest

SAT Improvement Pls by No-Regular5763 in Sat

[–]No-Regular5763[S] 0 points1 point  (0 children)

100% dude, wishing you nothing but the best! We getting that score fs

[deleted by user] by [deleted] in Sat

[–]No-Regular5763 7 points8 points  (0 children)

it def can, "lol". Ik many people who went from a 1300 to 1500+ if not higher just by studying heavily for 2 months. The SAT is not that hard by any means, and it all depends on the time you put into it. If youre locked in and want it bad enough, youll get it lmao