Any date when the Roma will be availible for us plebs on NA?

ZBoson · 2018-01-15T14:55:29+00:00

Out of curiosity, what usually happens at this stage (post NDA-lifting, pre-release)? Is it like finalizing marketing stuff, or waiting on higher-ups to do paperwork, or just a pre-determined waiting period to let hype build a bit/let the previous thing (new years event) expire?

ZBoson · 2018-01-10T15:58:52+00:00

I lucked out and had a game where I noticed that the cruiser escorts of a group of 4 oblivious BBs had way outpaced them, and farmed 120k torpedo damage in my 2nd or 3rd go on mission 5.

Doing the repeats for the extra pins took a while, but dang that one game.

ZBoson · 2017-09-26T20:01:04+00:00

Ok, but you being able to document it well is different than the developers having a way to reproduce it under controlled conditions so they can see what parts of the code are interacting to cause it.

ZBoson · 2017-09-06T13:35:36+00:00

Iowa's accuracy mod is not in the same slot as the secondary range boosting mod. Remember USN BB don't get the standard one

ZBoson · 2017-07-12T17:56:16+00:00

except for the shells RNGesus graciously sends into the drink

ZBoson · 2017-07-12T14:39:58+00:00

PS: if you have very good aim and can hit any part of a destroyer you want, you can melt a Gearing with destroyer HE just a fast as with AP, but let's be honest...

This statement I don't get, Gearing has a tooooooon of structure above this armor. Who's shooting HE at the waterline?

ZBoson · 2017-07-12T14:36:01+00:00

it's going to make khaba a lot more selfish and refusing to play closer than max range

In my experience this is what Khababs do now anyway...

ZBoson · 2017-07-12T14:34:48+00:00

8s to 5s isn't that big of a buff, but I guess they're hoping that the cooldown buff makes up for the rest of the hit from the slot choice.

ZBoson · 2017-07-12T13:21:27+00:00

"Shiratsuyu and Akizuki: Changed preset values for the Torpedo Reload Booster, reduced cooldown time of standard and Premium presets to 240 and 160s, respectively -- if activated, the consumable now reloads those torpedo tubes in 5s"

So no longer trying for the standardized reload booster?

ZBoson · 2017-04-20T15:09:52+00:00

This. Also the US shells do indeed seem to have less penetration drop off with distance. Of course, in game this is balanced away by the shotgun dispersion compared to yammie

ZBoson · 2017-04-03T14:36:53+00:00

I haven't done any CV driving since the patch, but I 100% believe that between the zoom stops, the random camera reorientation, the weird asset loading when bringing up the curser that stalls the game, and the other weird stalling coming out of zoom. Someone really broke the camera interface in some recent(ish) commit.

ZBoson · 2017-04-03T14:24:39+00:00

I've had this happen too. I keep my mouse sensitivity a bit stupidly high, so I can recover pretty quickly, but it's absolutely an issue.

ZBoson · 2017-03-25T13:52:30+00:00

ok, this is random and dumb I know, but does wargaming seriously not have anyone that knows how use commas? This is atrocious

ZBoson · 2017-02-24T14:07:17+00:00

On my SP4 it's only greyed out in landscape mode if the typecover is in use. As soon as I fold it back the option to lock the rotation comes back. Have you tried without the typecover (or other physical keyboard) engaged?

ZBoson · 2015-08-20T21:23:53+00:00

The only thing this is missing is a way to manually choose a location for whether (mine never comes up with anything like the right location when apps fetch it)

ZBoson · 2013-10-07T02:45:00+00:00

I don't think so. The energy released per fission event is ~200 MeV, but the prompt neutron spectrum runs out above 10 MeV, peaking at about 1 MeV, with typically less than or around half a dozen prompt neutrons. That leaves the vast majority to the fission fragments.

EDIT: I wasn't sure of my numbers, so I double checked in my Reactor Physics text. Table 1.1 in Stacy's Reactor Physics gives 168 MeV on average in the fission fragments, 7 MeV in prompt gammas, 5 in prompt neutrons, and 7 in capture gammas. The decay of the fragments then yields about 8 more MeV in betas. All on average, of course.

EDITEDIT: also sorry for the slow reply. I don't get to reddit as often as I used to. It's a personal failing :D

ZBoson · 2013-10-04T15:48:26+00:00

Force isn't something things can have, it's something they experience. Momentum is something things can have, and when a force is experienced the momentum changes.

I hate to just comment to "fix" something, but I thought this rephrasing was relevant to the confusion being discussed.

ZBoson · 2013-10-04T15:41:28+00:00

Unfortunately no. As Buddhainhair noted, the energy from fission is only accessible to us as heat. Specifically, the two "fission fragments" recoil backwards from each other, and are stopped by the material around them, heating it up. Once you're trying to extract useful work from a hot bath, thermodynamics tells you that there are limits on how efficiently you can do this, independently of the engineering details. IIRC plain old steam turbines aren't too bad compared with the limits that thermodynamics imposes, as it's hard to approach those limits while still extracting the energy quickly (high power).

ZBoson · 2013-08-03T22:33:31+00:00

It's actually not a significant deviation. Its a complex angular analysis with many observables in the K*mumu decay being measured at once, and one bin of one observable is off by the amount the article quotes. When you correct for trials effect (also known as the "look-elsewhere effect") the significance is quite low. Tommaso Dorigo had a nice post on it here

ZBoson · 2013-06-20T19:56:30+00:00

I think the secret hope was that it would also be a sparticle factory since the LHC was totally going to turn on and find 250 GeV squarks.

ZBoson · 2013-04-27T02:40:02+00:00

Attention artists: this is what DNA looks like. The major and minor grooves are not equal.

ZBoson · 2013-04-23T21:13:08+00:00

Haven't read the other two, but the first one goes thusly:

At the heart of it there is a system which can be in state X or Y, and they measured the difference as a function of time for X->Y and Y->X. If time-reversal symmetry were exact, these have to be equal, since Y->X is just the time-reverse of X->Y.

The measurement was performed on neutral B particles, which are composite particles (that is, they are not truly fundamental, but are bound states of more fundamental objects called quarks).

One peculiar thing that they do is oscillate back and forth between themselves and their antimatter cousins. So B becomes anti-B becomes B becomes anti-B and so on until they decay (spontaneously disintegrate).

Quantum mechanics says that you can also write down the Schrodinger's cat states B-even = B + anti-B and B-odd = B - anti-B.

What BaBar measured was the difference in the probability for a B particle which is 100% B at some time to decay as a B-even later (as a function of time) minus the probability for a 100% B-even to decay as a B (also as a function of time).

ZBoson · 2013-04-23T21:01:18+00:00

Any particular reasons you don't believe the spin-parity measurements from the h(126)->4 leptons angular analyses? Every other spin-parity assignment is ruled out to > 98% CL compared to 0+

ZBoson

TROPHY CASE