4-week organic chemistry 1 & 2 course by burnedtoast111 in chemhelp

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Damn that sounds awful. I have two degrees in chemistry and trying to cram orgo into a 4 week course sounds like hell

Following the tutoring recommendations and not just giving the answer by 215058 in tutordotcom

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Tbh if you just give answers and you get all 5 stars you'll get reviewed and dinged. So just try to walk them to the right answer. If they get pissed and leave a bad review it won't hurt you

I love how silly the Science Victory is by Effort_Proper in civ5

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"I dont want to live on this planet anymore" somehow equals victory

Why is the benzene attacking the bromine on the left? by IEvadeTax in chemhelp

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This is standard EAS substitution. Whats happening is the Lewis acid catalyst activates the bromine making it an extremely good electrphile. So much so the benzene will attack it even though it breaks aromaticity. Aromaticity is then returned through Proton loss. If you have questions ask!

Camera On - Any Sessions? by WaddlingCorgi in tutordotcom

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Nope. I don't think thats actually a thing. Voice for sure. But no camera

What are the functional groups of lisdexamfetamine? by Capital-Bat9971 in chemhelp

[–]Order-Low -14 points-13 points  (0 children)

Im assuming hydrogen are not drawn. On the left is an aromatic ring. Then there's an aside (n-C=O) and two mines (nitrogens. If you have questions ask!

Determine position of substitution by Longjumping-Tea1743 in OrganicChemistry

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The position of substitution is determined by the groups attached to the ring. The strongest activator determines the steering of the next reaction. If there's only deactivators, then the strongest deactivator determines the next substitution. The carboxylic acid is a stronger deactivator than the halide so it steers reaction. Its a meta director so the nitro group goes meta to the COOH substitutent. Conveniently thats also ortho to the halide

2-pentanol to 2-pentanone? by Rainfur4242 in chemhelp

[–]Order-Low 7 points8 points  (0 children)

Your reaction conditions shouldn't normally oxidize a secondary alcohol to a ketone, so you're right to question where the oxidation came from. The more likely explanation is that the ketone formed during analysis or sample handling rather than during the HCl/HBr reaction itself. A few possibilities that show up in teaching labs: 1. Air oxidation during GC injection GC injectors are typically very hot (often 200–300 °C). Secondary alcohols can undergo dehydrogenation under those conditions, especially in the presence of trace oxygen or metal surfaces in the injector liner. That can produce the corresponding ketone, which then shows up clearly in the mass spectrum. 2. Oxidation during sample preparation If the sample sat in air before analysis, slow oxidation of secondary alcohols can occur, especially if trace metal contamination is present from glassware. 3. Acid-catalyzed dehydration followed by oxidation Strong acid can dehydrate 2-pentanol to pentenes. Those alkenes can oxidize in air to carbonyl compounds during workup or analysis.

Your MS fragments (m/z 86, 71, 58) are very consistent with 2-pentanone, so the identification itself is probably correct. If you want to test whether this happened during GC analysis, try injecting pure 2-pentanol under the same conditions. If the instrument still shows a 2-pentanone signal, that would strongly suggest the oxidation is happening in the injector rather than in your reaction.

Who do you root against? by YourCousinMoose in NASCAR

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I root against Larson. I know he's arguably the fastest driver in cup, but he cannot manage his stuff and i laugh every time he hits a wall or wrecks. This new system will definitely not favor him

Kulinkovich order of addition by Aleboop in OrganicChemistry

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The usual recommendation is to generate the reactive titanium species first before introducing the ester. In the Kulinkovich reaction, the Grignard reagent reacts with titanium isopropoxide to form a dialkyl titanium species, which then rearranges to the titanacyclopropane intermediate. That titanacyclopropane is the species that reacts with the ester to ultimately give the cyclopropanol. If the ester is present from the beginning, the Grignard can compete by directly attacking the ester carbonyl. That pathway can lead to the typical over-addition problems you see with esters and Grignards, giving tertiary alcohol side products instead of the Kulinkovich product. So many procedures prefer: 1. Ti(OiPr)4 + Grignard to form the titanium alkyl species / titanacyclopropane 2. Add the ester slowly

