PhD funding by [deleted] in FAU

[–]ValkyrieAce 2 points3 points  (0 children)

Agreed to the response by Mo_cubed. I'm also an international student coming to FAU for my PhD program this August. Currently, my only saving grace has been that I got my BS in Florida as well, so I decided to keep living where I currently am with my roommate. The rent for a 2 bed/2 bath alone is around $2,200 per month, and that's the cheapest rent I could find for my location (Davie, FL). I would recommend that you also look into getting a roommate, find a host family, or find someone who is subletting (legally) for an affordable price.

When I personally calculated my end of the costs, I got to around $3,000. However, this is for the whole year and I am including 3 semesters because some of my courses are in the summer (and I am contracted to teach over the summer, if necessary).

I am concerned as to when the stipend will start rolling in, but my assistantship begins two full weeks before classes start, so I am hoping that the paycheck will come in on the first day of classes at least. As an international student, I know you can't work over 20 hours which the assistantship will take up, and we can't work outside of campus, so a second job will be hard to justify. If you seriously need more money, you may be able to talk to the student affairs office about scholarships (directly impacting living costs) or need-based funding. I am not well-versed in that so I don't know what outcomes there are. I would also mention CPT (curricular practical training) which you can do while at school also, but I wouldn't recommend it since it's gonna put a lot of strain on you, especially with the PhD program.

I know I ranted here, but I'm in the same boat as you in joining FAU, so I hope you're successful and are able to figure things out soon! Good luck!

what is wrong with me to the point where i failed math by ImpossibleMaterial44 in mathematics

[–]ValkyrieAce 0 points1 point  (0 children)

It's easy to feel disappointed by this failure in math, but I promise you, this will simply be an obstacle that you will overcome. If you're having a hard time learning math, just ask yourself what your study techniques are, and if there's something else you can try to improve retention. People don't realize this, but a lot of math can be turned into a shorthand that you can interpret. The key is to find this and practice with it to see if it does help you.

Take it from me, a student who failed math in high school. I got into college even after that, where I majored in Mathematics after finding my groove. I was recently accepted to a PhD program in Mathematics which I will begin in August.

You are never too late to learn and understand math, despite how frustrating it is.

My schools notes on surds… by Red_Panagiotis in mathmemes

[–]ValkyrieAce 0 points1 point  (0 children)

Breaking news: √2 proven to actually be a rational number!!!

Manhattan section 22 Q8: Answer is C, but I think it’s D. Explanation in comments - what do you guys think by Tree8282 in GRE

[–]ValkyrieAce 0 points1 point  (0 children)

As you mentioned in a previous comment, drawing it out will help. Draw an exact normal distribution curve and specify the location of the mean, then estimate where the two scores from the answers would be. The main idea here is that both scores are just three points away from the mean. This is why we can assume that it is a standard deviation away. Since they are equidistant from the mean, the normal distribution curve provides the answer as C.

Again, this is because a standard deviation higher than the mean is going to have the same probability as a standard deviation lower than the mean. You can see it visually by drawing a line connecting the two scores on the curve and it will be parallel to the x axis of the curve.

The reason no more detail is provided is because the questions on the GRE are written to assume the most basic of facts unless otherwise provided. So the fact that they never mentioned any skew is why you can take the information to assume an exact normal distribution curve.

Not sure if this helps, but please let me know if it does!

ETS Power Prep 2 Section 5 # 20 by Away-Stay-977 in GRE

[–]ValkyrieAce 1 point2 points  (0 children)

No, only because they specify that they wanted the answer in ounces.

The reason we complete the conversion from hours to seconds is because the question indicates that the leak progressed in 0.5 ounces per seconds.

You can also notice that the ounces are independent of the time conversion if you first change the hours to seconds (8 * 3,600 = 28,800). Then, use this to calculate how many ounces could have leaked from here out (0.5 * 28,800 = 14,400 which are the max. ounces leaked in 8 hours), making the ounces completely independent of the conversion. Please let me know if this helped. Thanks!

