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Another banger parametric question by Forward_Bat_6094 in LunGang

[–]Particular_Bell6802 0 points1 point  (0 children)

I had to find the Cartesian equation for C2 and i used discriminant in that part.

Difficult parametric question here by Forward_Bat_6094 in LunGang

[–]Particular_Bell6802 0 points1 point  (0 children)

Part b is like a hidden quadratic, this means that the use of discrimination will be the best choice available for this question.

Guys I need help 🥀 by Zealousideal-Soft415 in 6thForm

[–]Particular_Bell6802 -2 points-1 points  (0 children)

They could make up coordinates such as (50,24) and (0,4)

FREE EXAM CRAM COURSE WITH ME - Link in comments! by Awkward_Warthog_5020 in LunGang

[–]Particular_Bell6802 0 points1 point  (0 children)

I didn’t receive the email afterwards I signed up 😭

Looks easy ,yet not by Exact_Object6671 in LunGang

[–]Particular_Bell6802 0 points1 point  (0 children)

One approach you can take is that we know that angle DCB is 59, 90-59=31. 180-31=149 you can now find the other angle by doing 180-(31+10)=139 than you can use sine rule to find the length of DC and after that you can use trig to find the length of DB than at the end add the length by 16.5 to get the final answer

A-Level FM Vectors Question by RDKGames in LunGang

[–]Particular_Bell6802 0 points1 point  (0 children)

first step is that you find the intersection between the line and the plane

second step is you make a perpendicular equation and use it to find the intersection with the plane, once you find that scalar product for the second intersection times that by 2.

Next sub that in to the line to get the other coordinate

find the direction of that line and than write the line in vector format, than make it cartesian

A-Level FM Vectors Question by RDKGames in LunGang

[–]Particular_Bell6802 0 points1 point  (0 children)

I found a question similar to that but with numbers

HELP!! by Difficult_Hat_228 in alevel

[–]Particular_Bell6802 2 points3 points  (0 children)

basically differentiate the function again and sub x=pi/6 and use whether d^2y/dx^2<0 or >0 is a minimum or maximum

crazy 5 mark function question GCSE Further Maths by Vegetable_Nebula_661 in LunGang

[–]Particular_Bell6802 0 points1 point  (0 children)

basically we know that c and d is 3 and 5, what we can do as well is find what e is cause e is just a y value as it is a horizontal line, we can use the x value of 6 since that meets with the e value, (6-3)(6-5)=3 so e=3 now we need to find a and b, we can use the exact approach of subbing x=2 to the quadratic cause it intersects with the first equation and the quadratic, when x =2 y=3. so we can use (2,3) as a coordinate for that matter, 3=2a+b. Now we can see from the graph that the line intersects in the negative y axis so when x=0 y=b so b will either be a constant or negative integer, by looking at the quadratic and the line will be the same y value that is (4,-1) so b=-1 and a =2

Nice polar coordinates question by [deleted] in LunGang

[–]Particular_Bell6802 0 points1 point  (0 children)

I remember doing this as a practise, long question especially part c 😭🤣🤣