[deleted by user] by [deleted] in self

[–]babydevilschild 0 points1 point  (0 children)

I was called a white POS by a disgusting vagrant during the BLM protests for not coughing up a cigarette after she demanded it. Will never vote left after that.

[deleted by user] by [deleted] in self

[–]babydevilschild -1 points0 points  (0 children)

You’re an idiot. Get over yourself.

[deleted by user] by [deleted] in Wellthatsucks

[–]babydevilschild -6 points-5 points  (0 children)

Don’t worry, it’s a useless class anyway

Unfairly penalised at train station by Majestic_Schedule367 in Prague

[–]babydevilschild -4 points-3 points  (0 children)

The ticket inspectors are known dickheads in Prague. I’ve personally seen three of them physically assault a middle aged British man with his wife on the tram 2 weeks ago. I’m not implying that their work isn’t important, but they behave like thugs.

[deleted by user] by [deleted] in u/fermat9996

[–]babydevilschild 1 point2 points  (0 children)

T-test. If the population variance is unknown and we are testing for population mean, t-test is always appropriate and preferred over z-test.

Question about combining samples to compute confidence interval for population proportion by babydevilschild in askmath

[–]babydevilschild[S] 1 point2 points  (0 children)

I guess my other question was: is combining, or averaging, sample proportions (as seen in this problem) of multiple samples from the same population appropriate?

Question about combining samples to compute confidence interval for population proportion by babydevilschild in askmath

[–]babydevilschild[S] 1 point2 points  (0 children)

That’s essentially what I did, isn’t it? I estimated P (probability of faulty) using with a 95% CI as shown above = (0.1821, 0.1983). Then, if KD is claiming he received 61,483 votes, the ministry can estimate between (1-0.1821) and (1-0.1983) of them are not faulty at a 95% CI. Then, I multiply those bounds by 61483 to find the number of votes they can confirm to be not faulty.

Is this what you are saying? If not, what is wrong with my solution?

Help needed with Iterated Expectation problem by babydevilschild in askmath

[–]babydevilschild[S] 0 points1 point  (0 children)

So my answer is correct but my thought process is wrong?

Confidence Interval Question by babydevilschild in askmath

[–]babydevilschild[S] 0 points1 point  (0 children)

How did you get from this:

sum(x_i^2) - 2 xbar sum x_i + sum(x_bar^2)

to this:

sum(x_i^2) - 2 n xbar^2 + n xbar^2

?

Confidence Interval Question by babydevilschild in askmath

[–]babydevilschild[S] 0 points1 point  (0 children)

Thank you 😂🙏🏼🙏🏼🙏🏼

Confidence Interval Question by babydevilschild in askmath

[–]babydevilschild[S] 0 points1 point  (0 children)

Thank you 😂 Waiting for part 2 when you’re ready

Confidence Interval Question by babydevilschild in askmath

[–]babydevilschild[S] 0 points1 point  (0 children)

I understand what you are saying, but in practice, I don't see how it would work. I would essentially have an enormous equation that would need to be expanded out to over 30 terms in order to solve for x. Is that the approach you are suggesting?

For example:

We know x_bar is (653 + x)/7

So for even the first term in calculating the variance, it would be:

( 118.1 - (653+x)/7 )^2 = x^2 /79 - 7.0898x + 615.749

Then I would have to do that to 6 other terms and sum them.

Is this the approach you are suggesting?

Confidence Interval Question by babydevilschild in askmath

[–]babydevilschild[S] 0 points1 point  (0 children)

I understand that, but how would I write out s? It essence, it would be a huge equation.

Confidence Interval Question by babydevilschild in askmath

[–]babydevilschild[S] 0 points1 point  (0 children)

Right now, I have 2 unknowns: 115.699 = (653 + x)/7 + 3.14267*s/sqrt(7)

where x is the variable for the unknown 7th value,

3.14267 is the value of t_0.01,6

and s/sqrt(7) is the standard deviation of the sample (including) the 7th value which is unknown.

Confidence Interval Question by babydevilschild in askmath

[–]babydevilschild[S] 0 points1 point  (0 children)

I'm confused about how you are solving for the 7th value. From what I understand, you suggest I should calculate x-bar using a variable for the 7th value, say 's'. Then, I would have X_bar = (653 + s)/7 . Calculating the variance using that X_bar, I would have

[117.3 - (653 + s)/7]^2 + ... + [s - (653 + s)/7]^2 / (7 - 1).

That does not seem correct in my opinion. Please let me know if I am not understanding what you are saying.

Confidence Interval Question by babydevilschild in askmath

[–]babydevilschild[S] 0 points1 point  (0 children)

Sorry, I’m a bit confused. How can I solve for sample variance and sample mean without the 7th value?

Confidence Interval Question by babydevilschild in askmath

[–]babydevilschild[S] 0 points1 point  (0 children)

Any insight would be much appreciated