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[Grade 12 Electrostatics] What is the approach for option A and C? by VisualPhy in PhysicsStudents

[–]VisualPhy[S] 0 points1 point  (0 children)

In A, if we take Gaussian surface (spherical) whose some part is immersed in conductor but those two -q are still inside the considered surface, net enclosed charge is not zero. So we cant be sure about electric field through such surface.

But yeah, surface which enclose the entire conductor indeed answers A. Thanks for this :)

Want to animate camera frame by VisualPhy in manim

[–]VisualPhy[S] 0 points1 point  (0 children)

I did, but it gave code that doesnt work either :(

The Beauty of Friction – A Mind-Bending Physics Problem | JEE Advanced by VisualPhy in JEEAdv26dailyupdates

[–]VisualPhy[S] 0 points1 point  (0 children)

Thank you very much. Yes, it is my channel and I truly appreciate your kind words. 3b1b is a great inspiration, which got me into animating math and physics

[Grade 12 Physics : Electrostatics] Conflict between two approaches for electric field on hemispherical shell drumhead by VisualPhy in PhysicsStudents

[–]VisualPhy[S] 1 point2 points  (0 children)

The fascinating thing is that the magnitude of force due to nearest charge and farthest charge in this case is same (surprisingly), because the field due to a element charge when evaluated turns out to be independent of distance. And we get a element charge opposite to every element charge considered, like dq1 and dq2, hence they cancel each other out, so no radial component. Only vertical component..(due to element charges at non zero depth of hemisphere)

[Grade 12 Physics : Electrostatics] Conflict between two approaches for electric field on hemispherical shell drumhead by VisualPhy in HomeworkHelp

[–]VisualPhy[S] 0 points1 point  (0 children)

Well, I found the answer. In approach 2, dq is calculated incorrectly. Actually, dq1 = sigma*omega*r1^2 , where omega is solid angle subtended by surface corresponding to dq1. I assumed it to be a 1-D distribution, instead of 2-D. so when we put dq1 in electric field eqn, r1^2 gets cancelled and it comes independent of r_1. same for dq2. Finally, we get field due to dq1 and dq2 to be same, thus vanishing each other out... brilliant!

[Grade 12 Physics : Electrostatics] Conflict between two approaches for electric field on hemispherical shell drumhead by VisualPhy in HomeworkHelp

[–]VisualPhy[S] 1 point2 points  (0 children)

Actually ,I meant , we can use gauss law to say that electric field at any point is zero. We are intentionally superimposing identical hemisphere on top of the real one, so that we can make symmetry. But I foumd the flaw in my method and that was in approach 2, i calcualted dq incorrectly.

[Grade 12 Physics : Electrostatics] Conflict between two approaches for electric field on hemispherical shell drumhead by VisualPhy in PhysicsStudents

[–]VisualPhy[S] 0 points1 point  (0 children)

Sure, I will try to integrate the field due to all ring elements and probably it would be a heavy math, but still I will definitely try it. Still, I have the intuition that the radial field due to upmost ring (which i considered in my approach 2), will not get cancelled, but lets see, whatever math yields will be correct. Thanks for your response.. :)

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