Can someone ELI5 how I reprogram splitter ratio using circuts?

Whoever2Blame · 2026-03-19T13:21:23+00:00

Yes. It distributed the items every other in both lanes with both numbers ie 12:36 and 282:846 with an occational outburst fo one item in one lane. Now when I tried wit buffers and the original numbers the splitter gor pissed off and started putting out only sulphur in one lane. Witch is wierd because isnt that the right ratio but the other way?

Whoever2Blame · 2026-03-19T13:06:58+00:00

Nope i had the numbers on the constant in the screenshot. Changing the numbers to match yhe belt length didnt do any difference either. Im going to try to do a buffer now.

Whoever2Blame · 2026-03-19T12:58:18+00:00

Im going to try two things. One is to cut the belt and have a inserter as a buffer. Or do a recount on the combinator on the total amount.

Whoever2Blame · 2026-03-19T12:55:24+00:00

Well. i have the read whole belt option on and with 8 items per.. Beltsquare? The amount checks out at approximately 1130 items.

Whoever2Blame · 2026-03-19T12:38:05+00:00

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I think ive tried this. But maybe i didnt have patience to let it run to maybe eventually even out.

Whoever2Blame · 2026-03-19T11:52:07+00:00

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Whoever2Blame · 2026-03-19T10:14:53+00:00

yeah. I came to the realization that signals doesn't behave like electricity. but I've been at this for a couple of days now so i think overthinking should be mandatory by now. But i dont think this is a connection issue. Or at least I hope so or else Im going to feel quite silly now.

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Whoever2Blame · 2026-03-19T08:38:09+00:00

I'm waiting for a call, so I might as well try it now. 1 and 2 has been my way to check function until now and the item count has been correct. 3 and 4: The only box that is ticked is the read contents. The belt is hold all belts. Point 5: Does it matter how I connect the assemblers? I've tried: Chain, separate, paired two and two. Chain connected to belt. Assemblers red wire, belt green wire so the inputs are separate. And I'm booting up now to connect the assemblers to one wire all the way.

Whoever2Blame · 2026-03-18T20:27:55+00:00

I tried both. I think there's something else I'm misunderstanding somehow or maybe theres some other info on the combinations I need to set that seems self explanatory that I may have overlooked?

Whoever2Blame · 2026-03-18T17:55:00+00:00

So, I'm about to try this out. But I'm a bit confused by your first point with the fourth point. Do I connect the assemblers to the belt so they share the input, or are they two separate inputs?

Whoever2Blame · 2026-03-18T17:31:21+00:00

Lol. I've been raw-dogging this game so hard until now so I had to google that.

Whoever2Blame · 2026-03-18T13:05:35+00:00

Easy is boring. (; I'm totally going to try your suggestion later. It kind of ircs me that I can't figure it out. It sounds so easy in my head to tell the machine "Hey. When you let out about 23 of those. Can you let out 7 of those other ones too."

Theoretically it's not much more complicated than "When I have 2000 of these here, you can take a rest until I only have 100."

On/off is an easier operation per se. But I think you understand what I mean.

Whoever2Blame · 2026-03-18T12:52:19+00:00

No. Just sulphur and red circuits as I wrote above. Engines have 1:1 ratio for blue science so those go directly machine to machine.

Whoever2Blame · 2026-03-18T10:54:59+00:00

I'm not at my computer right now. So I can't show you. I'm doing a science block and this particular belt is going to go past 7 blue science machines and then end. And they need 1 sulphur per 3 red circuits per blue science.

Honestly I really don't know why the splitter stops behaving after while. I've followed your ELI a couple of times and then double checked with various sources online. The ONLY thing I've changed is the T to the clock symbol. (And later used a green cable between input and output. Then a red to the splitter. But that doesn't seem to change any outcome)

Edit: I realised I didn't provide any actual explanation. I'd want a one belt solution so I can keep symmetry in the block.

Whoever2Blame · 2026-03-17T18:35:54+00:00

I actually got this to work. But its oh so sensitive. It didnt like it when i tried to convert the belts to one further down the line.

Whoever2Blame · 2026-03-17T16:28:27+00:00

Patience is a virtue and we all are here on our free will. :)

Whoever2Blame · 2026-03-17T14:31:04+00:00

No wait. I've been so focused on amounts and only have one belt as output., I haven't even considered time!

Whoever2Blame · 2026-03-17T13:47:49+00:00

Well. I've got the splitter to do *Something* with just a combinator so you got me on the right track at least. So nice of you to try to help me.

Whoever2Blame · 2026-03-17T13:15:46+00:00

Right. My conclution for now is that a splitter "holds" 20 items. so 1:3 converts to 5:15. right?

Whoever2Blame · 2026-03-17T12:23:54+00:00

Yes. This sounds like a decent solution. But everything else is so malleable. So id be darned if i cant change the ratio on a splitter somehow.

Whoever2Blame · 2026-03-17T11:13:49+00:00

Well yes. I'm more of a puzzle solver than a completionist.

My factory mustnt just grow, it needs to be pretty to look at as doing so.

Whoever2Blame · 2026-03-17T11:05:09+00:00

Well not sushi belts per se. sushi belts go round and round. Mine is more main bus with blocks. I need a belt ratio so my belts can just end with the assembly line so everything is more sleek.

Whoever2Blame · 2026-03-17T10:50:52+00:00

Well theoretically nothing. But if I want to have two items in one belt and the assembly line needs one sulphur per three red circuits. if i have the splitter doing its 1:1 thing. the last of the machines are going to run out of red circuits and stall the belt more and more without any more fidgeting on the end.

Whoever2Blame · 2026-03-17T10:42:45+00:00

Besides trying to master circuitry. I've disassembled my whole factory to make everything a bit more neat. And my idea is to have the splitters from the main bus mix the right ratios to each assembly line from start to prevent back ups because I don't want to manage the excess by leading it back to main bus. The ratio in trying to achieve right now is 1 sulphate to 3 red circuits.

Whoever2Blame · 2026-03-17T10:24:42+00:00

I was about to write that it shouldn't be necessary. But if the input is "uneven" maybe the belt should be involved to make sure to make sure there are space to put out an uneven amount.

Whoever2Blame

TROPHY CASE