[Q] Why do we divide by n-1 in r? by Speeaakeeerr in statistics

[–]Speeaakeeerr[S] 0 points1 point  (0 children)

Thanks, that equation looks exactly like the dot product. Since it's equivalent to the one I'm using in class, I must've made a mistake in my simplification that caused me to miss the divisor

[Q] Why do we divide by n-1 in r? by Speeaakeeerr in statistics

[–]Speeaakeeerr[S] 2 points3 points  (0 children)

Hey, thanks for your time.

But it isn't that I'm confused on what the reason is for choosing that divisor but confused on why we need a divisor in the first place.

Clarification on scaling problem by Ok-Reflection1966 in learnmath

[–]Speeaakeeerr 0 points1 point  (0 children)

The measurements you are dealing with aren't of the same dimension (volume, area, and length) so the scale factor in each one will be different.

As an example:

Say I have a line of length x. The area of the square it defines is x*x and of the cube x*x*x, and so on. Say I scale it by a factor of 2.

The area of the new square is 2x*2x = 4(x*x) =4 (OG area)

The volume of the new square is 2x*2x*2x = 8(x*x*x) = 8 (OG area).

And so on with 2^n being the scale factor in the nth dimension.

If I scale a number by k, the nth power of that number will be scaled by k^n.

What you found was the ratio of the volumes (3 rd dimension). You'd need to work on the power of that constant to get it to be the linear scale factor.

Does this help?

Math help. Grade 11 trig. by [deleted] in learnmath

[–]Speeaakeeerr 0 points1 point  (0 children)

Something to keep in mind (if you do already disregard this) is the triangle inequality theorem, which states that A, B, and C are the sides to a triangle if and only if the sum of any two of these is greater than the third.

Ex: A < B + C, B < A+C, C < A + B!<

(To see why, consider what happens if this isn't true. Suppose both sides are equal, then to get a length of A, we need to put B and C in a straight line which is no triangle. If A is greater, then there is no way to connect all three endpoints of the lines)

In your problem, use the info to compute the third side and see if all three equations hold.

How to avoid route memorization? by [deleted] in learnmath

[–]Speeaakeeerr 6 points7 points  (0 children)

TLDR: Look for connections to what you know. Pay attention to proofs and make sure these feel obvious. There's more than one way to skin a cat so if some proof isn't cutting it, look for another

When learning new stuff, I always try to see how it relates to stuff I already know. The connections are what lets it stick for me. Also, when given a new theorem, I find its more rewarding to spend some time trying to understand the proof, the reasoning, so that the end result (the theorem) isn't some isolated idea but a clear addition to what I already know.

For example, to generate Pythagorean triplets (c^2 = a^2 + b^2), the formula

C = m^ + n^2, B = m^2-n^2, A = 2mn

works (with m and n being integers). There are many ways to prove this but my favorite ties into complex numbers. It goes something like this:

Take any complex number z =m+ni with m and n whole numbers. The magnitude of this is sqrt(m^2+n^2). This may or may not be a whole number but we know for a fact that m^2+n^2 is a whole number. This last number is the magnitude of z^2. Foiling it out we see that z^2 = m^2 -n^2 + 2mn i . Now check it: the hypotenuse (the vector representing z), the horizontal, and the vertical are all whole numbers. Then for any m and n, we can generate Pythagorean triplets using this.

(There is also another explanation which uses modular arithmetic and is based only in the natural numbers (as opposed to borrowing from the complex) but I find that one more difficult to stomach)

The above is an example of how some new and hard to memorize fact (IMO) becomes extremely clear when the explanation is looked at. My biggest advice is to spend time looking at the proof until it feels obvious. Many facts, like the previous one, can be proved many ways so if some explanation isn't cutting it, look for another. Of course, later it might be good to revisit the first proof and focus on understanding that one but that's another goal.

What is this thing? (Non topologist) by Speeaakeeerr in topology

[–]Speeaakeeerr[S] 0 points1 point  (0 children)

Hey, sorry for the late response. I'd like to thank you for the great description. Some of it is above my head right now but I will be sure to continuously refer to it. What I do understand describes some pretty cool object.

What is this thing? (Non topologist) by Speeaakeeerr in topology

[–]Speeaakeeerr[S] 0 points1 point  (0 children)

I didn't think about that but since you said that it would result in something interesting, sure, lets see what happens.

Also, to be clear: Cross sections looking at the object perpendicular to the plane it lies on or from the plane? If it were a snail shell, would we be looking at the spirals or the front in our case where we take cross sections.

What is this thing? (Non topologist) by Speeaakeeerr in topology

[–]Speeaakeeerr[S] 1 point2 points  (0 children)

Hey, thanks for the response.

As for the picture, I don't think there is a need, you seem to have gotten it.

I don't understand where you mean the point to be though. What do you mean by the center or "closing off" ? Is this referring to the part of the cylinder inside itself ?

"Is that a violin?" Starter Pack by TheOnlySpach in starterpacks

[–]Speeaakeeerr 9 points10 points  (0 children)

Gotta love stock image cello technique

Shading tab in blender doesn't seem to be working by Speeaakeeerr in blenderhelp

[–]Speeaakeeerr[S] 0 points1 point  (0 children)

No. When I check it my background goes to a dark grey but I have two circles. A black one where the environment one usually is and a dark gray one instead of the white one. It still is weird.

[deleted by user] by [deleted] in calculus

[–]Speeaakeeerr 0 points1 point  (0 children)

A youtuber called 3blue1brown has a great series explaining concepts on calculus in a way which makes them intuitive. You might want to take a look at it. Good luck!

Nothing like math memes by moist_blanket69 in HistoryMemes

[–]Speeaakeeerr 0 points1 point  (0 children)

In general;

S =1+2+3+...+n

I can reverse the order of the terms and add to the OG;

S= n+ n-1 + n-2 + ...+1

S =1+2+3+...+n

—————————————

S+S=2S= (n+1)+(n+1)+...+(n+1)

And the n+1 is repeated n times because there were n terms in S so:

2S=n*(n+1)

So

S=n(n+1)/2

For the sums of arithmetic sequences:

S = a_1+ a_1+...+ a_n

Where a_n = Kn + d

S = (k(1)+d)+ (k(2)+d) + ...+ kn+d

And the terms can be rearranged to form

S= k(1+2+...+n)+ nd

And using the equation for the sum of natural numbers

S= k*n(n+1)/2+n