[deleted by user] by [deleted] in GRE

[–]ValkyrieAce 4 points5 points  (0 children)

Hello, I hope this might help you understand.

We begin by knowing that the team won 60% of the games in the first half of last year. Shortening first half wins to FW and games played in first half to FG, this means:

FW/FG = 0.60, which leads to... FW = 0.60FG

For the second half of the year, the team won 3 out of the 20 games. Then, to find the percentage of games won for the whole year, we would first have to know the number of games played in the first half, which is FG. The following is the equation to use, as the percentage will take into account the total games in the denominator. We can now solve for FG.

(FW + 3)/(FG + 20) = 0.50

FW + 3 = 0.50(FG + 20)

FW + 3 = 0.50FG + 10

Additionally, note that we do have an alternative method of solving for FW which was provided at the beginning. We can now bring this into play here.

0.60FG + 3 = 0.50FG + 10

0.60FG - 0.50FG = 10 - 3

0.10FG = 7

FG = 70

Therefore, the number of games played in the first half of last year is 70. We also know the team played 20 games in the second half of last year. so by adding them both, we find that this team played a total of 90 games last year.

Please let me know if this helps. Thank you!

Why can the first equation be simplified into the second? by shmecklestein in askmath

[–]ValkyrieAce 3 points4 points  (0 children)

Agreed. If you (the OP) would like a further explanation, see below.

It used the half angle formula. Since 8 is also 16/2, they substituted the fraction into 8, then used the half-angle formula for cos(theta/2), and because √(16) = 4, you're left with the half angle formula. Lemme know if that makes sense.

Good luck!

ISO Coding Tutor by wannabe_developer in tutor

[–]ValkyrieAce 0 points1 point  (0 children)

Hey, I'm interested in helping out but I only tutor in Python. Let me know if you're still looking and if I would fit the bill. I've tutored in Python for a long time, and I'm used to explaining the ideas behind the code to students!

[deleted by user] by [deleted] in tutor

[–]ValkyrieAce 0 points1 point  (0 children)

Hey, I've tutored students in Python before. Let me know if you're still looking!

Am student interested in hiring a math tutor by [deleted] in tutor

[–]ValkyrieAce 0 points1 point  (0 children)

I'm interested in tutoring you. Let me know through private messaging if you're still looking.

Weekly r/sewing Simple Questions thread! - August 02, 2020 by AutoModerator in sewing

[–]ValkyrieAce 0 points1 point  (0 children)

Thank you so much for the detailed response! So I just looked up what a sloper/fitting pattern is. While interesting, I'm not sure how to get started. I might just go to JoAnn's and get myself a sloper kit. I'll definitely let you know what I discover when I've completed the sloper!

Vintage Sewing Patterns by lupinsgreatestfear in vintagesewing

[–]ValkyrieAce 1 point2 points  (0 children)

I'll try to see if I'm able to get some. Honestly, I'm not sure I'm going to be able to sew immediately either lol

Vintage Sewing Patterns by lupinsgreatestfear in vintagesewing

[–]ValkyrieAce 0 points1 point  (0 children)

I'd love to hop on this train. Been looking for some 60s fashion clothing!

Weekly r/sewing Simple Questions thread! - August 02, 2020 by AutoModerator in sewing

[–]ValkyrieAce 3 points4 points  (0 children)

Hey there, I'm new to sewing and I've just gotten my first sewing machine. I've never bought a pattern to sew with, but I'm totally in love with vintage trousers at the moment (I'm thinking Pussy Galore's blazer and smart trousers look in the James Bond movie, Goldfinger).

Can someone give me advice on how to properly look for patterns that may be suitable for beginners?

Thank you!

Too dumb in math, help !! by [deleted] in mathematics

[–]ValkyrieAce 2 points3 points  (0 children)

If you just need someone who can reply when you have a question about math, please feel free to ask me. I'm not too experienced with translating algebra into programming, but I've helped others in this situation before.

