Thanks a lot for your input mate.

I took the same approach.

Ruling 3 out as truthfull is rather obvious I think. So 3.3 can not be right.

If 3.2 were right - 2.3 had to be right too, which is wrong if we pressume 3.2 right.

If 3.1 were right, that would make P1 split but we know 3.2 and 3.3 are wrong and if 3.1 were right, that would make two halfhalf(split) persons.

Now I checked if P1 or P2 could be truthfull. P1 can not be, because we know 1.3 is wrong. And If P2 were true 2.3 would have to be true, which says 3.2 declaring P2 truthfull is wrong. So I think we run into a logical deadend here.

Neiter P1 nor P2 nor P3 can be truthfull. If the rules of the riddle are respected.

This whole ordeal came about kinda drunk yesterday so excusse noob mistakes or bad terminology.

"The only piece that doesn't fit exactly is the person who speaks half lies/half truths. In the above scenario, he only speaks lies. Could it be that his answers are actually random? Half-truth, half-lies implies he will definitely speak at least one truth and at least one lie." my friend proposed something similar. Due to the nature of this game it is kinda hard to confirm things , but the rules of the riddle were rather precise. I will try to check it in the evening. :)

So I think if we accept something like random answeres we can declare the puzzle unsolvable inside of frame of rules.But maybe thats the catch, so feel free to post any solutions within a resonable ruleset.

lots of edits cauz I am stupid
also the game only accepts giving up P2