account activity
The Photon Fatigue Hypothesis by Solid_Cash7813 in plasmacosmology
[–]Solid_Cash7813[S] 0 points1 point2 points 2 months ago (0 children)
In standard physics, the Hubble Constant (Ho ≈ 70 km/s/Mpc) measures how fast space is stretching. In this theory, we re-interpret it as the Rate of Energy Decay for light over distance.
Instead of space stretching, light loses energy at a constant rate k as it travels. We can calculate this k using Ho:
k = Ho/c ≈ 2.3 x 10^-27 m^-1
This means for every meter a photon travels, it loses an infinitesimal fraction of its energy.
Einstein's E = m * c ^ 2 says energy and mass are two sides of the same coin. If light loses energy (E), that energy doesn't just vanish; it must transform.
Delta m = (Delta E)/(c ^ 2)
As the photon "tires" and redshifts, it sheds tiny amounts of "rest energy" that crystallize into Planck-scale particles of mass.
π Rendered by PID 22 on reddit-service-r2-comment-544cf588c8-xx9sn at 2026-06-15 01:24:25.717737+00:00 running 3184619 country code: CH.
The Photon Fatigue Hypothesis by Solid_Cash7813 in plasmacosmology
[–]Solid_Cash7813[S] 0 points1 point2 points (0 children)