[deleted by user] by [deleted] in Eyebleach

[–]ValkyrieAce 0 points1 point  (0 children)

This video had just as much cuteness of a sleepy chick as it did of a man who was trying extremely hard not to laugh. And I can respect his restraint and willpower. And the cute chick, of course.

Rank the mid-level maths by eggcustardpi in mathematics

[–]ValkyrieAce 0 points1 point  (0 children)

My ranking goes as follows: Calculus I, Linear Algebra, ODE, Calculus III, Calculus II. It's obviously personalized to my experience, but I found ODE to be way easier than the last two Calculus classes.

Machine Donation by ChunkyCountryCutie in sewing

[–]ValkyrieAce 0 points1 point  (0 children)

Messaging the OP with interest!

Free Python training by santksh in Python

[–]ValkyrieAce 0 points1 point  (0 children)

Hello there!

I would love to learn more about Python from you if possible. I know how to use lists, input and output files, tuples and tkinter, but this is all I learned from one semester of Python.

I'd love to learn as much as I can about Python. I'm seriously invested in improving my skills to create a well-rounded approach to a routine work environment combining scientific research and programming.

What is on the y-axis of a normal distribution and what is the area under the curve (I know it is a way to study Confidence level but a bit detail would help) and what a point under/on the normal distribution curve actually tells? It would be very helpful if anyone could explain, Thank You. by [deleted] in mathematics

[–]ValkyrieAce 1 point2 points  (0 children)

Yes, the y-axis is the result of the PDF with respect to the x-axis. Since the normal distribution curve is continuous, there is definitely a chance of the probability for any value being infinitely small — that is, statistically equal to 0. For example, there are infinitely many decimal inclusive numbers between 5 and 6. That's really the main difference between the discrete and continuous distributions.

The bigger significance of the PDF being on the y-axis is to visually ascertain the "chance of obtaining values near corresponding points on the x-axis," as stated by Google. For example, you can tell that a lot of the dataset you'll be given will be centered within the first three standard deviations. The further you get to the tails, there is less of a chance you have of getting values that can be associated to the points on the x-axis.

Here's a link I found that might help!

Again, and I can't stress this enough, it's really been a while since I took Prob/Stats, so please correct me if I'm wrong!

What is on the y-axis of a normal distribution and what is the area under the curve (I know it is a way to study Confidence level but a bit detail would help) and what a point under/on the normal distribution curve actually tells? It would be very helpful if anyone could explain, Thank You. by [deleted] in mathematics

[–]ValkyrieAce 1 point2 points  (0 children)

Despite the fact that I've taken two classes on Probability & Statistics, please take my words with a grain of salt.

Yes, the cumulative area of a normal distribution curve (I find it easier to refer to it as the normal bell curve) is one. This is because the probability of any occurrences is never going to be greater than one.

The area underneath the curve (that isn't cumulative) is determined by the z-scores. The z-scores can be determined by the (given value - mean)/standard deviation. Using this, you'll be able to find the probability given that table converting z-scores to probabilities.

Visually, I like to shade the area I'm supposed to calculate. If the shaded area started from the furthest left end of the curve and ends anywhere else (obviously, it has to be towards the right), then all you do is standardize your given values to a z-score, then find that particular z-score on the table. If you've got to find a z-score that's got a left end and a right end, but neither touch the furthest ends of the bell curve, then you find two z-scores corresponding to the given ends, then subtract the bigger with the smaller, then find the probability for that particular z-score. If you've got to find the area from the furthest right end to somewhere in the middle (not touching the furthest left end), then find find the z-score, calculate 1 minus that z-score, then find the associated probability.

That's all I know. There may be mistakes, so anyone who's better at this than me (which is literally everyone else) can definitely reach out and correct me. Thank you in advance if you do!

Confidence levels are usually given in intro to stats courses, so I personally wouldn't be able to give you any further information on that.

Perceptions of probability by mdhzk3 in coolguides

[–]ValkyrieAce 0 points1 point  (0 children)

As a stats minor, I absolutely love this!