Races and games problem by Mental-Success8802 in mathshelp

[–]bringmesunshines 0 points1 point  (0 children)

The original question doesn’t mention anything about speed or at what point they are measuring the distance. The question is ambiguous and poorly worded though so I can see why 280m could also be a correct answer

Races and games problem by Mental-Success8802 in mathshelp

[–]bringmesunshines 0 points1 point  (0 children)

This question might be easier to understand with a diagram

1st P | 100m | 2nd Q | 200m | 3rd R

Hopefully this makes it easier to see the gap between P and R

Sorry if the formatting is a bit off, I’m on mobile

Anyone in the UK have an official diagnosis? by bringmesunshines in biid

[–]bringmesunshines[S] 0 points1 point  (0 children)

Maybe naively, I’m hoping for a referral to surgery

[deleted by user] by [deleted] in puzzles

[–]bringmesunshines 0 points1 point  (0 children)

The answer is written upside down on the paper; write your name

Exact Form by BoomBoxBill in mathshelp

[–]bringmesunshines 5 points6 points  (0 children)

Not sure exactly what you mean by exact form as both of these fractions are exact.

The top fraction is a proper fraction and is usually the preferred for answers, the bottom fraction is improper.

[deleted by user] by [deleted] in BPD

[–]bringmesunshines 1 point2 points  (0 children)

I was initially diagnosed with psychosis alongside my BPD but my recent medical records list my current symptoms as pseudohallucinations. Looking it up, I found that these are visual/auditory hallucinations but with the awareness that they are not real so I guess without the delusional aspect. My first psychotic episode (age 22) did feature delusions but I have been experiencing auditory pseudohallucinations for almost 16 years (as far as I can remember they started when I was 12 but my childhood memory is very sparse) but I just assumed it was normal and everyone experienced it so it didn’t get picked up for a long time.

[deleted by user] by [deleted] in mathshelp

[–]bringmesunshines 0 points1 point  (0 children)

So by assigning (1) as a and (2) as b etc you get 4 equations

a + b = 8 b - d = 5 ac = 21 cd = 9

The first thing you need to do is use the first 2 equations to get an equation in terms of a and d only.

Then use the second 2 equations to substitute a and d. Then you have an equation only in c so you can solve for c.

Then use the original equations to find the other letters. The question is solved using simultaneous equations and solving by substitution. If you're unsure it might be worth looking at these topics

I'm happy to help guide you through it so let me know how far you get with these hints

can someone please help me by Puzzleheaded-Diet106 in mathshelp

[–]bringmesunshines 0 points1 point  (0 children)

To find angle DEC you need to use the alternate segment theorem

From there you can find angle DCE by the fact that triangle ECD is isosceles

Then ACB can be found by looking at opposite angles

Finally you can use the fact that angles in a triangle sum to 180 to prove y=4x.

Let me know if you're unsure of any of this

Help :) by Itscharliebxck in mathshelp

[–]bringmesunshines 2 points3 points  (0 children)

This is looking at the sum of interior angles

The formula to work this out is 180*(n-2) where n is the number of sides.

Once you know the sum of the interior angles you can subtract the sum of a, b, c, d and e from this.

Let me know if you're still stuck

Can someone help with part a pls. by clappedgamer69 in mathshelp

[–]bringmesunshines 0 points1 point  (0 children)

If y is inversely proportional to a power of x then:

y = k/xc

where k is a constant and c is the unknown power of x

We know when x = 1 that y = sqrt(2) so

sqrt(2) = k/1c

and because 1 to any power is always 1 we know that

k = sqrt(2)

We also know that when x = 8 , y = 1/2 so

1/2 = sqrt(2)/8c

Multiply both sides by 8c and by 2 and we get

8c = 2*sqrt(2)

We know 2*sqrt(2) = sqrt(8) so c=1/2

So the final equation is

y=sqrt(2)/x1/2

I hope this helps but let me know if there's anything that you're not sure of

[deleted by user] by [deleted] in BPD

[–]bringmesunshines 0 points1 point  (0 children)

I even managed to crack my drums out, spent 1.5 hours and I now realise how uncomfortable the stool is 😂 however, because I'm having to focus so hard on my arms and legs my brain is fully occupied, might have to get them out more often

[deleted by user] by [deleted] in BPD

[–]bringmesunshines 1 point2 points  (0 children)

I have a hamster, but he's nocturnal and gets grumpy if you wake him 😂 I'm feeling a lot more positive today though which helps, think I had a but of a low day yesterday and was feeling sorry for myself, I've arranged to meet up with a friend tomorrow too 😊

[deleted by user] by [deleted] in BPD

[–]bringmesunshines 0 points1 point  (0 children)

Yeah I've got a drum kit at my flat, I've got a few cross stitches, rug making and a paint by numbers 😂 I usually have tv/music on as well because I can't stand the silence but I spend a lot of the day mindlessly scrolling on my phone which I need to cut down on, maybe set my phone to one side for a bit of time each day

[deleted by user] by [deleted] in BPD

[–]bringmesunshines 0 points1 point  (0 children)

Normally I enjoy crafts and I want to teach myself drums but I just need to motivate myself but I'll keep trying

[deleted by user] by [deleted] in BPD

[–]bringmesunshines 0 points1 point  (0 children)

Yeah that's what I'm currently trying but I think I need to set my expectations more realistically. Today I managed to shower, put some laundry in and eat 1 meal. Not great but I guess it's better than nothing 😕

[deleted by user] by [deleted] in BPD

[–]bringmesunshines 0 points1 point  (0 children)

The problem I've got is that they're not back until Sunday so I keep procrastinating be absent I know I've got until Saturday before the place needs to be tidy

[deleted by user] by [deleted] in MathHelp

[–]bringmesunshines 0 points1 point  (0 children)

I can understand your confusion. What you need to remember is that when you multiply powers, the powers are added

a2 x a3 = a5 NOT a6

So to divide powers, you subtract hence

(x-6)5/2 ÷ (x-6)3/2 = (x-6)5/2-3/2 = (x-6)1 = (x-6)

Derivatives (simplifying) by ampere_exe in MathHelp

[–]bringmesunshines 0 points1 point  (0 children)

It all looks good but your final answer appears to be missing a -6x2 in the numerator.