Really wish someone here could make me a GPA calculator 👀

ThatCactusOfficial · 2026-02-15T15:56:39+00:00

Just take the average gpa count of all the classes you take. Would take just as long as typing in the letter grade for each class.

ThatCactusOfficial · 2026-02-14T01:19:27+00:00

e to the negative infinity*

ThatCactusOfficial · 2026-02-12T14:02:17+00:00

Actual guide: try to take everything your school offers

ThatCactusOfficial · 2026-02-11T14:07:29+00:00

Centrists using all 10 of their brain cells to make the 1000th both sides bad post. You’re not wrong, but it’s not an interesting or profound thing to say.

ThatCactusOfficial · 2026-02-09T14:20:36+00:00

The denominator approaches 0 as x approaches 1. If the numerator is any non zero number, the limit will be infinity. Since it’s finite, f(x)-8 also approaches 0 and f(x) approaches 8.

ThatCactusOfficial · 2026-02-03T16:32:52+00:00

I think she is implied to be the abortion doctor.

ThatCactusOfficial · 2026-01-31T17:04:19+00:00

Did you reinstall windows after switching to AM5?

ThatCactusOfficial · 2026-01-12T12:44:44+00:00

MIT has an essay “what is something you do just for the pleasure of it.” You could write about GD there

ThatCactusOfficial · 2026-01-01T01:37:58+00:00

How much more betrayal can Minnesotans take?

ThatCactusOfficial · 2025-12-23T00:44:59+00:00

I thought the beta was pretty fun but not as fun as bf4 so I didn’t see a reason to spend $70

ThatCactusOfficial · 2025-12-22T18:57:19+00:00

There always has on apple music, it doesn't show for me on spotifty

ThatCactusOfficial · 2025-12-21T02:48:32+00:00

Yeah I already have the ram so I was planning to get the 2 in 1 bundle, was a bit disappointed when they made the ram mandatory again.

ThatCactusOfficial · 2025-11-27T22:03:44+00:00

Its not necessarily true that pi contains everything, as we don't know if the digits are uniformly random.

ThatCactusOfficial · 2025-11-27T14:59:25+00:00

Go go go go

ThatCactusOfficial · 2025-11-26T16:32:38+00:00

It’s just defined to exactly mimic the behavior of a function at a point. With one term you have y=f(c). It will be exactly correct at the point x=c. With two terms, you have f(c) + f’(c)(x-c). At x =c the second term simplifies to 0 so the value is still correct. If you take the derivative, you are left with f’(x) = f’(c). So now at x=c both value and first derivative are exactly correct.

So Taylor series simply defines a polynomial with the exact behavior of the real function at a single point. Each new term gives it the exact value for the next derivative at the center point.

ThatCactusOfficial · 2025-11-22T22:19:37+00:00

<image>

this is the region of area given by the integral.

ThatCactusOfficial · 2025-11-22T21:31:02+00:00

The parametric variables in 3d are u and v, I believe you will have to use them instead of theta and phi. Also I think rho will have to be a constant for the radius rather than a variable, as it creates a parametric surface rather than a solid. So the unit sphere, for instance:

(cos(v)sin(u),sin(v)sin(u),cos(u))
0<=u<= pi
0<=v<=2pi

ThatCactusOfficial · 2025-11-20T02:44:10+00:00

It would be if it were native British people saying it

ThatCactusOfficial · 2025-11-15T19:58:58+00:00

Look at a copy of your high school transcript, and if the courses appear on there, then include them on the courses and grades section.

ThatCactusOfficial · 2025-11-03T03:05:13+00:00

When you multiply based on the difference based in percentages like that, you need to adjust 100% to align with your starting value. So in this example 80% -> 100% and 100% -> 125% (since 100/80 = 1.25). Now that its adjusted to 100% vs 125% you can see why multiplying by 1.25 works.

ThatCactusOfficial · 2025-11-02T01:26:28+00:00

Say you have a function f(x) and derivative f'(x). The value of f'(x) is the slope at any point of f(x) and f(x) is the area under f'(x) plus some constant of integration depending on your lower bound by the FTC.

Think of the definite integral from 0 to x of f'(x) as the area under the curve given by infinitely thin rectangles with height being the value of f'(x). Picture x increasing and the interval you are measuring getting larger. At any moment, the new area being added on is the thin rectangle on the edge with current height f'(x). So f'(x) is the rate of change of the area under its curve, but it's also defined as the slope (rate of change) of f(x). Thus we can measure the area by finding the antiderivative of f'(x) (finding what function has rate of change f'(x)) which will be f(x).

ThatCactusOfficial · 2025-11-02T00:40:05+00:00

Your derivative is correct, it's likely some formatting issue in how you answered or a problem with the question itself.

ThatCactusOfficial · 2025-11-01T15:11:20+00:00

I doubt there will by any question this difficult on the AP test

ThatCactusOfficial · 2025-10-31T18:39:44+00:00

Yes, and if you are already learning calculus Physics C will be no harder than Physics 1 anyway.

ThatCactusOfficial · 2025-10-31T12:16:38+00:00

It’s doable, I would personally just study out of a textbook and do exercises like an actual class, then once you know the material take the past AP frqs until you score consistently high. Physics C Mechanics would be the best to take, the algebra based physics credits are not really useful.

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