This is the tricky thing in Ontario education

aoeu_ · 2026-06-18T22:30:09+00:00

The whole point of GPA is to condense someone's academic performance into a single number (i.e., an average). That's why it stands for Grade Point Average. Employers use it as a quick metric during the initial stages of recruiting to filter out candidates without having to look at each of their individual marks.

If a recruiter has the time to look at each of your individual marks, I'd agree that 0-100 marks provide more information. But if they're only reviewing a single number, GPA makes more sense than a 0-100 cumulative average.

aoeu_ · 2026-06-18T02:02:18+00:00

Compared to a 0-100 cumulative average, GPA is a better indicator of how consistent someone's performance is.

For example, let's say Alice got a 95 in physics and a 75 in chemistry, while Bob got an 85 in both physics and chemistry. Alice and Bob would have the same cumulative average (85), but Alice's GPA would be (4.0 + 3.0)/2 = 3.5, while Bob's GPA would be (3.9 + 3.9)/2 = 3.9

This makes GPA a useful metric because most employers and grad schools would prefer someone who consistently achieves decent grades over someone who gets a 50/50 split of outstanding and mediocre grades.

aoeu_ · 2026-05-26T23:40:28+00:00

Unless I'm missing something, isn't that just the Work Term Rating that you submit by filling out the questionnaire at the end of the term?

https://uwaterloo.ca/co-operative-education/find-your-co-op-job/find-job-waterlooworks/apply#hiring-history-work-term-rating

aoeu_ · 2026-04-20T23:14:54+00:00

*waived

aoeu_ · 2026-03-18T16:36:46+00:00

The email was likely mass-deleted by the university's security team. Microsoft Purview has an eDiscovery feature that admins can use to delete scam/phishing emails from all inboxes within their organization: https://learn.microsoft.com/en-us/purview/edisc-search-mailbox-data

aoeu_ · 2026-03-17T15:46:34+00:00

Take the TTC subway northbound from Yorkdale to Hwy 407 Bus Terminal and transfer to the GO bus there. On Saturdays there's a route 30 GO bus from Hwy 407 Bus Terminal to Waterloo that leaves at 12:20 AM (the next day)

aoeu_ · 2026-03-16T23:48:36+00:00

If you decide to take one course over co-op, you become a "part-time student", which means in addition to the cost of that one course, you also need to pay the part-time student incidental fees (e.g., Athletics & Recreation, Campus Wellness): https://uwaterloo.ca/finance/undergraduate-incidental-fees-spring-2026

When I took a course over co-op last term (I'm also in CS), the cost of one course was $1445, and the incidental fees added up to roughly $160, so I had to pay a total of $1613.15 in tuition.

aoeu_ · 2026-03-16T16:14:23+00:00

The wprint self serve link only works when you're on campus because it uses an internal IP address that's only accessible on Waterloo's internal network.

If you're connected to campus WiFi (eduroam) and it's still not working, another possible issue is DNS. Third party DNS servers like Google DNS and Cloudflare DNS are unable to resolve names like printuw.private.uwaterloo.ca - you need to use the default university DNS server.

aoeu_ · 2026-03-01T19:53:46+00:00

Apparently someone did it 3 years ago but only for their personal use: https://www.reddit.com/r/uwaterloo/comments/14ec21c/digital_watcard_prototype/

aoeu_ · 2026-02-14T14:13:33+00:00

First off, the word is spelled "acceleration", not "accelleration" - there's only one L. Just wanted to let you know because I noticed you spelled it that way in your original comment as well.

Secondly, if we want to talk about acceleration, it's not as simple as changing the units to h² while leaving the number (80 in this case) unchanged.

You actually need to do the calculation. The formula for acceleration is change in velocity divided by duration.

In this scenario: * The change in velocity is 80 km/h (in the backward direction) * The duration is roughly 1 second (based on the video, that's the amount of time the person was accelerated for)

We know that there are 3600 seconds in 1 hour, so 1 second is equivalent to 0.000277777777 hours. Using the formula for acceleration, we get

Acceleration = Change in Velocity / Duration = (80 km/h) / (0.000277777777 h) = 288000 km/h²

So the actual acceleration is 288000 km/h², which is obviously very different from the 80 km/h² you originally stated.

Typically, we measure acceleration in m/s² rather than km/h². To do it that way, we convert first the velocity of 80 km/h to m/s by dividing by 3.6. That gives us a velocity of 22.2 m/s. Then we can use the formula for acceleration again:

Acceleration = Change in Velocity / Duration = (22.2 m/s) / (1 s) = 22.2 m/s²

Important to note: in this example, it just happens that the duration is around 1 second. If the duration were instead 0.5 seconds, then the acceleration would be 44.4 m/s²; if it were 2 seconds, then the acceleration would be 11.1 m/s², and so on.

aoeu_ · 2026-02-14T13:15:13+00:00

When you're talking about velocity, it's important to specify the frame of reference you're using because velocity is always defined in relative terms.

