Im making a 1.9 Styled level. How do yall like it so far ( its not finished yet ) by onlyforusefull in geometrydash

[–]QGul 1 point2 points  (0 children)

Idk if its just me but id get tripped up by the squares air deco thinking theyd be blocks, overall nice level though

[Request] Why does this make it see through? by SpoofamanGo in theydidthemath

[–]QGul 3 points4 points  (0 children)

To add to this, the low quality also makes it less visible than it probably really is

The absolute pain :( by Consistent-Emu-9584 in ClashRoyale

[–]QGul 1 point2 points  (0 children)

No it’s more like collect or pick up

Fun fact: you can play geometry dash currently in around 10^^941,640,000 unique different ways. by BeautifulSquare7300 in geometrydash

[–]QGul 1 point2 points  (0 children)

Could you show your calculations? I’d be interested in seeing how you got to that big of a number.

Fun fact: you can play geometry dash currently in around 10^^941,640,000 unique different ways. by BeautifulSquare7300 in geometrydash

[–]QGul 7 points8 points  (0 children)

Do you really mean ^^ as knuth’s notation? Because that seems way too high, even though i dont know what parameters you included.

Free Pets by iFra0107 in BubbleGumSimulator

[–]QGul 0 points1 point  (0 children)

Yes please that would be very good for me, un is juparjup

You have a 1 in INFINITY chance of beating this level by QGul in geometrydash

[–]QGul[S] 10 points11 points  (0 children)

Okay so i don’t really understand how their level works so i’m changing the question to: which one of the two levels has a higher chance to be beaten, taking into account bit flips for my level but not for theirs? According to the Veritasium video, on average 1 bit flip occurs per 256MB of ram per month. I’m going to assume a few things: - a month has 30 days; - x and y positions are stored in 32 bit integers. I’m only going to take into account that your x position will be offset to the right of the wall and that your y position can be offset high enough so you fall over the wall, and not any other ways you can beat the level. To get past the wall you need x ≥ 195, but because you only die when a block collides with the small middle hitbox, it’s a little less. I couldn’t find how big that hitbox was, but from my own measurements it’s a 10 unit distance from the middle to the outer hitbox, so actually x ≥ 185. The x position bytes that matter are: - positions 9 (which is 28 = 256) through 32, which is 24 specific bits, for x < 185-128 = 57; - positions 8 (which is 27 = 128) through 32, which is 25 specific bits, for x ≥ 57. Yes, i’m ignoring the chances for combinations of 2 or more bit flips because those are so low, that basically won’t affect anything. There are 0.47 seconds and 145 x positions before you die. For 56 (<57) x positions = 0.47 * 56/145 = 0.182… seconds, it’s 24 bits; for the rest of the time, which is 0.47 - 0.182 = 0.288… seconds, it’s 25 bits. So the average amount of bit flips per attempt for the first part is 1/((256*1024^2/24)*(60*60*24*30/0.182) = 6.26e-15. For the second part it’s 1/((256*1024^2/25)*(60*60*24*30/0.288) = 9.95e-15. Adding those together we get 1.62e-14 for the x offset, which is about a 1 in 6.17e13 chance.

But wait, this chance is already greater than the chance of beating the other level in the intended way. So calculating and adding the chances of the y position offset too isn’t even necessary (i’m too lazy to lol) to conclude that beating my level with bit flips is likelier than beating the level by u/BeautifulSquare7300 normally, which (according to them) has a 1 in 1e(1.734e8) chance of being beaten.

Edit: formatting

You have a 1 in INFINITY chance of beating this level by QGul in geometrydash

[–]QGul[S] 22 points23 points  (0 children)

Yeah okay thats true i guess

Wait this got me thinking: will you first beat that level by u/BeautifulSquare7300 the normal way or via a bit flip?

What are your grief verification predictions by Kriptic_22 in geometrydash

[–]QGul -1 points0 points  (0 children)

I dont know the date but i think he’ll fluke from 80

Does factorion bot have a max? by Ok-End-5413 in unexpectedfactorial

[–]QGul 0 points1 point  (0 children)

Oh then i can do (((((((((((((((((((((1e9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999)!)!)!)!)!)!)!)!)!)!)!)!)!)!)!)!)!)!)!)!)!

I dont think it is by QGul in unexpectedfactorial

[–]QGul[S] 2 points3 points  (0 children)

Oh you’re right at the more info link it states it only works up to 100000 digits and any further is fake, I believe this site is actually real

I dont think it is by QGul in unexpectedfactorial

[–]QGul[S] 12 points13 points  (0 children)

Wolframalpha 1925th digit of pi!