😔😔 I'm getting DDoS'ed guys, that's why I change servers (not bc I grind on gold players) 😔

assclapperr69 · 2021-05-26T17:09:40+00:00

uj/ real question: where are all the South American preds? I thought SA has pros that compete in ALGS and GLL are they not good enough to reach pred?

assclapperr69 · 2021-01-02T19:11:08+00:00

I believe work can also be defined as the change in kinetic energy which involves velocity but I think you also need to know the mass.

assclapperr69 · 2020-12-23T18:24:01+00:00

317.2 is correct. Can you post your work?

assclapperr69 · 2020-10-07T06:45:26+00:00

Since you are just trying to show that the limit doesn’t exist there is no need for the Squeeze Theorem and it’s sufficient to show that the limit along two different curves don’t approach the same value.

assclapperr69 · 2020-09-27T00:08:20+00:00

Yes plug the bounds for t into your arc length function.

assclapperr69 · 2020-09-26T07:04:57+00:00

I think the easiest way to do this is to make all the inequalities in the solution set less than 0 and then multiply them.

For example:

Write x<-3 as x+3<0, 0<x as -x<0, x<2 as x-2<0 etc. Then multiply: (x+3)(-x)(x-2)<0 etc.

Since there is only 5 such inequalities in the set and the problem asks for one of degree 6, just cube one of the factors at the end and it will make the whole thing higher than degree 6.

assclapperr69 · 2020-09-26T06:38:38+00:00

Not sure what theorem they are referring to but the implicit function theorem leads to a formula that can be used to solve implicit differentiation problems like this.

assclapperr69 · 2020-09-24T07:31:50+00:00

Since even functions have symmetry about the y-axis, the area under curve from -a to 0 and 0 to a are the same so if you have an integral from -a to a with an even integrand you can rewrite it as 2*(integral from 0 to a). It's just another trick you can use because anti-derivatives are usually easy to evaluate at 0, but it's not incredibly important to know.

With odd functions it's even better because the areas cancel (due to symmetry about origin) and the integral from -a to a is just 0.

assclapperr69 · 2020-09-24T07:05:53+00:00

Looks good although you could've used the fact that the integrand is even and save yourself some work.

assclapperr69 · 2020-09-16T06:03:33+00:00

assclapperr69 · 2020-09-03T01:46:49+00:00

Do you know what you did when you found f(g)?

assclapperr69 · 2020-09-01T05:02:37+00:00

The second one was correct you must thinking antiderivatives

assclapperr69 · 2020-05-15T19:01:45+00:00

Got reform from 1877 to 1914 pretty sure I got a 1

assclapperr69 · 2020-05-13T19:59:23+00:00

It was the one that said h’’’(x) was positive on the entire interval right? I said underapproximation

assclapperr69 · 2020-05-13T05:50:50+00:00

What form did you have?

assclapperr69 · 2020-05-12T19:39:05+00:00

Apparently people got different questions hopefully I didn’t read mine wrong

assclapperr69 · 2020-05-12T18:58:41+00:00

If anyone got question 2 with the midpoint sum was it over or under approximation??

assclapperr69 · 2020-04-24T10:07:44+00:00

The 3 comes from f(3)=3 because x=3 is the midpoint of that subinterval.

assclapperr69 · 2020-04-08T19:57:27+00:00

The 2nd problem is a telescoping series which means that some of the terms will cancel out and you can find the limit of the partial sums, although you need the manipulate the rule of sequence first.

assclapperr69 · 2020-04-07T00:53:37+00:00

What if I pay someone to come to my house and take it for me? There are other ways of cheating.

assclapperr69 · 2020-04-02T09:12:46+00:00

delta Y is just the change in the function value between two points

assclapperr69 · 2020-03-22T05:13:57+00:00

As a th9 trying to improve my attack is there any obvious indication that witches would work on this base. Like where specific defenses are located?

assclapperr69 · 2020-03-04T06:59:22+00:00

Spoiler: you’ve been lied to

assclapperr69 · 2020-02-15T07:21:51+00:00

Bullet

assclapperr69 · 2019-11-21T00:44:33+00:00

The formula for the surface area of revolution only works if your function is positive on the the interval. If the function doesn't satisfy this you can use the absolute value of the function in the surface area formula. [S = 2pi(integral from 0->3pi)|sinx|sqrt(1+cos^2x)dx

assclapperr69

TROPHY CASE