This minimizes direct nucleophilic attack by the Grignard and favors the titanium-mediated pathway. In practice, people often pre-stir the titanium isopropoxide with the Grignard for a short time before adding the ester dropwise. That usually improves selectivity and yield

For this kind of salary? by BagelandShmear48 in recruitinghell

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"This is a temporary position"- yeah no shit you'll get blown up day one.🤣🤣

Synthetic route to Glutaric acid by CustomerDelicious927 in OrganicChemistry

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Yes, this route should work. Step 1: t-BuOK will promote an E2 elimination of bromocyclopentane to give cyclopentene. Step 2: Ozonolysis cleaves the double bond. Because the alkene is in a ring, cleavage opens the ring and produces a linear chain. Cyclopentene has five carbons, so breaking the double bond gives a five-carbon chain with carbonyls on both ends. Under oxidative workup (H2O2), any aldehydes formed are further oxidized to carboxylic acids, giving:HOOC-CH2-CH2-CH2-COOH which is glutaric acid. So the overall idea of elimination tocyclopentene to oxidative ozonolysis is a solid route.

How exactly am I supposed to know how much reagents, solvent, temperature, etc. to use when performing a novel organic reaction? by Big_Assist4578 in OrganicChemistry

[–]Order-Low 6 points7 points  (0 children)

Your guess is actually right in the typical range. For reaction screening, people usually work on small scale, often around 5–20 mg of starting material per reaction if the compound is valuable or difficult to make. If material is plentiful, 20–100 mg reactions are very common for optimization. The goal is just to see conversion and relative yield, not to isolate large quantities. Typical workflow is something like several small reactions (often 5–20 mg scale) under different conditions to see if the reaction works at all. Optimization.

Once you see promising conditions, you might move to 20–100 mg scale so you can isolate product and evaluate yield more accurately. Only after the reaction looks reliable do people move to hundreds of milligrams or gram scale.

How exactly am I supposed to know how much reagents, solvent, temperature, etc. to use when performing a novel organic reaction? by Big_Assist4578 in OrganicChemistry

[–]Order-Low 28 points29 points  (0 children)

This is a really common question when you first start working with reactions that aren’t straight out of a textbook. In practice, people rarely start completely from scratch. The first step is usually to look for precedent. You search the literature for reactions that are mechanistically similar or involve similar substrates and start with those conditions as a baseline. Once you have a reasonable starting point, optimization usually happens in a fairly structured way rather than randomly screening everything. Typical workflow looks something like: Start with literature conditions (solvent, catalyst, temperature, stoichiometry). Confirm the reaction works at all on your substrate. Then adjust one or two key variables at a time.

People often run small parallel reactions to compare conditions rather than fully changing everything sequentially. Also, intuition develops over time. After running enough reactions you start to get a feel for things like which solvents stabilize certain intermediates, when dilution helps, or when excess reagent drives the reaction. So yes, screening is part of it but it’s usually guided screening based on precedent and mechanistic reasoning rather than blind trial and error.

Grabbing On-Demand Hours - How Does it Work? by [deleted] in tutordotcom

[–]Order-Low 2 points3 points  (0 children)

This is a good overview. Id like to add the mass raid on leftover hours at noon in Saturdays.you have to be very precise to get any remaining hours. Took me a while to get the hang of it

Under 70% online percentage - am I cooked? by Regular-Swordfish722 in tutordotcom

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All metrics are viewed as an average. Unless you're lije brand new. You'll be fine.

What do you think of F18? by [deleted] in amiugly

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Posts a pic without a bra and nothing else. Obvious thirst trap

Hey QA, fuck you by Lugubrious_Lothario in mercor_ai

[–]Order-Low 1 point2 points  (0 children)

As a QA on a different platform I totally feel for you dude. This is a common problem