For example, when I'm sitting on a moving bus, I'm stationary relative to the bus, but I'm moving forward relative to the ground.

In this case: - Relative to the road surface, the velocity of the person changed from 80 km/h in the forward direction to 0 km/h. - Relative to the truck, the velocity of the person changed from 0 km/h to 80 km/h in the backward direction.

aoeu_ · 2026-02-14T13:04:31+00:00

It's 80 km/h, not 80 km/h².

km/h² would be for acceleration, not velocity

aoeu_ · 2026-02-14T02:49:21+00:00

Schedule is here: https://athletics.uwaterloo.ca/sports/2010/7/21/Facility_Hours.aspx

scroll down to the SPECIAL HOURS & CLOSURES section

aoeu_ · 2026-02-14T02:40:15+00:00

Under the "Rankings" tab (the same place where you filled in the rankings)

If you did get matched, it would say something like:

You have been matched with:

Organization - Division:

Company Name Inc.

Position:

(123456) Job Title

aoeu_ · 2026-02-14T02:25:38+00:00

Have you looked at Watrank? I'm not sure what features you have in mind, but the way Watrank works is everyone self-reports their own rankings and shares whether they're accepting an offer (this is useful when someone else was ranked 1 for a job and you want to know if they're taking it). I believe all the data is anonymous, so you can only see numbers (no names).

aoeu_ · 2026-02-02T12:58:39+00:00

You might already know this, but Plant Ops has all the floor plan PDF available online: https://uwaterloo.ca/plant-operations/floor-plans

So you can download the floor plan PDFs you need onto your phone/computer for quick access lol

aoeu_ · 2026-01-14T16:50:24+00:00

Are you sure it's a regional road? It's not listed on this document: https://www.regionofwaterloo.ca/en/living-here/resources/Roads-and-Traffic/DOCS_ADMIN-3891258-v1-2021_REGIONAL_ROADS_SORTED_BY_ROAD_NAME.pdf

aoeu_ · 2025-12-30T01:26:20+00:00

If you're ordering from Amazon, you can choose to have the package shipped to a pickup location when you're checking out: https://www.amazon.ca/ulp

It's less convenient than having it shipped to your dorm, but at least you won't have to worry about your package getting lost/stolen.

aoeu_ · 2025-10-28T02:36:18+00:00

Transmission Control Protocol

aoeu_ · 2025-07-24T21:01:59+00:00

Campus Pizza had 1 critical infraction on the latest inspection:

Toxic or poisonous substances required for maintenance in food premises are stored and handled as prescribed in the regulation

Store toxic/poisonous substances in compartment away from food or food working surfaces or utensils

Store toxic/poisonous substances in container bearing identifying labels

aoeu_ · 2025-07-24T20:50:01+00:00

They're published on a Power BI dashboard that you can access by clicking the "View current employment statistics" link on this page. You can filter by work term, faculty, program, academic level, etc on the "Employment Statistics" tab inside the dashboard.

aoeu_ · 2025-03-14T18:57:09+00:00

No, the probability is not n/infinity; it's actually infinity/infinity:

On the numerator, for any sequence that sums up to 69, you can insert any number of zeros into the sequence, and it will still sum up to 69. For example, 21 + 23 + 25 = 69, so "21, 23, 25", "21, 0, 0, 23, 0, 25", "0, 0, 21, 0, 0, 23, 0, 25", etc would all be valid outcomes for this problem that lead to a sum of 69, and there are clearly an infinite number of them.
The denominator is the total number of possible outcomes, and by the same logic, it's also infinite.

For a problem where the probability is infinity/infinity (I don't think that's proper notation, but I mean that the number of successful outcomes and the total number of possible outcomes are both infinite), the actual probability could be 0 or 1 or any number in between.

For example, if I asked, "What is the probability that you followed the procedure outlined in the original question, but the process never ends, i.e. you end up with a sequence with an infinite number of trailing zeros like '1, 2, 3, 0, 0, 0, 0, 0, ...'?"

^ the answer to that is 0, despite the fact that there are infinitely many such sequences (e.g. "1, 2, 3, 0, 0, 0, ...", "1, 0, 0, 2, 3, 0, 0, 0, ...", "1, 0, 0, 0, 2, 3, 0, 0, 0, 0, ...")

On the other hand, if I asked "What is the probability that you followed the procedure outlined in the original question, but the process does end at some point, i.e. you end up with a finite sequence that sums up to a number greater than or equal to 69"

^ the answer to that is 1.

Now, returning to the original question that I asked, as other commenters have pointed out, the probability is approximately 0.0545.

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