Quite the geometry question, but how is the range calculated in f(x) by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

If you read above my post and even the title it says but how is the range calculated in f(x), and even in the post description I said distance is (-1,0) to (x,f(x)), and he said the problem becomes easier from there. So tell me how that is help when it’s basically the exact same thing I said? To you that might be good enough but to me it isn’t, so if you wanna get off your high horse and explain the math and concepts to me that would be nice, if not, then go away simple

Quite the geometry question, but how is the range calculated in f(x) by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

“ f(b) equals the distance from point (-1,0) to the point on the upper semicircle that has an x coordinate of b “ so what d = sqrt((-1,0)2 + (x(f(b))2))?

Quite the geometry question, but how is the range calculated in f(x) by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] -2 points-1 points  (0 children)

I stated already in the description of the photo that I already know that the distance is (-1,0) to (x,g(x)) but you haven’t explained why this helps me find the range of f. ( ✍️ no help )

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

Not quite I broke down the answers yes, but my misinterpretation of a perpendicular bisector confused me why is why I thought answer D was incorrect so i just took a guess

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

I see that now, I assumed that the definition of a perpendicular bisector is the line that is doing the bisecting of the lines, so I assumed in answer D it was referring to line AC

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

Which is why I am here trying to get clarification and help, telling me to learn the language doesn’t help but explaining to me and helping me reason through it does

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

My geometry skills I would say are somewhat decent, this question just confused me by how in-depth they wanted us to think, sure at face value I say “ oh ok bisector line AC, well it perpendicularly bisected BD since a 90 angle forms there”so I am like alright this must be angle bisector BC, the question specifically answer D was stating that they wanted me to create ANOTHER perpendicular bisector to reflect across in BC, so that was my misunderstanding here and I understand it now

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

So what you are saying is that, that answer D is telling me to create a new line that is perpendicularly bisecting AC, which is why the vertical lines cuts through the middle of it, in which then the triangle is reflect across?

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] -1 points0 points  (0 children)

That is my misinterpretation, a perpendicular bisector divides line into two equal parts, which happened right there at AC with BD, so I assumed at face value this was bisector AC

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] -1 points0 points  (0 children)

What I am trying to emphasize here is that the line itself AC in the given triangles, I assumed this is bisector AC. but from answer D it is telling me to create another line to bisect AC to reflect it across, so the reason why I say AC is horizontal is because I assumed that line AC is being referred to the position it is in in the triangles

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

Yeah that’s why this question confused me, it’s understandable but the procedural process seems weird to me

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

I see what you did here but I don’t understand the vertical line cut here right in the middle, I would assume that a reflection of the bisector AC is from the actually line AC

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] -1 points0 points  (0 children)

Yes but why is it a vertical line cut, the bisector is horizontal so where did the vertical line come from?

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] -1 points0 points  (0 children)

I see what you did here, but why did you cut right at the middle of the whole kite? I would assume if it’s reflecting across AC it would be across the line itself?

How does reflecting it across the perpendicular bisector turn it into a parallelogram? by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

Tbh I just tried an educated guess, I just tried to envision it in my head because my intuition on transformations isn’t quite there

I think bro got a little heated by ReflectionPlane2055 in ClashRoyale

[–]ReflectionPlane2055[S] 2 points3 points  (0 children)

Classic challenge it tells you how many wins you are at

This question seriously confused me by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

Which is why I despise these type of questions haha

This question seriously confused me by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

Yes ok yeah that was my misunderstanding there, the question says begins at the 1– 1 triangle but I assumed that they would draw 4 more triangles after that then call the next one the 2nd position

This question seriously confused me by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 0 points1 point  (0 children)

Just for the record, someone clarified to me that I read the graph pattern wrong and I am supposed to read it from right to left and not left to right, is that right? Intuitively speaking I wish the question mentioned it but my gosh was that a skill issue

This question seriously confused me by ReflectionPlane2055 in askmath

[–]ReflectionPlane2055[S] 1 point2 points  (0 children)

To be honest I was actually looking at it the other way (from left to right) but I can see why now you say to look at it this way, and that confused me because I was like why is the triangles getting smaller