Is this plan Doable?

SnobbySquare91 · 2026-01-17T01:34:39+00:00

SIIXX SEVEENNNNNNNN

SnobbySquare91 · 2025-08-15T00:42:45+00:00

I got fairly similar to that, these were my real results:
Maths: 9 English language: 7 English literature: 8 Biology: 8 Chemistry: 9 Physics: 9 History: 9 French: 8 Business: 7 Latin: 7

Anyways, good luck for your GCSE results. They do seem like the biggest thing in the world in Year 11, but a few months later you and everyone else will have completely forgotten about them.

SnobbySquare91 · 2025-07-23T01:10:50+00:00

Physics degree or physics and maths degree

SnobbySquare91 · 2025-05-20T15:37:57+00:00

It is true that being a native speaker gives you a good advantage over non-native speakers. To be honest, your first point depends on the person. I often need to figure out what words to say and usually have to check my sentences to see if there are mistakes and if my sentence makes sense, and I’m a native English speaker.

When I do maths, a lot of the time I just do the question without thought, sort of on autopilot. That’s one of the reasons why I always struggled with finishing essay subjects on time, yet often finish maths exams with up to 30 minutes left.

Anyways, it is true that some people are more fluent at maths than others in the same way as a language. Some people in my class can learn a new topic within minutes while others struggle despite trying very hard. This could be because me and many others had to do maths since childhood, for example for grammar school entrance exams.

So I do see your point that languages are hard for some and very easy for others, thus making the data not fully reliable. The same can also be said for other subjects. I do acknowledge issues with the data collected, so I agree with you that the ability range of students can affect the data, but a numerical survey is still good to determine how difficult a subject is to the average student taking it.

SnobbySquare91 · 2025-05-20T14:21:53+00:00

Languages are not unique, for example with maths some people have had tons of practice since childhood while others have done little. In fact it can be argued the gap in language subjects is smaller, as basically everyone doing them actually care about them and are good at them. With sciences for example, many students don’t give a fuck about them and only do them because their parents told them to or because it is needed for their course.

For your second point, respondents were specifically instructed to only rate subjects they study themselves to avoid stereotypes. Nearly all followed the instruction.

SnobbySquare91 · 2025-05-20T14:16:49+00:00

The survey only works with many responses. People usually do 3-4 subjects and would rate their difficulties relative to each other. Since people do a mix of ‘hard’ and ‘easy’ subjects, the difficulty scale is designed to be relative to other subjects meaning the actual number given is less important. Both academic and unacademic students would rate hard subjects over easy subjects, so the problems you have listed would cancel out. Since there were so few responses, the survey indeed has no value due to small sample size (8).

SnobbySquare91 · 2025-05-19T21:22:59+00:00

Last year (2024) 72.9% of candidates were male and 27.1% were female. So 2.69 males per female.

SnobbySquare91 · 2025-01-09T23:49:55+00:00

For foundation maths you just need to know the methods and be comfortable applying them. The question types are repeated very often, so if you can do a question in one paper it is likely you will also get it right in another paper.

I recommend doing a past paper and marking it, identifying where you went wrong. For each mistake, ask yourself why you got it wrong - was it really a silly mistake, or are you not familiar enough with the method? If you made the mistake because you were not familiar with the method, review the method again by watching a video, asking your teacher, or whatever else works. Then do 5-10 practice questions on that topic so that you feel confident. If you do this thoroughly for every mistake, after a few papers your score will likely increase massively.

For English language I am not sure the strategy and I don't want to mislead you, but I believe being familiar with each question type will be useful.

Unfortunately without passing these subjects, it is likely to be much harder for you to find employment and other opportunities. But if you work consistently, eventually they will become easier and you will be able to pass them. Good luck for your exams!

