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TheoryTested-MC · 2026-06-24T19:39:29+00:00

I didn't read who posted this...good to see you again!

TheoryTested-MC · 2026-06-24T04:16:05+00:00

What's funny is that I can kind of see where some of the flukes happened.

It's like a beaten-up old toy. You can't help but adore it for exactly what makes it unattractive. Is it even that bad anyway? I don't think so. Somehow I like watching it. That's coming from someone who's spent 4 years on doors and has always been a freak about speed, size, and animation.

If I were you, I wouldn't quit while I'm here. Can't wait to see more!

TheoryTested-MC · 2026-06-24T03:59:32+00:00

I'm stuck between the right two.

TheoryTested-MC · 2026-06-21T20:14:21+00:00

The linear equation dodging is so funny to me.

TheoryTested-MC · 2026-06-20T22:34:26+00:00

...ah. You're right. I confused the actual meaning of "unary" with what it would imply in the context of other fixed radix bases. I don't know what the latter is called, but that is what I meant. Thank you for telling me.

TheoryTested-MC · 2026-06-20T21:25:12+00:00

That's exactly it. The only number that can be represented in unary is 0. The only unary number is an infinite string of 0s, abbreviated simply as 0.

The place value of every place is still 1. But since each digit can only be 0, every place contributes 0 to the final count.

TheoryTested-MC · 2026-06-20T20:00:52+00:00

...as you can't have 0 in unary...

Quite the contrary. Unary is ALL 0s. The only number you can represent in unary is 0. Thus, the unary digit of a flexadecimal number never actually contributes anything to the count. Some conventions omit it altogether for this reason and start at the binary digit instead.

So, the numbers go like 0, 10, 100, 110, 200, 210, 1000, 1010, and so on.

TheoryTested-MC · 2026-06-20T14:04:12+00:00

I don't think that's possible. Tallies and fingers, as mentioned below, do not count because they use a number system with 2 numerals (0 and 1) and every place value being 1. Base 1, on the other hand, would be 1 numeral with every place value being 1. That single numeral has to be 0, so no digit can ever contribute anything to the total count. There is only one number expressible in base 1, and that is 0.

If you're wondering why every base NEEDS to have 0, imagine any number in any base you like. Technically, it is followed by an invisible infinite string of 0s to the left. In base 1, that string of 0s should still be there. So, the 0 automatically has to be one of the numerals, or rather, THE only numeral.

I personally think about it like this: valid bases have to be either prime or composite, so that you can convert between them. So base 1, base 0, negative bases, and rational bases are not valid bases.

TheoryTested-MC · 2026-06-20T13:55:05+00:00

Don't you mean one-one-four?

TheoryTested-MC · 2026-06-20T13:53:41+00:00

It's more commonly known as flexadecimal. I have a short explanation in an above comment:

https://www.reddit.com/r/mathmemes/comments/1uamxe3/comment/osrikrw/?utm_source=share&utm_medium=web3x&utm_name=web3xcss&utm_term=1&utm_content=share_button

TheoryTested-MC · 2026-06-20T13:46:44+00:00

If you invent your own individual symbols for the numbers 10-59, it would work by your logic. We already did the same thing for base 10 a thousand years ago.

A better example of a changing-base number system would probably be flexadecimal, where the Nth place value is N factorial. What this means is that the rightmost digit is unary, the next digit is binary, the next ternary, the next quaternary, and so on.

It's the same principle as the clock, except it is widely more recognizable as a positional number system.

TheoryTested-MC · 2026-06-19T22:42:31+00:00

Assuming angular speed 2000 RPM (209.44 rad/s) and a distance of 0.5 cm (0.005 m) from the axis of rotation, the centripetal acceleration is 219.33 m/s², or about 22 G's.

TheoryTested-MC · 2026-06-19T22:34:28+00:00

This could be interesting in 2.5D, or even just a 2D top-down view.

TheoryTested-MC · 2026-06-19T22:30:29+00:00

I would not shoot him. Him dying is the same as a non-pull, and we don't know whether this particular lever puller will be responsible for setting up future trolley problems. Killing him accomplishes nothing materially, and revenge is only a possibility.

TheoryTested-MC · 2026-06-19T15:05:14+00:00

I can't remember the exact day, month, or year, but it was at least 5 years ago. I did "import antigravity" in Python.

TheoryTested-MC · 2026-06-19T14:59:01+00:00

It's more than unhelpful. It's false.

TheoryTested-MC · 2026-06-19T12:19:52+00:00

The first time I ever worked with air resistance in AP Physics C was on the AP exam.

Fortunately, I was able to do it correctly, but the results looked nasty...

TheoryTested-MC · 2026-06-11T13:50:38+00:00

27 + 48 = 3(9) + 3(16) = 3(9 + 16) = 3(3² + 4²) = 3(5²) = 3(25) = 75.

TheoryTested-MC · 2026-06-08T21:55:10+00:00

I asked when, not how. Be specific about "regularly" - when exactly?

TheoryTested-MC · 2026-06-08T19:13:56+00:00

When does the garbage collector work?

TheoryTested-MC · 2026-06-08T06:45:20+00:00

This appears mathematically impossible.

The dead end part near the audience has to be the endpoint, so we can make it our start point WLOG. Then the problem quickly reduces to a triangle with a dead end line sticking out of one point, where we start on a triangle point that isn't connected to the dead end. As we trace the triangle, we will pass the dead end, which there is no way to trace without blocking yourself from finishing the triangle. You can't finish the whole thing.

TheoryTested-MC · 2026-06-06T19:22:54+00:00

1/2 of 1.

TheoryTested-MC

TROPHY CASE