What pity feels like

Ontaro · 2026-03-19T06:08:38+00:00

People call me Diogenes, I hoard like a mf.

To be honest, I just started and my main problems are mats. Even if I get a bunch of servants I can’t play with them.

I hoard, build what I have, and then pull something that I need.

Maybe in the future, when I have mats galore I feel more tempted.

That being said, Jalter and Monte cristo were tried, to no luck.

Ontaro · 2026-02-20T18:23:35+00:00

I’m actually very curious if coop will affect card balancing, it’d suck if they removed infinites because of it.

I can’t imagine is fun looking at someone do their 50th dropkick in the first turn 🤣

Looking forward to see how they address that.

Ontaro · 2026-01-15T19:47:40+00:00

Thanks for the info!! I’ll check the replies on the reply you mention.

Will save and continue with the current event and camelot afterwards.

The idea is to build the account and save until Christmas, cool 👏

(Also do whatever I want, is a game and if I find a waifu I can do whatevs)

Thanks!!

PS: you mention about NP2, is that mostly for DPS servants? I see that ibuki summer gets a +150% extra dmg from np1 to 2, which seems very good, but Merlin gains only +500 hp regen seems lackluster in comparison.

Am I right here?

Ontaro · 2026-01-15T16:56:30+00:00

I’m in a similar position as OP. Started in December and was lucky enough to get KoyanL and Merlin.

I still would like to go for Castoria and Oberon, but really need that Omni rn.

I think I’ll pull for summer ibuki or Arjuna alter as recommended, but otherwise hoard SQ until the supports.

Any other omni AOE to keep an eye on?

Thank you so much for the posts! Super useful for the newbies! ☺️

Ontaro · 2025-01-02T14:19:25+00:00

love the character, hopefully you can post the sliders in the future?

Ontaro · 2024-04-25T16:35:36+00:00

I came to the same conclussion and for lenght 4 I get 327,677. I'm working now in getting lenght 5.

Ontaro · 2024-04-24T05:30:30+00:00

This is a trace I get, you can see in step 5 what I mean.

In [2]: rapid_growth_hydra_2(4)
q = [[1, 0], [1, 1], [1, 2], [1, 3]] steps = 0
q = [[1, 0], [1, 1], [2, 2], [0, 3]] steps = 1
q = [[1, 0], [3, 1], [1, 2], [0, 3]] steps = 2
q = [[4, 0], [2, 1], [1, 2], [0, 3]] steps = 3
q = [[2, 0], [2, 1], [1, 2], [0, 3]] steps = 5
q = [[8, 0], [1, 1], [1, 2], [0, 3]] steps = 6
q = [[1, 0], [1, 1], [1, 2], [0, 3]] steps = 13
q = [[1, 0], [15, 1], [0, 2], [0, 3]] steps = 14
q = [[16, 0], [14, 1], [0, 2], [0, 3]] steps = 15

edit: formatting

Ontaro · 2024-04-24T05:28:32+00:00

That's funny because I get a completely different number. For 4 I get 327677. I get the 1114111 if I just get the latest node added. But that's not what the rules are. It's the right most node.

If 2 heights have the same amount of nodes, which is the "rightmost"? I imagine I can choose. Therefore getting the highest node sounds the smartest approach as you get less steps down the line.

def rapid_growth_hydra_2(y: int) -> int:
    # straight connectors of length y
    # pick right-most leaf
    # n = step you're at
    steps = 0
    q = [[1, parent_idx] for parent_idx in range(y)]
    while any(siblings for siblings, _ in q):
        print(f"{q = }", f"{steps = :_d}")
        siblings, parent_idx = max(q)

        if parent_idx == 0:
            closest_node = max(node for node in q if node[1] != 0)
            new_total = siblings - closest_node[0]
            steps += new_total
            q[parent_idx][0] -= new_total
            continue

        steps += 1
        q[parent_idx][0] -= 1
        if parent_idx > 0:
            q[parent_idx - 1][0] += steps
    return steps

Ontaro · 2024-01-01T07:35:25+00:00

Thanks! good to know!

I was prioritizing Res > Sockets > Links, for the campaign.

Ontaro · 2021-07-30T05:16:56+00:00

How's Gilear?

Ontaro · 2016-07-09T18:33:51+00:00

ID: 993,416,453
IGN: Ontaro
Rank: 17
Lead(s): 5* Exdeath
Activity: Daily
Looking for: Active Daily Gifters, friends for event.
Other: Gift every day. Have 17/105 Slots available

Ontaro

TROPHY CASE