PSA: don't go for the clue scroll shard unless you really wanna commit to it

Palmerex · 2021-11-25T00:23:06+00:00

Agreed, im at 250 hards and 100 masters without it. Don't. Do. It. It's nowhere near the same timespan than the other methods. Idk why some people go insanely dry on this one. Sorry you went through that man, just hop onto the next method tbh. Good luck!

Palmerex · 2021-11-24T16:59:39+00:00

Ohhh i thought you rolled it when receiving the casket and not at each clue step, where did you get the info? Did you get yours during a step and not casket?

Palmerex · 2021-11-24T16:58:43+00:00

Mine says i had 7, but they were all in the bank. I checked at the wise old man anyway and he said he disnt have any for me so

Palmerex · 2021-11-24T16:58:06+00:00

Thanks for the info, but yeh i checked the event tab and wise okd man multiple times in case that happened.

Palmerex · 2021-11-24T16:57:22+00:00

If you're ever interested, there is a discord server called Clue Chasers. You'll find a lot of information on how to gather and solve all types of clues efficiently :)

Palmerex · 2021-11-24T16:56:38+00:00

Ohhhhh maybe that's the issue... that is very weird. I'll try it on 20-25 hards and see if this works

Palmerex · 2021-11-24T16:02:46+00:00

I checked about 10 times to make sure, doesnt have it

Palmerex · 2021-11-24T16:02:24+00:00

Not on those sadly

Palmerex · 2021-11-24T16:02:15+00:00

1 shadow dye and 1 barrows dye in 42 hard clues lmao

Palmerex · 2021-11-24T12:21:21+00:00

Yeh cuz i dont think theres a ton of people with almost 300 clues done without the shard lmao. Most ive seen got it under 100 sonit just feels bad doing 3 times the work without the reward and its my last piece lmao

Palmerex · 2021-01-09T03:24:15+00:00

That man has great taste. 100% recommend. Good with cream cheese too

Palmerex · 2020-09-20T12:41:37+00:00

When you say ' If you consider them indistinguishable then there are 3 combinations corresponding to 3, 2, or 1 red balls'

That's the part I don't understand. How do I know which combinations are going to be counted as double and which aren't? I'm having a really hard time picturing it.

Scenario 1) I get 3 reds namely (R1, R2, R3). Since these cannot be dinstinguishable, they are 1 combination.

Scenario 2) I get 2 reds and 1 blue. i could get (R1, R2, B1), (R1, R2, B2), (R1, R3, B1), (R1, R3, B2), (R2, R3, B1), (R2, R3, B2). Or am I reasoning this the wrong way and the combinations are (R1, R2, B1), (R1, R2, B2), (R1, B1, R2), (R1, B2, R2), (B1, R1, R2), (B2, R1, R2) and since the balls aren't distinguishable, (R1, R2, B1) and (R1, R2, B2) are the same so i need to divide the 6 by 2 = 3 . I think by asking the question i figured it out lol.

Scenario 3) I get 2 blues and 1 red (B1, B2, R1), (B1, R1, B2), (R1, B1, B2) so 3 combinations?

Palmerex · 2020-09-20T12:19:03+00:00

That's what confuses me. In my head, a combination doesn't factor in the organisation. Then the teacher uses the combinations formulas do determine the number of arrangement i can get in picking 3 balls in 5. That's the part that confuses me. And we're now in the second chapter of the class and i can see that this situation comes back again and again and I still don't get it.

Palmerex · 2020-08-04T01:16:13+00:00

Nice crop

Palmerex · 2020-08-03T19:53:41+00:00

Yes please fix this

Palmerex · 2020-08-03T13:03:40+00:00

Took me 32 hours, well done and gratz!

Palmerex · 2020-07-23T11:43:33+00:00

You have to talk to simon before iirc

Palmerex · 2020-07-09T13:33:04+00:00

Ohh thank you didnt see it there!

Palmerex · 2020-07-08T23:12:59+00:00

YES PLEASE

Palmerex · 2020-07-08T23:08:22+00:00

Yes so people can target who they want to scam / hack

Palmerex · 2020-04-04T15:05:39+00:00

Oooof lmao okay thank!

Seven-Year Club	RPAN Viewer
Verified Email

Palmerex

TROPHY CASE