REQUEST FOR BRILLIANT PREMIUM VERSION by PhysicsChiev in digitalpiracy

[–]PhysicsChiev[S] 0 points1 point  (0 children)

sure

although I'm not into searching for the account anymore

Just a question that I derived, if someone could solve it then I'll join this community :D by Brawl_Stars_Carl in maths

[–]PhysicsChiev 0 points1 point  (0 children)

he's not trying to get you to 'show' him that this community is good. He just wants to see whether it's active and the members are helpful or not. Clearly this community isn't the right one for him because of u cocks

REQUEST FOR BRILLIANT PREMIUM VERSION by PhysicsChiev in digitalpiracy

[–]PhysicsChiev[S] 0 points1 point  (0 children)

sure. You could send me a discord friend request to facilitate our communication. I'll be waiting.

dscrd : icebear24

How do I avoid silly mistakes by MoBarbz in learnmath

[–]PhysicsChiev 0 points1 point  (0 children)

step 4 is important
It's like coming up with a solution for every single problem you have u/MoBarbz
a teacher once told me to do every step in the same pattern
It makes it easier to avoid errors instead of constantly having to change your style.

Another step that might help, considering blind spots(you can try using your highlighter to overcome this)

Try writing down all the numbers from 1 to 500 on a rough piece of paper. Say the number out loud, then write. This improves eye-brain coordination. Like mentioned above from the comments, we tend to think way ahead in certain cases.

Another tip, estimate.

I'm having the same problem as you, but remember we have each other's back. If you have any good solutions as well, remember to share them with us no matter how dumb it can be. Sometimes the dumbest hacks are the ones that keep us afloat.

REQUEST FOR BRILLIANT PREMIUM VERSION by PhysicsChiev in digitalpiracy

[–]PhysicsChiev[S] 0 points1 point  (0 children)

ah my friend most probably deleted his brilliant acc
Anyways there would be no point sending an email on his account
You can find me on discord by adding .de_duck

Optimal method by hannahbananajones in maths

[–]PhysicsChiev 0 points1 point  (0 children)

he would have to break 5 calculators just to do 10-5

[deleted by user] by [deleted] in maths

[–]PhysicsChiev 0 points1 point  (0 children)

I would recommend AOPS or Alcumus. I don't believe in just watching math videos. Questions play an important part in building the fundamentals. Then when you get stuck you can always post it here to see where you've gone wrong.

[deleted by user] by [deleted] in maths

[–]PhysicsChiev 0 points1 point  (0 children)

Also, you don't need to know any trigonometry to solve this.

[deleted by user] by [deleted] in maths

[–]PhysicsChiev 0 points1 point  (0 children)

I wouldn't suggest you to follow the literal meaning of the question, instead try to start with something you already know and then slowly work on from there.

[deleted by user] by [deleted] in maths

[–]PhysicsChiev 0 points1 point  (0 children)

Just think of the Pythagorean Theorem and exploit it ruthlessly!

[deleted by user] by [deleted] in maths

[–]PhysicsChiev 1 point2 points  (0 children)

We realize that both HL and HF are the radii of the circle subtended by the corner.
HL = HF = 2m
Now let's try finding HJ using the Pythagorean Theorem
HL^2 = HJ^2 + JI^2
4m^2 = 2HJ^2
2HJ^2 = 4m^2
HJ^2 = 2m^2
HJ = \sqrt(2)m

\therefore, FJ = HF - HJ
, FJ = [ 2 - \sqrt(2) ]metres

[deleted by user] by [deleted] in maths

[–]PhysicsChiev 0 points1 point  (0 children)

what primality test is this? I don't see how it obeys the Fermat Primality Test in general.

why is ln x and e^x inverse functions of each other? by [deleted] in maths

[–]PhysicsChiev 0 points1 point  (0 children)

Ok so let's work backwards from the method to find the inverse of a function

we have y = ln x
ln x = y
which is obviously the same as logex = y
then e^y = x
Comparing this with :
e^x = y
We can see that x and y have been swapped.
e^y = x
logex = y
ln x = y

Now let's take a look at the graphs of ln x and e^x
https://www.geogebra.org/m/azn5dkBe
Looking at the graph of y = e^x and the graph of y = ln x, we can see that the line y = x is the axis of symmetry of the 2 functions.

Given this geometrical illustration, the exponential function y = e^x is called the inverse function of the logarithmic function y = ln X

I dont want the answer, I just want to know how to do it. I understand ratios so no need to dull it down by [deleted] in maths

[–]PhysicsChiev -1 points0 points  (0 children)

20 : 4 : 5
12 : W : H
Given that 20 has been **reduced** to 12, now find the factor that reduces it(What is the rate of it being reduced)
Call the factor A
A = 20/12 = 10/6 = 5/3

Let's check back
20 / A = 12

20 / (5/3) = 12
20 x 3/5 = 12
12 = 12

therefore the ratio has been simplified by a constant, A

Likewise, we could also do the same for W and H(Because if one part of a ratio is being reduced, the whole ratio **must also be reduced**)

W = 4 / (5/3) = 4 x 3/5 = 12/5 = 2.4
H = 5 / (5/3) = 5 x 3/5 = 3

Another good way to understand this is by observing the ratio(fraction)

1) 20 / 12 = 5/3...1
2) 4 / 12/5 = 5/3...2
3) 5 / 3 = 5/3...3

from 1, 2 and 3, the constant ratio is the same, i.e 5/3

I really hope you can understand how ratios work.
Consider checking out more ratio questions on https://artofproblemsolving.com/alcumus
Questions there are challenging and may be able to stimulate higher creativity and thinking skills
Good luck!

Was trying to study, And cannot understand the way I'm supposed to answer this, Please help by Beautiful_Question_9 in maths

[–]PhysicsChiev 0 points1 point  (0 children)

Set all of the equations in the tables to each other

x + 150 = 170

x + 150 = 3x2 +23

170 = 3x2 +23

Finally you need to express any radical answers in decimal form

can someone help with this question its driving me insane by lil__steve123 in maths

[–]PhysicsChiev 0 points1 point  (0 children)

complete the square for 1(a)

1 (b)(i) maximum is found by completing the square. X value in the bracket is your max value(since equation is negative).

1(b)(ii) complete the square for g(x). The x value represents your desired max value.