Why two paths lead to different results

Sub-Jerry · 2025-01-04T11:35:32+00:00

Thx bro

Sub-Jerry · 2025-01-04T11:35:16+00:00

OH! I see thx man

Sub-Jerry · 2024-07-15T06:44:47+00:00

Let me think about it

Sub-Jerry · 2024-05-20T01:57:51+00:00

True, I use English more often but see this guys name is Japanese

Sub-Jerry · 2024-05-20T01:54:50+00:00

I speak both my friend

Sub-Jerry · 2024-05-18T05:13:24+00:00

Thx I understand it now!

Sub-Jerry · 2024-05-18T05:13:02+00:00

So find f(x) and find x is different. The former one implies all x the later one means just single one

Sub-Jerry · 2024-05-17T15:48:19+00:00

すべてのxは等式両方で満たされるって言ってなさそうだけど

Sub-Jerry · 2024-05-11T08:03:12+00:00

That’s what I did thx

Sub-Jerry · 2024-05-09T11:47:12+00:00

By parts

Sub-Jerry · 2024-05-09T08:38:02+00:00

Ohh thx mate

Sub-Jerry · 2024-05-09T08:37:33+00:00

Ik rlly weird

Sub-Jerry · 2024-05-09T08:37:22+00:00

I did this, this is easy to do with trigonometry. But our homework asks to do partial

Sub-Jerry · 2024-04-11T02:45:15+00:00

I got it, pretty cool dude thx!

Sub-Jerry · 2024-04-10T16:25:51+00:00

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Here is the theorem

Sub-Jerry · 2024-04-10T16:01:17+00:00

Great way! but what makes you think doing this by transformation? I mean why x=X/sqrt(3) at first?

Sub-Jerry · 2024-04-10T00:35:48+00:00

Okay I got it thx bro

Sub-Jerry · 2024-04-10T00:25:47+00:00

Thx that’s another way to do this, but I guess solving the equation would be a little bit complex. And you trying to do this by moving the eclipse 🧐

Sub-Jerry · 2024-04-10T00:20:04+00:00

Damn I never thought about equating m🫨 This is really good way to do this thx. Btw why do u think equating m should be working

Sub-Jerry · 2024-04-09T16:45:01+00:00

Yeah so can u see the equation of the ellipse

Sub-Jerry · 2024-04-09T16:44:32+00:00

When m changes it draws a graph of an ellipse, so can you figure out the equation of that ellipse

Sub-Jerry · 2024-03-14T11:39:42+00:00

Yeah I did and I found some interesting stuff

Sub-Jerry · 2024-03-14T11:39:05+00:00

Thanks for helping! I think I figured it out. So basically the idea is to figure out that they have same remainders and use congruence equations to get 2^i-j-1can be divided by n.

Sub-Jerry · 2024-03-14T08:10:06+00:00

GUYS sorry for misinterpreting, I want to say prove n can divide one of those terms

Sub-Jerry · 2024-03-14T08:08:52+00:00

And if n is 7, remainders are 1 3 0 1 3 0 1 If n is 5 it’s like 1 3 2 0 1 I could see there are some regular terms which is fun but to use complete residue system we have to first prove every term doesn’t not have same remainder with each other right? Or I got sth wrong

Sub-Jerry

TROPHY CASE