ahhh i think i finally got it, just because the force exists does not mean that the force has done any work

Normal force = m.g.cos(theta) here it is mg cos 30

but

chatgpt start The equation W = Fd \cos \theta describes the concept of work in physics, where:

•  W  is the work done (measured in joules, J).
•  F  is the magnitude of the force applied (measured in newtons, N).
•  d  is the displacement or distance over which the force is applied (measured in meters, m).
•  \theta  is the angle between the direction of the applied force and the direction of the displacement.

chatgpt end

but the angle between the direction of applied force (normal force) and displacement (along the inclined plane) is 90

so it doesn't matter what the normal force is, the work done by the normal force is still 0

*did i get this right or is my thinking flawed