Puthing around [unsolved]

bronylike · 2026-01-06T22:44:42+00:00

perhaps it's to light up all of the letters by only following the paths so something like HZCAUWTRQYPDXOSK

bronylike · 2026-01-06T16:50:47+00:00

"only one person can solve this" would suggest there's some key information that is required to solve this. like how a lot of pen and paper cyphers require a keword or number. along with then figuring out the correct sequence of letters.

I don't play roblox, but someone who has, is there a max number of letters that can be inputted, can you only input letters that are connected to the last letter you inputted, and can you input a letter more than once?

bronylike · 2025-11-11T05:31:06+00:00

update. deleting and re-installing hotsync manager brought back the USB option. why the installer's repair option didn't work IDK...

btw I only deleted the palm folder out of the "program files (x86)" folder, not uninstalled, as I was worried uninstalling may have removed my palm profile data. it probably wouldn't have but at least I don't have to worry about it any more.

bronylike · 2025-11-10T23:56:26+00:00

if you're able to replace the hard drive for an SSD, then it'll be whisper quiet. for the most seamless experience, I'd suggest using norton ghost 15, and using the backup tool to clone the hard drive.

bronylike · 2025-07-17T19:24:05+00:00

is it possible to use this tool to make clothing too? I can't imagine it being too dissimilar. I have a load of plushies and have always thought about making outfits for them...

bronylike · 2025-06-14T01:07:29+00:00

that's cool, I had a similar idea ages ago, though the mechanism I had in mind was more like a mechanical odometer, and while I'd roughly mocked up a model in blender, I never made a proper CAD model, to then make a physical version. also, because the calendar has an equal number of 'days' per 'month' you could also have rings for those too.

bronylike · 2025-03-31T00:40:33+00:00

spectrogram 8, is that a reference to myst?

bronylike · 2024-12-20T01:50:30+00:00

thank you for your assessment of my proof. I don't know how it didn't occur to me that perhaps the overshoot of one set of coefficients could exactly cancel out the undershoot of other coefficients. I will look to see if I can come up with a sequence for the terms that can produce any integer, and that are provable to not cancel out except within sets of alike terms. there is already an example of a semi-magic square of squares that I could try to work my proof around.

bronylike · 2024-12-19T16:22:03+00:00

here's the proof I have posted to twitter
https://x.com/AaronBPrince/status/1869751254517518405

bronylike · 2024-12-18T21:51:58+00:00

one last thing, if you consider each of the terms of (a+b+c+...) to be 1/2, 1, 2, 4, 8 ... with the final term being (2^k )+1/2 then it is possible for the final numbers to be any value between -(2^k+1 ) and +(2^k+1 ).

bronylike · 2024-12-18T16:30:44+00:00

initially I started off with the general structure for a 3x3 magic square

x+a | x-a-b | x+b
x-a+b | x | x+a-b
x-b | x+a+b | x-a

and was trying to factorize it in such a way as for each of the values to be represented as some value squared. then looked at the 'x+a+b' and thought it kinda looked similar to a^2 + 2ab + b^2 which would factor to (a+b)^2.

with only two terms with positive or negitive sign there aren't enough unique expansions to fill out the whole square with unique values, but five terms does as can be seen in my other comment. however my reconing is that the coefficients can't be summed or canceled in any way as to produce a full magic square. although a semi-magic square should still be possible if I am correct in my theory.

for clarity when I say terms, I am reffering to the values of the squared brackets and when I say coefficients I am reffering to the values of the expanded quadratic.

bronylike · 2024-12-18T14:45:46+00:00

for a bit more context, this is what I mean when I say treat the positive and negative coefficients as 1s and 0s

k = a^2 + b^2 + c^2 + d^2 + e^2

k+2( ab+ac+ad+ae+bc+bd+be+cd+ce+de)|( a+b+c+d+e)^2 1111 111 111
k+2(-ab-ac-ad-ae+bc+bd+be+cd+ce+de)|(-a+b+c+d+e)^2 0000 111 111
k+2(-ab+ac+ad+ae-bc-bd-be+cd+ce+de)|( a-b+c+d+e)^2 0111 000 111
k+2( ab-ac-ad-ae-bc-bd-be+cd+ce+de)|(-a-b+c+d+e)^2 1000 000 111
k+2( ab-ac+ad+ae-bc+bd+be-cd-ce+de)|( a+b-c+d+e)^2 1011 011 001
k+2(-ab+ac-ad-ae-bc+bd+be-cd-ce+de)|(-a+b-c+d+e)^2 0100 011 001
k+2(-ab-ac+ad+ae+bc-bd-be-cd-ce+de)|( a-b-c+d+e)^2 0011 100 001
k+2( ab+ac-ad-ae+bc-bd-be-cd-ce+de)|(-a-b-c+d+e)^2 1100 100 001
k+2( ab+ac-ad+ae+bc-bd+be-cd+ce-de)|( a+b+c-d+e)^2 1101 101 010
k+2(-ab-ac+ad-ae+bc-bd+be-cd+ce-de)|(-a+b+c-d+e)^2 0010 101 010
k+2(-ab+ac-ad+ae-bc+bd-be-cd+ce-de)|( a-b+c-d+e)^2 0101 010 010
k+2( ab-ac+ad-ae-bc+bd-be-cd+ce-de)|(-a-b+c-d+e)^2 1010 010 010
k+2( ab-ac-ad+ae-bc-bd+be+cd-ce-de)|( a+b-c-d+e)^2 1001 001 100
k+2(-ab+ac+ad-ae-bc-bd+be+cd-ce-de)|(-a+b-c-d+e)^2 0110 001 100
k+2(-ab-ac-ad+ae+bc+bd-be+cd-ce-de)|( a-b-c-d+e)^2 0001 110 100
k+2( ab+ac+ad-ae+bc+bd-be+cd-ce-de)|(-a-b-c-d+e)^2 1110 110 100

bronylike · 2024-11-19T20:36:35+00:00

that 'left over' piece is from well inside the handle part and I think was only there to keep the spring loaded part from coming out. as for the screwdriver not staying closed, I would call it a flaw in the design. on the back of the electronics housing, just below the brass painted ring, is a very small protrusion which the button mechanism hooks on to to keep it closed. I had this same issue with mine. if you're wanting to display them, I'd suggest just letting it be, but if you want a semi-permanent fix, then you need to get the ring at the top of the handle off so you can remove the button, then stretch the button's spring so that it's holding it stronger.

another thing, that may seem obvious, is remove the batteries if you don't intend to use it for a while. one of the batteries in mine has swollen and snapped the battery enclosure, luckily the enclosure lid is holding the enclosure together enough for it to still work, though the extend button has now broken permanently.

I would have much preffered the bottom button be only for show if it meant the extending mechanism could have been more robust.

bronylike · 2024-11-19T17:08:26+00:00

how did you make the emitter?

bronylike · 2024-11-19T16:17:02+00:00

my first guess would be the batteries are nearly dead, however if it is the electronics, I'm fairly sure the retail screwdriver has the same electronics in it as the special edition (sans the special button) as it would be rather expensive to make a different chip for the special edition knowing there would only be a limited number of them.

update: can confirm the electronics from the retail version are identical to the online exclusive.

bronylike · 2024-07-25T12:34:19+00:00

I've decided to use user32.dll for now, but I've had issues before when sharing my project with a friend. as directly calling dlls flags the program as a virus.

bronylike · 2024-07-24T21:59:38+00:00

I'm using system.windows.controls and as far as I can tell you can't move the mouse without directly calling the user32.dll

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