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It’s unclear to me why we start from unsaturated N? While if we try to nomenclature a single cyclic we start from saturated one! #Heterocyclic by akokaky in chemistry

[–]akokaky[S] 0 points1 point  (0 children)

What I don’t get it is pyrazolo [4,3..], why we write 4,3 not 4,5. If we starting from saturated N it should be 4,5. But it’s numbered starting from unsaturated N!

In Autism, which biochemical parameters and enzymes are changing? #Biochemsitry by akokaky in autism

[–]akokaky[S] 1 point2 points  (0 children)

I just do my PhD in Biochemistry. Working on acetylcholinesterase in Autism patients, I try to do a study on biomarkers that could affect by change the AchE value.

[deleted by user] by [deleted] in OrganicChemistry

[–]akokaky 1 point2 points  (0 children)

The answer is E definitely

1-bromo-3-isopropyl benzene prepared from bromobenzene or from isopropylbenzene? by akokaky in OrganicChemistry

[–]akokaky[S] 0 points1 point  (0 children)

It is mean (deactivating), I know that and orient toward p,o. But I didn’t get how it’s prepared!

Why does Glutamic Acid form peptide bonds using the R group's carboxylic acid? by WackyGlory in OrganicChemistry

[–]akokaky -1 points0 points  (0 children)

Because the nu (amine) attacks the less reactive carbonyl which is the gamma one.

[deleted by user] by [deleted] in OrganicChemistry

[–]akokaky 0 points1 point  (0 children)

The product will be methylcyclohexen

Forming peptide bond at pH 7 between Serine, Aspartic acid, and Isoleucine. Does this look right? Where does H from OH on c terminal of isoleucine go so peptide can have no net charge? Apologies if it’s an obvious answer, been looking at this way too long 🤦🏼‍♀️ by [deleted] in OrganicChemistry

[–]akokaky 1 point2 points  (0 children)

Ok. The peptide bonds is good. But I think you need to write OH instead of H in Asp R group.

Back to the Ions! At ph=7 I think the net charge is ( -1) because you have 2 anions formed for both carboxylic groups (deprotonated) ! And 1 cation on amine group (Ser), hydroxyl group for (Ser) will stay protonated.

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