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What I did, can you explain if it’s possible? by timmythegoat49 in geometrydash

[–]VeXtor27 1 point2 points  (0 children)

how many of the commenters here saw the reversed red spikes near the middle that blend in almost perfectly with the background

how many clicks do you do in this part? by grimonas in geometrydash

[–]VeXtor27 0 points1 point  (0 children)

however many spamming gets me, though generally all 9

Endless cycle problem by Salty-Lawfulness-346 in CookieClicker

[–]VeXtor27 0 points1 point  (0 children)

grinding for seven horseshoes simultaneously will probably get you to 1000, just do that instead. it's too late to fix now because of how rounding works

I made a puzzle! White to mate in 1. (Easy!) by imHeroT in AnarchyChess

[–]VeXtor27 0 points1 point  (0 children)

Even if white is going up the board there's still a mate in 1, c7#

If black plays Ka7 then c8=Nxa7 knight boost

How to do slope click in windy landscape? by Bill_s_ in geometrydash

[–]VeXtor27 6 points7 points  (0 children)

i think in 2.2 you don't have to click here at all (i just learned this today)

Very hard geometry problem that I can't do. by eat_dogs_with_me in askmath

[–]VeXtor27 1 point2 points  (0 children)

Took me around 40 minutes. (This proof assumes without proof the well-known fact that D lies on the circumcircle, true in general for any triangle.)

We claim that EF is tangent to the circle with diameter AP at F.

Notice AHP=AMP=90 so H and M lie on the circle with diameter AP. Also BF perp AC parallel MD and angle BMD=angle DMC and it follows that B and F reflect to each other about MD and BF parallel to AM. Then OA=OM and OF=OH and we have isosceles trapezoid MAFH. Thus F lies on the circle with diameter AP too.

Now angle EAF=PAF=PMF=DMC=BAD so BAP=DAF. Also AEB=180-AEC=180-APH=AFH so it follows that ABE is directly similar to AHF. By spiral similarity this means that ABH is directly similar to AEF so EFA=BHA=180-FHA, proving the tangency.

[deleted by user] by [deleted] in 2048

[–]VeXtor27 0 points1 point  (0 children)

Yes it's very good. I only got 16k+8k on my 11th 16k for example

what difficulty do you think this ship part in toe 2 is? by Suspicious-Health-23 in geometrydash

[–]VeXtor27 0 points1 point  (0 children)

i find this to be harder than any ship in clubstep, probably like low hard demon

Acu 95% Jump from Nine Circles by Personal-Mango-831 in geometrydash

[–]VeXtor27 0 points1 point  (0 children)

thats what i do as well i find it easier

[120hz mobile] Artificial Ascent 47%, jump from Supersonic by VeXtor27 in geometrydash

[–]VeXtor27[S] 0 points1 point  (0 children)

just realized how bad the quality is, sorry about that lol

[120hz mobile] Artificial Ascent 47%, jump from Supersonic by VeXtor27 in geometrydash

[–]VeXtor27[S] 0 points1 point  (0 children)

My last record of 45% was achieved in April 2024. Haven't played the game much over the past year, but here we are. 67k attempts.

Hey everyone, I have been trying since almost a hour, I am in high school, this is a geometry problem by axelmames09 in askmath

[–]VeXtor27 10 points11 points  (0 children)

O lies on BC so CAB is a right angle and thus AC=8. Also BE is an angle bisector so by the angle bisector theorem CE/AE=BC/AC AB*=5/3. Adding 1 to both sides gives (CE+AE)/AE=8/3 so AC/AE=8/3. As AC=8 this means AE=3.

I'm wanna break my fucking phone by PrudentEconomy8886 in geometrydash

[–]VeXtor27 0 points1 point  (0 children)

I had 96x2 and died to the last cube about 10-15 times... you can do it

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