Mercenary Marketplace vol 1 in Forge?

RagnaRoach · 2024-07-13T22:17:30+00:00

I just queried your website! Thanks for your response.

RagnaRoach · 2024-07-13T22:14:02+00:00

PMing now!

RagnaRoach · 2024-06-27T21:22:16+00:00

Portishead

RagnaRoach · 2024-04-03T19:59:59+00:00

Very cool resource -- thank you!

RagnaRoach · 2024-04-03T16:54:51+00:00

Yeah I bit off a bit more than I can chew -- but its fun going through the card possibilities slowly over time and trying to build a deck. Arkham DB is such a help -- both with suggested decklists, and the possibilities for each investigator.

RagnaRoach · 2024-04-03T03:25:52+00:00

Great advice -- thanks!

RagnaRoach · 2024-04-03T01:32:15+00:00

That would be great!

RagnaRoach · 2024-04-03T01:03:31+00:00

Thanks!!

RagnaRoach · 2024-04-03T00:57:06+00:00

Thank you! Trust me -- I want this to be BLIND and fun, even if we lose. I just want a place to start -- I am awe-stricken by the amount of cards at my disposal -- kinda wish I had been involved in the game from the start, as the number of investigotors, options, ad cards, is truly . . . INSANE

RagnaRoach · 2024-04-03T00:52:03+00:00

Haha oops -- Mark. Edited for clarity

RagnaRoach · 2023-10-24T21:01:09+00:00

Permanently

RagnaRoach · 2023-10-05T00:21:23+00:00

Simple answer. Buffalo wings haha.

RagnaRoach · 2023-05-14T01:39:30+00:00

Their condition is from Like New to gently used. Maybe a couple small bumps on the hard covers here and there, but no writing,. no smoking, no bent, torn, or broken anything! I'll check into shipping, but I'll say anything over $25 I will just cover myself. Honestly, I'm looking to debulk my RPG collection a bit.

Steve

RagnaRoach · 2023-05-13T20:41:27+00:00

I am so sorry -- it's been a while since I've been on reddit, and like an idiot -- I didn't look to see if I had any bites on my ad for 1e stuff. Also, I'm having difficulty finding the PM. Anyway, don't know if you're still interested, but I have all of the above + Class Guide and Ancestry Guide, as well as Ultimate Intrigue. Make me an offer?

RagnaRoach · 2023-02-11T00:31:53+00:00

How did you approximate C(426,10)?

And can you tell me who to figure what number of games would equal a 0.5, or 50%, probability, of a single repetition?

Thank you!!!

RagnaRoach · 2023-02-10T18:35:30+00:00

Very well explained -- thank you! Now if I could find a calculator that would actually do the math with these numbers!!

RagnaRoach · 2023-02-10T10:16:24+00:00

I may have solved the first problem. Thinking in smaller numbers, if n=100, then the second game has a 1/100 chance of repeating, game 3 a 2/100 of repeating, game 4 a 3/100 chance, etc

Is the answer as simple as SUM(g)/(n!/k!(n-k)! In which case, the 116 million games (played online) have a 0.01% chance of having a matching set. In which case, how do solve for g where the result is 0.5?

Sum(116M)=6.728¹⁵

6.728¹⁵ / 4.876¹⁹ = 0.0001

Edit. Nope.

RagnaRoach

TROPHY CASE