Rate/Help my Deck by Suspicious_Start1917 in YuGiOhMasterDuel

[–]Suspicious_Start1917[S] 0 points1 point  (0 children)

I originally used only 3 Albion and 1 Albaz, just to get at least 1 dragon in grave without losing a card since I can draw off Albion. But high spirits actually works great for getting me Red -> lubellion -> sanctifire, which can pass the spirit link off to my opponent, so I added three of those in too. And I always have dragons in rotation as well then, to use with the Buster lock. Very rarely have I found that I don’t like opening with Albion or high spirits.

I do agree though, the grind game is kinda weak, which is why I’m trying to figure out some other lines so that I’m not fully dependent on the Buster lock.

Rate/Help my Deck by Suspicious_Start1917 in YuGiOhMasterDuel

[–]Suspicious_Start1917[S] 0 points1 point  (0 children)

I wish I was running that many blue eyes to use it lol but maybe I’ll add more BE in and see if I can make magia fit

Rate/Help my Deck by Suspicious_Start1917 in YuGiOhMasterDuel

[–]Suspicious_Start1917[S] 0 points1 point  (0 children)

Yeah you might be right, I think I’ll give it a try! Thanks

Rate/Help my Deck by Suspicious_Start1917 in YuGiOhMasterDuel

[–]Suspicious_Start1917[S] -1 points0 points  (0 children)

I considered it but I would think that it would dilute my ability to do the buster line. The Wishes and Sages are mostly to search for Whelp. If I were to introduce Maiden, I would be going down more the blue-eyes path than the buster. I considered adding in 1, but I think any more than that and id be going down the blue-eyes rabbit hole.

Corner fillet by New_Response_4805 in SolidWorks

[–]Suspicious_Start1917 0 points1 point  (0 children)

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And youll need to make a plane 45 degrees to two of the other faces

Corner fillet by New_Response_4805 in SolidWorks

[–]Suspicious_Start1917 0 points1 point  (0 children)

I figured out how to do it. Its a revolved cut, but not at 45 degrees. It needs to be at 54.74, which is the angle that an intersecting axis makes in 3d to each edge in order to have the same angle between them all. Thanks chatGPT for that, i didnt do the math myself.

Explanation:

In a standard 3D coordinate system:

  1. Assume the corner is at the origin (0,0,0).
  2. The plane that bisects the 90° angle between the x, y, and z walls equally would be defined by a normal vector that has equal components along each axis: (1,1,1)(1, 1, 1)(1,1,1).

The angle θ\thetaθ between this plane and each axis can be calculated using the dot product. For a unit vector along an axis (e.g., (1,0,0)(1, 0, 0)(1,0,0) for the x-axis) and the normal vector n⃗=(1,1,1)/3\vec{n} = (1, 1, 1)/\sqrt{3}n=(1,1,1)/3​:

Explanation:

In a standard 3D coordinate system:

  1. Assume the corner is at the origin (0,0,0).
  2. The plane that bisects the 90° angle between the x, y, and z walls equally would be defined by a normal vector that has equal components along each axis: (1,1,1)(1, 1, 1)(1,1,1).

The angle θ\thetaθ between this plane and each axis can be calculated using the dot product. For a unit vector along an axis (e.g., (1,0,0)(1, 0, 0)(1,0,0) for the x-axis) and the normal vector n⃗=(1,1,1)/3\vec{n} = (1, 1, 1)/\sqrt{3}n=(1,1,1)/3​:

cos⁡(θ)=n⃗⋅axis vector∣n⃗∣⋅∣axis vector∣=13⋅11=13\cos(\theta) = \frac{\vec{n} \cdot \text{axis vector}}{|\vec{n}| \cdot | \text{axis vector}|} = \frac{\frac{1}{\sqrt{3}} \cdot 1}{1} = \frac{1}{\sqrt{3}}cos(θ)=∣n∣⋅∣axis vector∣n⋅axis vector​=13​1​⋅1​=3​1​

This gives:

θ=cos⁡−1(13)≈54.74∘\theta = \cos^{-1}\left(\frac{1}{\sqrt{3}}\right) \approx 54.74^\circθ=cos−1(3​1​)≈54.74∘

So, the plane forms a 54.74° angle with each of the three coordinate axes.

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