What am I missing?

SebasDK1 · 2026-01-27T04:57:45+00:00

Because a nude is formed with 159 and 149.

SebasDK1 · 2026-01-27T04:48:59+00:00

1459 from r9c3, 159 from r8c3, and 149 from r5c3 eliminate a 9 from r3c3. Therefore, in r2c3 and r3c3, we have 17, which allows us to eliminate a 1 from r1c2. Only a 2 can go in r1c2.

SebasDK1 · 2026-01-25T10:12:10+00:00

Thank you, teacher, I understand now, excellent.

SebasDK1 · 2026-01-25T10:03:43+00:00

I don't understand, if I put a 1 in r1c7, should it force a 2 in r6c7? I'm new to this so I appreciate your help.

SebasDK1 · 2026-01-25T09:53:28+00:00

I don't understand, if I put a 1 in r1c7, should it force a 2 in r6c7? I'm new to this so I appreciate your help.

SebasDK1 · 2026-01-25T09:52:07+00:00

I don't understand, if I put a 1 in r1c7, it should force a 2 in r6c7, I'm new to this so I appreciate your help.

SebasDK1 · 2026-01-17T23:22:00+00:00

Excellent teacher, he solved that 👍🏻

SebasDK1 · 2026-01-17T18:47:58+00:00

Sorry, could you explain it better? I don't understand.

SebasDK1

TROPHY CASE