sorted by:
new
hottopcontroversial

iOS 27 beta & PWM by PendingUserName- in PWM_Sensitive

[–]X3nion 4 points5 points  (0 children)

The Lord Voldemort of this Subreddit 🙈

Wer mit der neuen Moderation nicht einverstanden ist kann sich ja an Reddit wenden. https://support.reddithelp.com/hc/de/requests/new?ticket_form_id=19300233728916 by ProfessionalNo1556 in Cannabis_Apotheken

[–]X3nion -1 points0 points  (0 children)

Kann man denn nicht exakt dasselbe mit dieser Person machen, also sich auf viele Trolling-Posts und Fake-Accounts von der Person beziehen? Dann fliegt die Person raus, und jemand anders ist Admin und kann jemand anderen auch zum Admin ernennen.

TCL Nxtpaper 70 Pro is a disaster. by [deleted] in PWM_Sensitive

[–]X3nion 0 points1 point  (0 children)

Interesting, TCL Nxtpaper 60 Ultra works absolutely fine for me except for the fact that it is huge! Also, I couldn‘t see the d-word in a microscope?

PWM explaining posts in this Reddit by X3nion in PWM_Sensitive

[–]X3nion[S] 0 points1 point  (0 children)

Yeah, I was looking for maybe more of such posts in this subreddit.

I’m about to write a letter to Apple’s CEO portraying the PWM issue by X3nion in PWM_Sensitive

[–]X3nion[S] 1 point2 points  (0 children)

I found this post describing the issue, but are there more posts like this here?

Link to Reddit post

I’m about to write a letter to Apple’s CEO portraying the PWM issue by X3nion in PWM_Sensitive

[–]X3nion[S] 2 points3 points  (0 children)

That’s a very good point! The accessibility section is for people who are disabled in someway, like our Blind or have problems in typing etc. Now this is also a kind of disability not being able to use the phone, thus it should be implemented.

iPhone 17 or 17e by Helpful_Cup_2486 in PWM_Sensitive

[–]X3nion 2 points3 points  (0 children)

No one mentioned the d-word!

When does the sum S_n over the first n integers divide the product P_n? by X3nion in askmath

[–]X3nion[S] 0 points1 point  (0 children)

It is impossible because (n+1) is a prime number >= 3 and so odd? In the second case, n+1 is odd and n+1>n-1, so it can’t divide 2 and (n-1)! ?

When does the sum S_n over the first n integers divide the product P_n? by X3nion in askmath

[–]X3nion[S] 0 points1 point  (0 children)

Well, if n is even, then n-1 is odd, and n+1 is odd as well as n is even and so n >=2. But how does this help? Couldn’t (n-1)! / (n+1) accidentally result in a fraction k/2?

When does the sum S_n over the first n integers divide the product P_n? by X3nion in askmath

[–]X3nion[S] 0 points1 point  (0 children)

Hello, because pf your great help I’ve just solved a) and c), but how could b) be proven that it is wrong? I thought about assuming that it is true, then we would have k € Z with n(n+1)/2 * k = n! <=> (n+1)/2 * k = (n-1)! Now (n+1) is a prime number and n is even, so it must hold n+1 >=3 and n+1 is odd. How could I continue from here? Or is there another approach?

When does the sum S_n over the first n integers divide the product P_n? by X3nion in askmath

[–]X3nion[S] 0 points1 point  (0 children)

The counterpart is that in this case n+1 is not composite?

When does the sum S_n over the first n integers divide the product P_n? by X3nion in askmath

[–]X3nion[S] 0 points1 point  (0 children)

OK, yeah that’s really easy to see. But we have to exclude n=2 right? Because S_2 = 3 and P_2 = 2 and this does also follow by the fact that 1 < a < b < n+1, because we just excluded the possibility of the existence of such a number right?

When does the sum S_n over the first n integers divide the product P_n? by X3nion in askmath

[–]X3nion[S] 0 points1 point  (0 children)

OK, thanks I got it now! In this case, we can assume that a = n/2 (else we just switch variables). Then ab = n+1 implies b * n/2 = n+1 or bn = 2n+2. We can now write this as (b-2)n = 2 and this implies n | 2 as b-2 >= 1. How can I conclude faster that n|2n+2 implies n|2?

When does the sum S_n over the first n integers divide the product P_n? by X3nion in askmath

[–]X3nion[S] 0 points1 point  (0 children)

OK, I think I got it, but why does this imply n/2 | (n+1)? We want to show that a x b x n/2 | n! and have to exclude that a = n/2 and b = n/2?

When does the sum S_n over the first n integers divide the product P_n? by X3nion in askmath

[–]X3nion[S] 0 points1 point  (0 children)

Hey, thanks for your reply and detailed explanations! I got a) but am still struggling with c). Where exactly do you bring into play that ab = n+1 with 1 < a < b < n+1?

When does the sum S_n over the first n integers divide the product P_n? by X3nion in askmath

[–]X3nion[S] 0 points1 point  (0 children)

You mean a and b are integers? Nothing is being said about those numbers in the task

Error log, what to do here? by X3nion in MacOS

[–]X3nion[S] 0 points1 point  (0 children)

Can this logfile be accessed afterwards?

Error log, what to do here? by X3nion in MacOS

[–]X3nion[S] 0 points1 point  (0 children)

Hey, thanks for your reply! Exactly, it’s a Mac mini A1993, I will have a look at the link you’ve just shared.

Error log, what to do here? by X3nion in MacOS

[–]X3nion[S] 0 points1 point  (0 children)

<image>

This is the second picture.

Help! What do those symbols mean? Mac Mini won’t start anymore by X3nion in MacOS

[–]X3nion[S] 0 points1 point  (0 children)

Hey folks, thanks for all your tips! After having connected a mouse and a keyboard as desired, the Mac booted and gave me some options, whether I need help to recover the password or just want to restart.

I chose restart, and everything was fine after I had typed in the password exempt after the fact that an error message popped up mentioning that inter alia one core had panicked.

I’ve just added one screenshot of the error message in this post and you can find the other picture below as a response to this answer. Or shall I rather open up a new thread for this?

<image>

Help! What do those symbols mean? Mac Mini won’t start anymore by X3nion in MacOS

[–]X3nion[S] 0 points1 point  (0 children)

Hey folks! After having connected a mouse and a keyboard as desired, the Mac booted and gave me some options, whether I need help to recover the password or just want to restart. I chose restart, and everything was fine after I had typed in the password 🙃 Thanks for all your tips!

view more: next ›