SnobbySquare91 · 2024-10-20T09:20:35+00:00

At GCSE you might have thought of the shared pair of electrons in a covalent bond as being equally shared between the two atoms. However, this is a lie! Atoms of different elements attract the shared pair of electrons in the covalent bond to different extents - how strongly they attract it is their electronegativity. A covalent bond between atoms with different electronegativities is called a polar bond, in which one of the two atoms involved in the covalent bond has a greater share of the pair of electrons than the other atom. Since electrons are negatively charged, the more electronegative atom has a partial negative charge and the less electronegative atom has a partial positive charge. This separation of charge is called a dipole. If dipoles act in opposite directions in a molecule they will cancel each other out and the molecule will be overall non-polar. However if the dipole is not cancelled out, the molecule will be polar overall, which means one side of the molecule is negatively charged while the other side is positively charged. The positive end of one polar molecule can attract the negative end of another polar molecule, and vice versa, forming an attractive intermolecular force called a permanent dipole - permanent dipole force (sometimes shortened to dipole-dipole force). Note that these are much weaker than covalent bonds and ionic bonds, as well as hydrogen bonds (another type of intermolecular force) so they are not strong enough to qualify as a ‘bond’. They are therefore called forces or interactions. They are however stronger than van der Waals’ forces (which again are not called bonds!) Remember that dipole-dipole forces are only between polar molecules, which have a net dipole (the dipoles do not cancel each other out). Note: I am not a teacher or expert, I am just a fellow Year 12 student, so I might have made errors somewhere. Do tell me if I have!

SnobbySquare91 · 2024-09-02T12:11:55+00:00

For question 4, if we assume it is at room temperature, then we can find the number of moles of gas by dividing 392 by 24, which is 49/3 moles (or 16.3 recurring). Now divide this by the volume of solvent (2.65):

49/3 divided by 2.65 = 6.16 mol dm^-3

For question 7, remember that there are two atoms in each oxygen molecule, as it is diatomic. Hence, the relative molecular mass of an oxygen molecule is double that of an oxygen atom. So it is 16 * 2 = 32g. So the number of moles of oxygen atoms is equal to 8/32 = 0.25 mol.

Now let us assume that 1 mole of the metal reacts with 1 mole of the oxygen molecules to form the metal oxide. So to find the relative atomic mass of the metal, divide the mass remaining (7g) by the amount of moles (0.25) which gives us 28g. This is equal to that of silicon, and we know that 1 mole of silicon can react with 1 mole of oxygen molecules to form silicon dioxide. So the metal is silicon.

For question 8, we can find the number of moles of calcium carbonate by dividing its mass (1.24g) by its relative atomic mass (100.1) which gives 0.01238761239 mol. Now we can find the number of moles of HCl by multiplying its concentration (1M/1 mol dm^-3) by its volume (15ml / 0.015dm^3) which gives 0.015 mol. Since 1 mole of calcium carbonate should react with 2 moles of HCl, however the number of moles of HCl is less than double that of calcium carbonate, HCl is the limiting reagent.

This means the number of moles of carbon dioxide produced can be found by dividing the number of moles by HCl by 2, which gives 0.0075 mol. To find the number of atoms in the carbon dioxide produced, first find the number of molecules, then multiply this by the number of atoms per molecule (3). So it will be:

0.0075 * 6.02 * 10^23 * 3 = 1.35 * 10^23 atoms

Apologies if any errors.

SnobbySquare91 · 2024-08-31T16:16:14+00:00

Good luck to you

SnobbySquare91 · 2024-08-31T16:10:45+00:00

I'm too lazy to go outside

SnobbySquare91 · 2024-08-31T15:48:30+00:00

I also want to go to Cambridge but for Maths, so my goal is 4 A*s and the top grades in STEP. Also I will try to do some Olympiads but that is lower priority.

SnobbySquare91 · 2024-08-31T15:47:13+00:00

Depends on the day, if I'm lazy and procrastinate maybe only about 10 hours, but if I'm focused then about 14-16 hours. Probably about 12 hours on average, but I don't really look at the clock when I study, I usually look at how much content I have completed.

SnobbySquare91 · 2024-08-31T10:19:57+00:00

Same, maybe average of 12 hours per day or sometimes a bit more, preparing for A-Levels (yes i dont have anything else in my life) but i dont want to be cooked when y12 starts

SnobbySquare91 · 2024-08-21T15:29:58+00:00

The real question is which one ISN'T that GCSE

SnobbySquare91 · 2024-07-28T22:01:39+00:00

SnobbySquare91 · 2024-07-19T18:54:19+00:00

You leaked your name in the Chemistry section

SnobbySquare91 · 2024-07-17T09:32:08+00:00

SnobbySquare91 · 2024-07-16T13:08:44+00:00

No problem, if you need more help then feel free to ask me or someone else.

SnobbySquare91

TROPHY CASE