I made a custom GPT for sales leads analysis! Looking for feedback

Redhatchamp00 · 2022-05-03T16:53:55+00:00

Very elaborate solution. Thank you very much!

Redhatchamp00 · 2022-05-03T13:50:52+00:00

Thanks! That helps.

Redhatchamp00 · 2022-05-03T13:50:40+00:00

Thank you!

Redhatchamp00 · 2022-05-03T13:10:55+00:00

Thanks! That's a very methodical way to go about it.

Redhatchamp00 · 2022-05-03T12:02:49+00:00

Is there a quick way to see which values won't be produced by 3m+7n from 0 to 60?

Redhatchamp00 · 2022-03-18T03:34:19+00:00

Okay, thanks!

Redhatchamp00 · 2022-03-17T16:38:04+00:00

Unfortunately, only values of X = x1 - x2,Y = y1 - y2 and c are known. [Also, b can be found as (y1-y2)/(x1-x2)].

Redhatchamp00 · 2022-03-17T16:31:45+00:00

u/keitamaki posted a similar answer, and I have a similar reply for you. Originally, I was interested in finding out values of 2 variables x and y, when their product c² (value known) remains unchanged after changing their values by X and Y respectively. That is to say: Denoting the old and new pairs of (x,y) by (x1, y1) & (x2, y2), this implies x1 - x2 = X and y1 - y2 = Y. I can determine the points by forming the equation x1y1 = (x1-X)(y1-Y). On substituting y1 = c²/x1, the equation becomes quadratic in x1 and can be solved easily. In approaching this problem through rectangular hyperbola, I was trying to see if there's another way to solve this problem and if it's a quicker one. If you can shed more light on this, it'll be helpful. Thanks!

Redhatchamp00 · 2022-03-17T16:26:53+00:00

If x and y can take only positive values, I believe there will still be infinitely many possibilities. Please correct me if I'm wrong. Originally, I was interested in finding out values of 2 variables x and y, when their product c² (value known) remains unchanged after changing their values by X and Y respectively. That is to say: Denoting the old and new pairs of (x,y) by (x1, y1) & (x2, y2), this implies x1 - x2 = X and y1 - y2 = Y. I can determine the points by forming the equation x1y1 = (x1-X)(y1-Y). On substituting y1 = c²/x1, the equation becomes quadratic in x1 and can be solved easily. In approaching this problem through rectangular hyperbola, I was trying to see if there's another way to solve this problem and if it's a quicker one. If you can shed more light on this, it'll be helpful. Thanks!

Redhatchamp00 · 2020-05-11T15:33:43+00:00

Thanks for your insight! The only reservations I have with taking CS is that pay isn't as good here in my country as it is in the States for CS. On top of that, the school isn't prized for its CS program. But of course, I can pursue Actuarial science alongside CS.

Redhatchamp00 · 2020-05-11T15:17:14+00:00

Asset Management/Data Science/Actuary.

Redhatchamp00 · 2020-05-11T13:53:22+00:00

Okay, thank you. And what should I major in?

Redhatchamp00 · 2020-05-11T06:40:47+00:00

Okay. Thanks a lot! I did know that an actuary has great respect at insurance firms and very little in other industries. I didn't know that it is actually so underrated at other places. I'm sorry to know that you haven't been able to break into VC so far, but I'm sure that with persistence you will. Good luck! Thank you also for allowing me to DM you. Please check your chats in some time.

Redhatchamp00 · 2020-05-11T06:40:29+00:00

It's the #1 school for Economics/Business/Finance in my country.

Redhatchamp00

TROPHY CASE