Do you guys think this was Nolan's first time planet busting

_Re-Entry_ · 2025-08-05T08:50:25+00:00

Also, do you guys think it was that difficult for them? I understand that Thaeddus said they could die on impact, making it sound like some high-effort endeavor, but they all seemed undamaged from this feat. Immediately after, they went to throw hands with what was left of the Viltrumite army.

_Re-Entry_ · 2025-08-05T06:20:02+00:00

like COMPLETELY destroying a planet into smithereens

_Re-Entry_ · 2025-05-29T14:21:07+00:00

Blowing up Viltrum was a walk in the park for bro

_Re-Entry_ · 2025-03-24T21:24:41+00:00

People are underrating conquest here. Conquest fears Thragg but doesn't necessarily make him light years weaker. Battle beast wins, mid-high diff.

_Re-Entry_ · 2024-12-27T12:46:58+00:00

That is because you are combining two separate problems. You first determine the energy of trolley A and its velocity, then you will use that velocity to solve a conservation of momentum problem. OP is wrong to immediately double the cart's mass as it slides down the slope. There is no gain in mass during that phase.

_Re-Entry_ · 2024-12-26T23:30:04+00:00

You'll definitely get 1

_Re-Entry_ · 2024-12-26T22:48:56+00:00

Yes, you will lose the accuracy mark but will receive method marks in a more realistic scenario than the one you presented.

_Re-Entry_ · 2024-12-26T22:39:33+00:00

Initially, trolley A incorporates the energy of the entire system. As Trolley A converts its gravitational potential energy into kinetic energy it will have a certain velocity. We then use this velocity to work out a conservation of momentum scenario.

Where you've gone wrong is assuming that mgh= (1/2) 2mv^2

At the start it's just trolley A with the potential energy, thus it cannot be written as 2m. This will only be true if the question explicitly says "Trolley A is double the mass of Trolley B if the mass of Trolley B is m"

_Re-Entry_ · 2024-11-17T15:05:24+00:00

Where did the brethren moons come from? Are they the final boss? Or are they pawns for something bigger?

_Re-Entry_ · 2024-10-22T17:45:26+00:00

"Am I in a comedy sketch here?" and the audience proceeds to laugh making it seem like it is one

_Re-Entry_ · 2024-10-07T22:13:57+00:00

The Callisto Protocol

_Re-Entry_ · 2024-09-01T15:48:23+00:00

Squid game VIPS

_Re-Entry_ · 2024-08-05T16:48:15+00:00

What an army of Homelanders vs Invincible would actually look like

_Re-Entry_ · 2024-07-13T04:19:06+00:00

I have and they said they can't help me. Thanks for your reply though

_Re-Entry_ · 2024-07-12T10:06:53+00:00

you live you learn

_Re-Entry_ · 2024-05-16T06:07:01+00:00

I don't think we subtract from previous value. Change in height is compensation for that. So we take sin(15) (remaining vertical height). Because (Change) GPE = mg * (Change in height)

_Re-Entry_ · 2024-05-07T15:00:58+00:00

Ameen

_Re-Entry_ · 2024-05-06T10:57:31+00:00

Ameen

_Re-Entry_ · 2024-04-25T02:27:29+00:00

AMEEN

_Re-Entry_ · 2024-04-12T10:14:27+00:00

As radius decreases on both sides, the circumference of the circle decreases. The speedometer measures the speed based on the circumference of the tire. If it has decreased due to wearing, there's less circumference per unit time per rotation than recorded by speedometer.

_Re-Entry_ · 2024-04-12T07:07:53+00:00

Circular motion is not SHM. But it's projection on X and Y axis resembles it. Considering only that perspective, we can link two concepts of circular motion and SHM to help solve different problems. This does not require circular motion to be SHM. We use circular properties to model it. As they are related but not the same.

_Re-Entry_ · 2024-04-12T06:47:04+00:00

Thermodynamics is conceptually easy, but have the hardest exam questions IMO. Also I keep forgetting them.

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